โž—Calculus II

Key Concepts of Multiple Integrals

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Why This Matters

Multiple integrals let you move beyond curves and into the world of surfaces, volumes, and three-dimensional objects. They're central to physics, engineering, and advanced mathematics because they let you compute quantities spread across regions of space rather than along a single axis.

The real skill here isn't just computing integrals. It's recognizing when to use which technique. You need to identify symmetry, transform coordinates using Jacobians, and apply theorems like Green's, Stokes', and the Divergence Theorem to convert difficult integrals into manageable ones. Know why each coordinate system simplifies certain problems and how the major theorems relate line, surface, and volume integrals to each other.


Setting Up Multiple Integrals

Setting up correct limits of integration is half the battle with multiple integrals. The differential element changes based on dimension and coordinate system, so getting comfortable with the setup process will save you on exams.

Double Integrals in Rectangular Coordinates

A double integral computes an accumulated quantity over a region in the xyxy-plane, expressed as โˆฌRf(x,y)โ€‰dA\iint_R f(x, y) \, dA where dA=dxโ€‰dydA = dx \, dy.

  • The limits of integration define the region RR. For a general (non-rectangular) region, the inner limits typically depend on the outer variable.
  • If you integrate dydy first, the inner limits are functions of xx. If you integrate dxdx first, the inner limits are functions of yy.
  • Master this setup before moving to other coordinate systems, since polar, cylindrical, and spherical all build on the same logic.

Triple Integrals in Rectangular Coordinates

Triple integrals extend integration to three dimensions: โˆญEf(x,y,z)โ€‰dV\iiint_E f(x, y, z) \, dV where dV=dxโ€‰dyโ€‰dzdV = dx \, dy \, dz.

  • Used for computing volume, mass, and moments when the region has faces parallel to coordinate planes (boxes, rectangular slabs, etc.).
  • There are six possible orders of integration (dxโ€‰dyโ€‰dzdx\,dy\,dz, dxโ€‰dzโ€‰dydx\,dz\,dy, etc.). Choosing wisely can dramatically simplify your calculation, so sketch the region and think about which variable has the simplest bounds before you start.

Fubini's Theorem

Fubini's Theorem guarantees that when ff is continuous over a closed, bounded region, the double integral equals the iterated integral regardless of the order you choose. In other words, you can integrate with respect to xx first or yy first and get the same answer.

This is a critical exam strategy tool: if one order of integration leads to an integral you can't evaluate (say, โˆซey2โ€‰dy\int e^{y^2} \, dy), Fubini's Theorem justifies switching to the other order, which may be straightforward.

Iterated Integrals

Iterated integrals are the actual technique you use to evaluate multiple integrals. You break the problem into sequential single integrals and evaluate from the inside out, treating other variables as constants at each step.

  • Even when both orders give the same result, one order may be far simpler to compute.
  • Watch your limits carefully. For non-rectangular regions, inner limits are often functions of the outer variable(s).

Compare: Fubini's Theorem vs. Iterated Integrals โ€” Fubini's Theorem is the justification for why iterated integrals work, while iterated integrals are the technique you actually use. If a problem asks you to evaluate a double integral, you're using iterated integrals. If it asks why you can switch the order, cite Fubini's Theorem.


Coordinate Transformations

Choosing the right coordinate system can transform an impossible integral into a straightforward one. The key is matching the symmetry of your region to the natural symmetry of a coordinate system.

Double Integrals in Polar Coordinates

Polar coordinates convert (x,y)(x, y) to (r,ฮธ)(r, \theta) using x=rcosโกฮธx = r\cos\theta, y=rsinโกฮธy = r\sin\theta. The area element becomes dA=rโ€‰drโ€‰dฮธdA = r \, dr \, d\theta.

  • That extra factor of rr is the Jacobian. Forgetting it is the single most common error on exams.
  • Any time you see x2+y2x^2 + y^2 in the integrand or boundary, think polar. Circular and annular regions become simple rectangles in rฮธr\theta-space.

Triple Integrals in Cylindrical Coordinates

Cylindrical coordinates use (r,ฮธ,z)(r, \theta, z) where x=rcosโกฮธx = r\cos\theta, y=rsinโกฮธy = r\sin\theta, and zz stays the same. The volume element is dV=rโ€‰drโ€‰dฮธโ€‰dzdV = r \, dr \, d\theta \, dz.

Think of this as polar coordinates in the xyxy-plane with zz tacked on. It's the natural choice for cylinders, cones, and paraboloids, or any solid whose cross-sections in the xyxy-plane are circles.

Triple Integrals in Spherical Coordinates

Spherical coordinates use (ฯ,ฮธ,ฯ•)(\rho, \theta, \phi) where ฯ\rho is the distance from the origin, ฮธ\theta is the azimuthal angle (same as in cylindrical), and ฯ•\phi is the angle measured down from the positive zz-axis.

