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AP Calculus AB/BC
Unit 3 – Composite, Implicit, and Inverse Functions
Topic 3.4
If $q(x) = 3 \cdot \cos^{-1}(e^{-2x})$, then $q'(x)$ is:
$\frac{6e^{-2x}}{\sqrt{1-(e^{-2x})^2}}$
$\frac{6e^{2x}}{\sqrt{1-(e^{-2x})^2}}$
$\frac{6e^{-2x}}{\sqrt{1+(e^{-2x})^2}}$
$\frac{6e^{-2x}}{\sqrt{1-(e^{2x})^2}}$
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AP Calculus AB/BC - 3.4 Differentiating Inverse Trigonometric Functions
Key terms
q'(x)
q(x)
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