Integration is the backbone of Unit 6 and shows up everywhere in AP Calculus—from finding areas and volumes to solving differential equations in Unit 7. You're being tested on your ability to recognize which technique fits which integral, not just whether you can mechanically execute a formula. The exam loves to present integrals that look intimidating but collapse beautifully once you identify the right approach: substitution, parts, partial fractions, or trigonometric manipulation.
Think of integration methods as a toolkit. Each technique exists because certain integral forms resist the basic power rule, and mathematicians developed specific strategies to handle them. The Fundamental Theorem of Calculus connects all of this to accumulation and net change, so every method you master here directly supports your ability to model real-world problems. Don't just memorize steps—know why each method works and when to reach for it.
Direct Integration: The Foundation
These methods handle the simplest cases and form the building blocks for everything else. When an integral matches a known form directly, apply the rule without overcomplicating it.
Power Rule and Constant Multiple Rule
Power rule: ∫xndx=n+1xn+1+C for n=−1—this is your first attempt on any polynomial term
Constant multiple rule lets you factor out constants: ∫k⋅f(x)dx=k∫f(x)dx, simplifying coefficients before integrating
Always add C for indefinite integrals—forgetting this constant of integration costs easy points on FRQs
Inverse Trigonometric Integrals
Recognize the forms: ∫1−x21dx=arcsin(x)+C and ∫1+x21dx=arctan(x)+C—these appear frequently
Pattern matching is key: any integral resembling a2−x21 or a2+x21 signals an inverse trig result
Memorize the derivatives of arcsin, arctan, and arcsec—integration reverses these relationships
Compare: Power Rule vs. Inverse Trig Forms—both are "direct" integrations, but power rule handles polynomial terms while inverse trig forms handle specific rational/radical structures. If you see 1+x21, don't try polynomial techniques—recognize it as arctan(x) immediately.
Substitution Methods: Simplifying Structure
When the integrand contains a composite function, substitution transforms it into something manageable. The chain rule in reverse—look for an "inside function" and its derivative nearby.
U-Substitution
Core idea: Let u=g(x), then du=g′(x)dx—rewrite the entire integral in terms of u only
Look for the chain rule pattern: the integrand should contain both a composite function and (a multiple of) the derivative of the inner function
Substitute back after integrating to express your answer in terms of x; for definite integrals, you can convert limits to u-values instead
Trigonometric Substitution
Use when you see radicals: a2−x2 suggests x=asinθ; a2+x2 suggests x=atanθ; x2−a2 suggests x=asecθ
Pythagorean identities eliminate the radical: for example, a2−a2sin2θ=acosθ
Convert everything: replace dx, adjust limits for definite integrals, and draw a reference triangle to convert back to x
Compare: U-Substitution vs. Trigonometric Substitution—u-sub works when you spot a function-derivative pair; trig sub handles radicals involving sums/differences of squares. U-sub is your everyday tool; trig sub is specialized for geometric forms.
Integration by Parts: Products of Functions
When the integrand is a product of two different function types, parts separates them strategically. Based on the product rule in reverse: ∫udv=uv−∫vdu.
Integration by Parts
Formula: ∫udv=uv−∫vdu—choose u to be the function that simplifies when differentiated, and dv to be easily integrable
LIATE priority helps with choosing u: Logarithmic, Inverse trig, Algebraic, Trigonometric, Exponential—earlier categories typically become u
Repeat if necessary: integrals like ∫x2exdx require applying parts multiple times; watch for cyclic patterns with trig-exponential products
Compare: U-Substitution vs. Integration by Parts—u-sub simplifies composites (function inside function); parts handles products (function times function). If you see x⋅ex, think parts; if you see ex2⋅2x, think u-sub.
Rational Function Techniques: Breaking Down Fractions
Rational functions (polynomial over polynomial) require algebraic manipulation before integration. The goal is to decompose complexity into integrable pieces.
Polynomial Long Division
When to use: if the degree of the numerator is greater than or equal to the degree of the denominator, divide first
Result: a polynomial (easy to integrate) plus a proper fraction where the numerator's degree is less than the denominator's
Then proceed with partial fractions or direct integration on the remaining proper fraction
Partial Fraction Decomposition
Purpose: break a proper rational function into a sum of simpler fractions like x−aA or x2+kBx+C
Factor the denominator completely into linear and irreducible quadratic factors; set up unknown constants for each factor
Solve for constants by clearing denominators and matching coefficients or substituting strategic x-values
Compare: Long Division vs. Partial Fractions—long division reduces improper fractions to proper ones; partial fractions decomposes proper fractions into integrable pieces. Always check degrees first: if numerator degree ≥ denominator degree, divide before decomposing.
Integrands with powers of sine, cosine, tangent, or secant often require identity manipulation. Pythagorean identities and power-reducing formulas are your primary tools.
Trigonometric Integrals
Odd powers of sin or cos: save one factor for du and convert the rest using sin2x+cos2x=1
Even powers: use power-reducing identities like sin2x=21−cos(2x) and cos2x=21+cos(2x)
Tangent-secant integrals: save sec2x for du when you have even secant powers, or secxtanx when you have odd tangent powers
Compare: Trigonometric Integrals vs. Trigonometric Substitution—trig integrals start with trig functions and use identities to simplify; trig substitution introduces trig functions to eliminate radicals. Know which direction you're going: simplifying trig or creating it.
Improper Integrals: Handling Infinity
When limits extend to infinity or the integrand has discontinuities, standard techniques need modification. Replace problematic bounds with limits and evaluate convergence.
Improper Integrals
Infinite limits: evaluate ∫a∞f(x)dx as limt→∞∫atf(x)dx—if the limit exists, the integral converges
Discontinuous integrands: split the integral at the discontinuity and take one-sided limits approaching the problem point
Convergence tests: compare to known convergent/divergent integrals; ∫1∞xp1dx converges for p>1 and diverges for p≤1
Compare: Convergent vs. Divergent Improper Integrals—both involve limits, but convergent integrals yield finite values while divergent ones grow without bound. FRQs often ask you to determine which case applies and justify your reasoning.
Quick Reference Table
Concept
Best Examples
Direct integration
Power rule, constant multiple rule, inverse trig forms