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💏Intro to Chemistry Unit 17 Review

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17.7 Electrolysis

17.7 Electrolysis

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
💏Intro to Chemistry
Unit & Topic Study Guides

Electrolysis is the process of using electrical energy to force a non-spontaneous chemical reaction to occur. It's how industries extract reactive metals, purify copper, plate jewelry with gold, and produce chemicals like chlorine gas. As a core topic in electrochemistry, electrolysis shows the flip side of galvanic cells: instead of getting electricity from a reaction, you're putting electricity into one.

Electrolysis

Electrochemistry Fundamentals

Electrochemistry studies chemical processes that involve electron transfer. The foundation here is redox reactions, where one species loses electrons (oxidation) and another gains them (reduction). These two processes are described separately as half-reactions, one for each electrode.

For any of this to work, you need an electrolyte: a substance that conducts electricity because it contains freely moving ions. This happens either when an ionic compound is dissolved in water or when it's melted (molten). The conductivity of the solution depends on how many ions are present and how easily they move.

Steps and components of electrolysis, Electrolytes | Introduction to Biology

Steps and Components of Electrolysis

An electrolytic cell uses an external power source (like a battery) to drive a reaction that wouldn't happen on its own. Here's what's inside and how it works:

Components:

  • An electrolyte (an ionic compound, either dissolved in water or molten)
  • Two electrodes submerged in the electrolyte
    • Cathode (negative electrode): where reduction occurs. Cations migrate here and gain electrons.
    • Anode (positive electrode): where oxidation occurs. Anions migrate here and lose electrons.
  • An external power source supplying electrical energy

The process, step by step:

  1. The electrolyte dissociates into cations (+) and anions (−).
  2. The external power source pushes electrons into the cathode and pulls them from the anode.
  3. Cations in solution migrate toward the cathode, where they pick up electrons (reduction).
  4. Anions migrate toward the anode, where they give up electrons (oxidation).
  5. The net result is a non-spontaneous chemical change driven by electrical energy.

Common applications:

  • Electroplating: depositing a thin layer of metal (like chromium or silver) onto an object's surface
  • Electrolytic refining: purifying metals like copper by dissolving impure metal at the anode and depositing pure metal at the cathode
  • Production of elements: extracting highly reactive metals like sodium or aluminum from their molten compounds, since these metals can't be obtained by ordinary chemical reduction
Steps and components of electrolysis, Electrolysis | Boundless Chemistry

Electrolytic vs. Galvanic Cells

These two cell types are essentially mirrors of each other. Both involve redox reactions and electrodes, but the direction of energy flow is reversed.

FeatureElectrolytic CellGalvanic (Voltaic) Cell
Reaction typeNon-spontaneousSpontaneous
Energy conversionElectrical → ChemicalChemical → Electrical
Power sourceRequires external sourceGenerates its own voltage
Cathode chargeNegativePositive
Anode chargePositiveNegative
Reduction siteCathodeCathode
Oxidation siteAnodeAnode
ApplicationsElectroplating, refining, element productionBatteries, fuel cells

One thing that trips students up: reduction always happens at the cathode and oxidation always happens at the anode in both cell types. What changes is the sign (+ or −) of each electrode. In a galvanic cell the cathode is positive; in an electrolytic cell it's negative.

Faraday's Laws in Electrolysis Calculations

Faraday's laws connect the amount of electric charge you pass through a cell to the amount of substance produced or consumed. This is how you solve quantitative electrolysis problems.

First Law: The mass of substance deposited or dissolved at an electrode is directly proportional to the total charge passed through the cell.

m=kQm = kQ

where mm is mass, kk is a proportionality constant, and QQ is total charge in coulombs.

Second Law: When the same amount of charge passes through different electrolytic cells, the masses of substances produced are proportional to their equivalent weights (molar mass divided by the number of electrons transferred per ion).

The practical formula that combines both laws:

m=QMnFm = \frac{QM}{nF}

  • mm = mass of substance produced (grams)
  • QQ = total charge passed (coulombs). Calculate this as Q=I×tQ = I \times t, where II is current in amps and tt is time in seconds.
  • MM = molar mass of the substance (g/mol)
  • nn = number of electrons transferred per formula unit (from the balanced half-reaction)
  • FF = Faraday's constant = 96,485 C/mol of electrons

How to solve an electrolysis problem:

  1. Write the balanced half-reaction at the electrode you care about.
  2. Identify nn (electrons transferred) and MM (molar mass of the product).
  3. Calculate total charge: Q=I×tQ = I \times t.
  4. Plug into m=QMnFm = \frac{QM}{nF} to find mass.
  5. If the product is a gas, convert moles to volume using the ideal gas law: PV=nRTPV = nRT.

Example: How many grams of copper are deposited when a 3.00 A current runs through a CuSO4CuSO_4 solution for 2.00 hours?

  • Half-reaction: Cu2++2eCuCu^{2+} + 2e^- \rightarrow Cu, so n=2n = 2, M=63.55M = 63.55 g/mol
  • Q=3.00 A×7200 s=21,600 CQ = 3.00 \text{ A} \times 7200 \text{ s} = 21{,}600 \text{ C}
  • m=21,600×63.552×96,485=1,372,680192,9707.11 g Cum = \frac{21{,}600 \times 63.55}{2 \times 96{,}485} = \frac{1{,}372{,}680}{192{,}970} \approx 7.11 \text{ g Cu}