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📏Honors Pre-Calculus

Limits Rules

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Why This Matters

Limits are the gateway to calculus—they're the foundational concept that makes derivatives, integrals, and continuity possible. In Honors Pre-Calc, you're being tested on your ability to evaluate limits using specific rules, recognize when those rules apply, and understand why functions behave the way they do as they approach certain values. This isn't just about plugging numbers into formulas; it's about developing the analytical thinking that will carry you through AP Calculus.

The rules you'll learn here fall into distinct categories: basic building blocks, algebraic operations, special techniques, and asymptotic behavior. Each rule exists because of how functions fundamentally behave near specific points or at extreme values. Don't just memorize the formulas—know which rule to reach for in different situations and understand what each one tells you about the function's behavior. That's what separates students who struggle with limits from those who master them.


Basic Building Blocks

These foundational rules establish how the simplest functions behave as xx approaches a value. Every complex limit evaluation builds on these two principles.

Limit of a Constant

  • The limit equals the constant itself—no matter what value xx approaches, a constant function never changes
  • Formal notation: limxck=k\lim_{x \to c} k = k, where kk is any constant
  • Why it matters: This rule lets you pull constants out of more complex limit expressions

Limit of x

  • The limit of xx as xcx \to c is simply cc—the function value equals the input at that point
  • Formal notation: limxcx=c\lim_{x \to c} x = c, reflecting direct substitution for continuous functions
  • Foundation for polynomials: Combined with the power rule, this lets you evaluate any polynomial limit directly

Compare: Limit of a Constant vs. Limit of xx—both allow direct evaluation, but constants ignore the approach value entirely while limxcx\lim_{x \to c} x depends on cc. If you're asked to explain why limx535\lim_{x \to 5} 3 \neq 5, this distinction is your answer.


Algebraic Operation Rules

These rules let you break apart complex expressions into simpler pieces. The key insight: limits distribute across basic arithmetic operations, allowing you to evaluate piece by piece.

Constant Multiple Rule

  • Pull constants outside the limit—multiply after evaluating the function's limit
  • Formal notation: limxc[kf(x)]=klimxcf(x)\lim_{x \to c} [k \cdot f(x)] = k \cdot \lim_{x \to c} f(x)
  • Exam strategy: Always simplify by factoring out constants first to reduce calculation errors

Sum and Difference Rule

  • Limits split across addition and subtraction—evaluate each piece separately, then combine
  • Formal notation: limxc[f(x)±g(x)]=limxcf(x)±limxcg(x)\lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)
  • Application: This is how you handle polynomial limits—break them into individual terms

Product Rule

  • Multiply the individual limits—each function's limit is evaluated independently
  • Formal notation: limxc[f(x)g(x)]=limxcf(x)limxcg(x)\lim_{x \to c} [f(x) \cdot g(x)] = \lim_{x \to c} f(x) \cdot \lim_{x \to c} g(x)
  • Critical condition: Both individual limits must exist for this rule to apply

Quotient Rule

  • Divide the individual limits—but only when the denominator's limit isn't zero
  • Formal notation: limxcf(x)g(x)=limxcf(x)limxcg(x)\lim_{x \to c} \frac{f(x)}{g(x)} = \frac{\lim_{x \to c} f(x)}{\lim_{x \to c} g(x)}, provided limxcg(x)0\lim_{x \to c} g(x) \neq 0
  • Watch out: When the denominator approaches zero, you may have an indeterminate form or infinite limit instead

Compare: Product Rule vs. Quotient Rule—both combine individual limits, but the quotient rule has a restriction. If an FRQ gives you a rational function, always check the denominator's limit first before applying the rule.

Power Rule

  • Raise the limit to the power—exponents pass through the limit operation
  • Formal notation: limxc[f(x)]n=[limxcf(x)]n\lim_{x \to c} [f(x)]^n = \left[\lim_{x \to c} f(x)\right]^n
  • Polynomials made easy: Combined with the limit of xx, this handles any term like x3x^3 or x10x^{10}

Root Rule

  • Take the root of the limit—radicals pass through when the limit exists and is valid
  • Formal notation: limxcf(x)n=limxcf(x)n\lim_{x \to c} \sqrt[n]{f(x)} = \sqrt[n]{\lim_{x \to c} f(x)}
  • Domain restriction: For even roots, the limit inside must be non-negative

Compare: Power Rule vs. Root Rule—both handle exponents, but roots require the result to be defined (no even roots of negative numbers in real analysis). The power rule has no such restriction for integer powers.


Special Techniques

When direct substitution fails or functions behave unusually, these tools provide alternative approaches. These are the problem-solving strategies that separate routine problems from challenging ones.