  • The volume element is dV=ฯ2sinโกฯ•โ€‰dฯโ€‰dฮธโ€‰dฯ•dV = \rho^2 \sin\phi \, d\rho \, d\theta \, d\phi. This Jacobian factor is heavily tested, so memorize it.
  • The conversion formulas are: x=ฯsinโกฯ•cosโกฮธx = \rho\sin\phi\cos\theta, y=ฯsinโกฯ•sinโกฮธy = \rho\sin\phi\sin\theta, z=ฯcosโกฯ•z = \rho\cos\phi.
  • Use spherical coordinates when boundaries involve x2+y2+z2=ฯ2x^2 + y^2 + z^2 = \rho^2 or the region has symmetry about a point (spheres, hemispheres, cones centered at the origin).

Change of Variables and Jacobian Determinants

The Jacobian generalizes all coordinate transformations. For a transformation from (u,v)(u, v) to (x,y)(x, y), the Jacobian is the absolute value of the determinant:

J=โˆฃโˆ‚(x,y)โˆ‚(u,v)โˆฃ=โˆฃโˆ‚xโˆ‚uโˆ‚yโˆ‚vโˆ’โˆ‚xโˆ‚vโˆ‚yโˆ‚uโˆฃJ = \left|\frac{\partial(x,y)}{\partial(u,v)}\right| = \left|\frac{\partial x}{\partial u}\frac{\partial y}{\partial v} - \frac{\partial x}{\partial v}\frac{\partial y}{\partial u}\right|

This factor scales the area (or volume) element to account for how the transformation stretches or compresses space. The rr in polar coordinates and the ฯ2sinโกฯ•\rho^2\sin\phi in spherical coordinates are both specific Jacobians. For a general substitution x=g(u,v)x = g(u,v), y=h(u,v)y = h(u,v), the integral transforms as:

โˆฌRf(x,y)โ€‰dA=โˆฌSf(g(u,v),h(u,v))โ€‰โˆฃJโˆฃโ€‰duโ€‰dv\iint_R f(x,y) \, dA = \iint_S f(g(u,v), h(u,v)) \, |J| \, du \, dv

Compare: Cylindrical vs. Spherical Coordinates โ€” Both handle 3D symmetry, but cylindrical works best when symmetry is around an axis (like a cylinder or pipe), while spherical works best when symmetry is around a point (like a sphere or ball). If your boundary equation involves both x2+y2x^2 + y^2 and z2z^2 combined as x2+y2+z2x^2 + y^2 + z^2, spherical is usually the way to go.


Line and Surface Integrals

These integrals extend integration to curves and surfaces, measuring quantities like work, flux, and circulation. They're the building blocks for the major theorems of vector calculus.

Line Integrals

A line integral accumulates a quantity along a curve CC. There are two main forms:

  • Scalar line integral: โˆซCfโ€‰ds\int_C f \, ds, which sums up a scalar function weighted by arc length. Used for things like total mass along a wire.
  • Vector line integral: โˆซCFโ‹…dr\int_C \mathbf{F} \cdot d\mathbf{r}, which measures how much a vector field pushes along the path. This computes work done by a force field.

To evaluate either form, you parameterize the curve as r(t)\mathbf{r}(t) for aโ‰คtโ‰คba \leq t \leq b, then convert everything to the single parameter tt.

Surface Integrals

A surface integral accumulates a quantity over a surface SS in 3D space: โˆฌSfโ€‰dS\iint_S f \, dS.

  • For a surface parameterized by r(u,v)\mathbf{r}(u, v), the surface area element is dS=โˆฅruร—rvโˆฅโ€‰duโ€‰dvdS = \|\mathbf{r}_u \times \mathbf{r}_v\| \, du \, dv. The cross product magnitude gives the local scaling factor, analogous to the Jacobian.
  • If the surface is given as z=g(x,y)z = g(x,y), then dS=1+gx2+gy2โ€‰dAdS = \sqrt{1 + g_x^2 + g_y^2} \, dA, which is often easier to work with.

Flux Integrals

Flux integrals measure the flow of a vector field through a surface:

โˆฌSFโ‹…dS=โˆฌSFโ‹…nโ€‰dS\iint_S \mathbf{F} \cdot d\mathbf{S} = \iint_S \mathbf{F} \cdot \mathbf{n} \, dS

  • Orientation matters. The unit normal vector n\mathbf{n} must point in the correct direction. For closed surfaces, the convention is outward-pointing normals.
  • Positive flux means net flow out of the surface; negative flux means net flow in.

Compare: Line Integrals vs. Surface Integrals โ€” Line integrals measure accumulation along 1D curves (work, circulation), while surface integrals measure accumulation across 2D surfaces (flux, surface area). Both require careful parameterization, and both appear in the major theorems of vector calculus.


The Fundamental Theorems of Vector Calculus

These three theorems connect different types of integrals. Each one relates an integral over a boundary to an integral over the region that boundary encloses. They're heavily tested, so know the hypotheses, the formulas, and when to apply each one.

