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Energy band diagrams are the foundation for understanding why materials conduct electricity differently—and more importantly, how we engineer semiconductors to build every electronic device you use. When you're tested on semiconductor physics, you're really being asked to explain the relationship between band structure, charge carriers, and device behavior. Questions will probe whether you understand how doping shifts the Fermi level, why junctions create built-in electric fields, and what happens to band diagrams under bias conditions.
These concepts connect directly to carrier transport, junction physics, and device operation—the core principles that appear repeatedly in FRQs about diodes, transistors, and photovoltaic cells. Don't just memorize that silicon has a band gap of —know what that means for thermal excitation, doping effectiveness, and device applications. If you can sketch a band diagram and explain what's happening to electrons and holes, you've mastered the conceptual core of semiconductor physics.
The band gap—the energy separation between the valence and conduction bands—determines whether a material is an insulator, semiconductor, or conductor. This single parameter controls whether electrons can be thermally excited into conducting states.
Compare: Insulators vs. Semiconductors—both have band gaps, but semiconductors' smaller gap allows thermal generation of carriers at room temperature. If an FRQ asks why silicon works for transistors but glass doesn't, band gap magnitude is your answer.
Pure semiconductors have limited conductivity, but doping—intentionally adding impurities—lets us control carrier type and concentration. This is how we transform a mediocre conductor into a precisely engineered electronic material.
Compare: N-type vs. P-type—both increase conductivity through doping, but they create opposite majority carriers. On band diagrams, look for the Fermi level position: closer to means N-type, closer to means P-type.
When different materials meet, band bending occurs to equalize the Fermi level across the junction. This creates built-in electric fields and the depletion regions that make devices work.
Compare: Forward vs. Reverse Bias—both involve the same junction, but forward bias shrinks the depletion region (current flows) while reverse bias expands it (current blocked). Draw the band diagrams side-by-side to see how the barrier height changes.
Not all junctions involve two semiconductors. Metal-semiconductor interfaces create their own unique band structures with distinct advantages for certain applications.
Compare: Schottky vs. P-N Junction—both rectify current, but Schottky junctions use majority carriers only, enabling faster switching. P-N junctions have higher forward voltage drop but better reverse blocking. Choose Schottky for speed, P-N for power handling.
| Concept | Best Examples |
|---|---|
| Band gap classification | Insulators (> 4 eV), Semiconductors (1–3 eV), Conductors (overlapping bands) |
| Intrinsic behavior | Pure Si, pure Ge, thermal carrier generation |
| N-type doping | Phosphorus in Si, arsenic in Si, donor levels near |
| P-type doping | Boron in Si, gallium in Si, acceptor levels near |
| Junction formation | P-N junction, depletion region, built-in potential |
| Forward bias effects | Reduced barrier, narrowed depletion, exponential current |
| Reverse bias effects | Increased barrier, widened depletion, saturation current |
| Metal-semiconductor contacts | Schottky barrier, thermionic emission, low forward drop |
What feature of the band diagram distinguishes an N-type semiconductor from a P-type semiconductor, and how does this relate to majority carrier type?
Compare the depletion region width under forward bias versus reverse bias—what happens to the built-in electric field in each case?
If an FRQ shows a band diagram with the Fermi level very close to the conduction band, what can you conclude about the doping type and approximate dopant concentration?
Why does a Schottky diode switch faster than a P-N junction diode? Explain in terms of the charge carriers involved in each device.
Two semiconductors have band gaps of and . Which would have higher intrinsic carrier concentration at room temperature, and how would this affect their conductivity without doping?