One-Sided Limits

  • Approach from one direction only—left-hand (xcx \to c^-) or right-hand (xc+x \to c^+)
  • Notation matters: limxcf(x)\lim_{x \to c^-} f(x) means approaching from values less than cc
  • Key test for existence: A two-sided limit exists only if both one-sided limits exist and are equal

Squeeze Theorem

  • Trap a function between two others—if the outer functions share a limit, the middle function does too
  • Formal statement: If g(x)f(x)h(x)g(x) \leq f(x) \leq h(x) and limxcg(x)=limxch(x)=L\lim_{x \to c} g(x) = \lim_{x \to c} h(x) = L, then limxcf(x)=L\lim_{x \to c} f(x) = L
  • Classic application: Proving limx0xsin(1x)=0\lim_{x \to 0} x \sin\left(\frac{1}{x}\right) = 0 by bounding with ±x\pm|x|

Limits Involving Trigonometric Functions

  • Memorize the key result: limx0sinxx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 (with xx in radians)
  • Related identity: limx01cosxx=0\lim_{x \to 0} \frac{1 - \cos x}{x} = 0 appears frequently in derivative proofs
  • Why it matters: These limits form the foundation for differentiating trig functions in calculus

Compare: Squeeze Theorem vs. Trig Limits—the squeeze theorem is a technique for proving limits, while the standard trig limits are results you should memorize. The squeeze theorem is actually how limx0sinxx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 is proven geometrically.


Indeterminate Forms and Resolution

When direct substitution gives you something meaningless like 00\frac{0}{0}, these concepts help you find the actual limit. Recognizing indeterminate forms is the first step; resolving them is where the real work begins.

Indeterminate Forms

  • Common types: 00\frac{0}{0}, \frac{\infty}{\infty}, 00 \cdot \infty, \infty - \infty, 000^0, 11^\infty, 0\infty^0
  • Not an answer: These forms mean the limit requires additional work—factoring, conjugates, or L'Hôpital's rule
  • Detection method: Always try direct substitution first to identify if you have an indeterminate form

L'Hôpital's Rule

  • Take derivatives of top and bottom separately—only for 00\frac{0}{0} or \frac{\infty}{\infty} forms
  • Formal statement: If limxcf(x)g(x)\lim_{x \to c} \frac{f(x)}{g(x)} yields 00\frac{0}{0} or \frac{\infty}{\infty}, then limxcf(x)g(x)=limxcf(x)g(x)\lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}
  • Can repeat: If the result is still indeterminate, apply the rule again until you get a determinate form

Compare: Indeterminate Forms vs. Undefined Expressions—00\frac{0}{0} is indeterminate (the limit might exist), but 50\frac{5}{0} suggests an infinite limit or no limit. Don't confuse "needs more work" with "doesn't exist."


Asymptotic Behavior

These concepts describe what happens at the extremes—as xx grows without bound or as functions blow up near certain points. Asymptotes are the graphical representation of these limit behaviors.

Limits at Infinity

  • End behavior analysis: limxf(x)\lim_{x \to \infty} f(x) and limxf(x)\lim_{x \to -\infty} f(x) describe what happens as xx grows large
  • Horizontal asymptotes: If limx±f(x)=L\lim_{x \to \pm\infty} f(x) = L, then y=Ly = L is a horizontal asymptote
  • Rational function shortcut: Compare the degrees of numerator and denominator to quickly find these limits

Infinite Limits

  • Function values blow up: limxcf(x)=\lim_{x \to c} f(x) = \infty or -\infty means unbounded growth near x=cx = c
  • Vertical asymptotes: These limits indicate a vertical asymptote at x=cx = c
  • One-sided behavior: Often limxc+f(x)=\lim_{x \to c^+} f(x) = \infty while limxcf(x)=\lim_{x \to c^-} f(x) = -\infty (or vice versa)

Compare: Limits at Infinity vs. Infinite Limits—these sound similar but describe opposite situations. Limits at infinity ask "what does yy approach as x±x \to \pm\infty?" (horizontal asymptotes). Infinite limits ask "where does y±y \to \pm\infty?" (vertical asymptotes). Know both directions.


Quick Reference Table

ConceptBest Examples
Basic Building BlocksLimit of a Constant, Limit of xx
Algebraic OperationsSum/Difference Rule, Product Rule, Quotient Rule
Exponent RulesPower Rule, Root Rule
Direction-DependentOne-Sided Limits
Bounding TechniquesSqueeze Theorem
Special Memorized ResultsTrig Limits (sinxx\frac{\sin x}{x})
Problem IndicatorsIndeterminate Forms
Resolution TechniquesL'Hôpital's Rule, Factoring, Conjugates
End BehaviorLimits at Infinity (Horizontal Asymptotes)
Unbounded BehaviorInfinite Limits (Vertical Asymptotes)

Self-Check Questions

  1. Which two rules both require you to evaluate individual limits before combining them, but one has a critical restriction the other doesn't? What is that restriction?

  2. You evaluate limx2x24x2\lim_{x \to 2} \frac{x^2 - 4}{x - 2} by direct substitution and get 00\frac{0}{0}. Is this the final answer? What should you do next, and what concept does this illustrate?

  3. Compare and contrast limits at infinity and infinite limits. If a function has a horizontal asymptote at y=3y = 3 and a vertical asymptote at x=1x = -1, write the limit notation that describes each.

  4. A limit problem gives you limx0+f(x)=4\lim_{x \to 0^+} f(x) = 4 and limx0f(x)=2\lim_{x \to 0^-} f(x) = -2. Does limx0f(x)\lim_{x \to 0} f(x) exist? Which rule or concept justifies your answer?

  5. You need to find limx0x2cos(1x)\lim_{x \to 0} x^2 \cos\left(\frac{1}{x}\right). Direct substitution doesn't work, and you can't factor. Which technique from this guide would you use, and what two bounding functions would help you?