Green's Theorem

Green's Theorem connects a line integral around a closed curve to a double integral over the enclosed region in 2D:

โˆฎC(Pโ€‰dx+Qโ€‰dy)=โˆฌR(โˆ‚Qโˆ‚xโˆ’โˆ‚Pโˆ‚y)dA\oint_C (P \, dx + Q \, dy) = \iint_R \left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right) dA

  • The curve CC must be simple (no self-intersections), closed, and positively oriented (counterclockwise, with the region on your left).
  • Use it in whichever direction makes the problem easier. Sometimes the line integral is hard but the double integral is simple, and sometimes it's the reverse.

Stokes' Theorem

Stokes' Theorem generalizes Green's Theorem to surfaces in 3D:

โˆฎCFโ‹…dr=โˆฌS(โˆ‡ร—F)โ‹…dS\oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot d\mathbf{S}

  • It relates circulation of F\mathbf{F} around a closed curve CC to the integral of the curl โˆ‡ร—F\nabla \times \mathbf{F} over any surface SS bounded by CC.
  • Orientation must be consistent: use the right-hand rule. If your right hand's fingers curl in the direction of CC, your thumb points in the direction of the surface normal n\mathbf{n}.

Divergence Theorem (Gauss's Theorem)

The Divergence Theorem relates flux through a closed surface to a volume integral of divergence:

โˆฏSFโ‹…dS=โˆญV(โˆ‡โ‹…F)โ€‰dV\oiint_S \mathbf{F} \cdot d\mathbf{S} = \iiint_V (\nabla \cdot \mathbf{F}) \, dV

  • The surface SS must be closed (like a sphere, box, or cylinder with caps) with outward-pointing normals.
  • Divergence โˆ‡โ‹…F\nabla \cdot \mathbf{F} measures source/sink strength at each point. Positive divergence means the field is expanding; negative means it's contracting.
  • This theorem is especially useful when computing flux directly would require parameterizing a complicated surface, but the divergence is simple.

Compare: Green's vs. Stokes' vs. Divergence โ€” All three relate a boundary integral to a region integral. Green's is 2D (line integral โ†’ double integral). Stokes' goes from a 3D boundary curve to a surface (circulation โ†’ curl). Divergence goes from a 3D closed surface to a volume (flux โ†’ divergence). To pick the right theorem on an exam, check the dimension and ask: am I dealing with curl, divergence, or a flat 2D region?


Applications of Multiple Integrals

Multiple integrals compute real physical quantities. Understanding these applications helps you set up integrals correctly and interpret your answers.

Volume, Mass, and Center of Mass

Volume of a region EE is the simplest application: V=โˆญEdVV = \iiint_E dV. You're integrating the constant function 1 over the region.

Mass with variable density uses a density function ฯ(x,y,z)\rho(x,y,z) to weight each piece of volume: m=โˆญEฯ(x,y,z)โ€‰dVm = \iiint_E \rho(x,y,z) \, dV. If density is constant, mass is just ฯร—V\rho \times V.

Center of mass locates the balance point using moment integrals. For example, the xx-coordinate of the center of mass is:

xห‰=1mโˆญExโ€‰ฯโ€‰dV\bar{x} = \frac{1}{m}\iiint_E x\,\rho \, dV

with analogous formulas for yห‰\bar{y} and zห‰\bar{z}. Always compute total mass mm first, then the moment integrals.

Compare: Volume vs. Mass Integrals โ€” Volume integrates dVdV alone, while mass integrates ฯโ€‰dV\rho \, dV. For center of mass problems, you need both: total mass for the denominator and moment integrals for the numerators.


Quick Reference Table

ConceptBest Examples
Rectangular coordinatesDouble integrals, Triple integrals, Iterated integrals
Polar/Cylindrical symmetryDouble integrals in polar, Triple integrals in cylindrical
Spherical symmetryTriple integrals in spherical coordinates
Coordinate transformation theoryChange of variables, Jacobian determinants
Line/curve integrationLine integrals, Green's Theorem
Surface integrationSurface integrals, Flux integrals, Stokes' Theorem
Volume integration theoremsDivergence Theorem
Physical applicationsVolume, mass, center of mass calculations

Self-Check Questions

  1. When would you choose spherical coordinates over cylindrical coordinates for a triple integral? Give a specific example of a region where each is preferred.

  2. What is the Jacobian for polar coordinates, and why does forgetting it lead to incorrect answers? How does this connect to the general change of variables formula?

  3. Compare Green's Theorem and Stokes' Theorem: what do they have in common, and how does Stokes' Theorem generalize Green's Theorem to three dimensions?

  4. If you need to compute the flux of a vector field through a closed surface, which theorem might simplify your calculation? Under what conditions would using the theorem be easier than direct computation?

  5. Given the integral โˆฌR(x2+y2)โ€‰dA\iint_R (x^2 + y^2) \, dA over the disk x2+y2โ‰ค4x^2 + y^2 \leq 4, explain why polar coordinates simplify this problem and set up (but don't evaluate) the transformed integral.