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Important Formulas

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Why This Matters

Mathematics isn't about memorizing a grab bag of equations—it's about recognizing patterns, relationships, and problem-solving structures. Every formula on this list represents a fundamental concept that appears repeatedly across algebra, geometry, trigonometry, and applied math. You're being tested on your ability to not just plug numbers into equations, but to identify which formula applies to a given situation and understand why it works.

These formulas fall into distinct categories: solving equations, measuring geometric figures, analyzing linear and exponential relationships, and working with triangles. When you encounter a problem, your first job is to recognize the underlying concept—is this about finding unknown values? Measuring space? Modeling change over time? Don't just memorize these formulas in isolation; know what type of problem each one solves and how they connect to each other.


Solving for Unknowns

These formulas help you find values that aren't immediately given—whether that's the solution to an equation or the missing side of a triangle. The key principle is using known relationships to determine unknown quantities.

Quadratic Formula

  • Solves any quadratic equation in standard form ax2+bx+c=0ax^2 + bx + c = 0—works even when factoring fails
  • The formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} gives both solutions simultaneously using the ± symbol
  • The discriminant b24acb^2 - 4ac tells you the nature of roots: positive means two real solutions, zero means one, negative means complex

Pythagorean Theorem

  • Relates the three sides of a right triangle through a2+b2=c2a^2 + b^2 = c^2, where cc is always the hypotenuse
  • Find any missing side by rearranging: c=a2+b2c = \sqrt{a^2 + b^2} or a=c2b2a = \sqrt{c^2 - b^2}
  • Foundation for distance calculations—this theorem underlies the distance formula and appears throughout geometry and physics

Trigonometric Ratios

  • SOH-CAH-TOA defines the three primary ratios: sinθ=oppositehypotenuse\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}, cosθ=adjacenthypotenuse\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}, tanθ=oppositeadjacent\tan\theta = \frac{\text{opposite}}{\text{adjacent}}
  • Choose your ratio based on which sides you know and which you need—each ratio uses a different pair
  • Bridges angles and distances—essential for real-world applications like surveying, navigation, and physics problems

Compare: Pythagorean Theorem vs. Trigonometric Ratios—both solve right triangle problems, but Pythagorean works when you know two sides and need the third, while trig ratios work when you have an angle and one side. If a problem gives you an angle measure, reach for trig.


Measuring Circles and Cylinders

Circle-based formulas all stem from the relationship between a circle's radius and its properties. The constant π\pi (approximately 3.14159) represents the ratio of circumference to diameter—it's built into every circle formula.

Area of a Circle

  • A=πr2A = \pi r^2 calculates the space enclosed by the circle, where rr is the radius
  • Radius is squared—doubling the radius quadruples the area, a common exam trap
  • Real-world applications include calculating material needed for circular objects, coverage areas, and cross-sections

Circumference of a Circle

  • C=2πrC = 2\pi r or equivalently C=πdC = \pi d measures the distance around the circle
  • Linear relationship with radius—unlike area, doubling the radius only doubles the circumference
  • Use for perimeter problems involving circular paths, wheels, or any "distance around" scenario

Volume of a Cylinder

  • V=πr2hV = \pi r^2 h combines the circular base area (πr2\pi r^2) with height (hh)
  • Think of it as stacked circles—the formula literally multiplies base area by how many "layers" you have
  • Capacity problems like tanks, pipes, and containers all use this formula

Compare: Area of a Circle vs. Volume of a Cylinder—notice that πr2\pi r^2 appears in both. The cylinder formula is just the circle's area extended into three dimensions. If you forget the cylinder formula, just remember: base area times height.


Analyzing Linear Relationships

Linear equations describe constant rates of change—situations where the relationship between variables forms a straight line. The slope represents how much yy changes for each unit change in xx.

Slope-Intercept Form

  • y=mx+by = mx + b where mm is the slope and bb is the y-intercept (the point where the line crosses the y-axis)
  • Slope = rise over run—positive slopes go up left to right, negative slopes go down, zero slope is horizontal
  • Instantly graphable—start at bb on the y-axis, then use mm to find additional points

Distance Formula

  • d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} calculates the straight-line distance between two coordinate points
  • Derived directly from Pythagorean theorem—the horizontal and vertical distances form the legs of a right triangle
  • Essential for coordinate geometry—finding lengths of segments, perimeters, and verifying geometric properties

Compare: Slope-Intercept Form vs. Distance Formula—both work in the coordinate plane, but they answer different questions. Slope-intercept describes direction and steepness of a line; distance formula measures how far between two specific points. Know which question you're being asked.


Modeling Growth and Change

These formulas describe quantities that don't change at constant rates—they either accelerate (exponential growth) or can be "undone" through inverse operations. Understanding these relationships is crucial for real-world applications in science, finance, and data analysis.

Exponential Growth/Decay

  • y=a(1±r)ny = a(1 \pm r)^n where aa is initial value, rr is rate (as decimal), and nn is time periods
  • Use + for growth, − for decay—population increase uses (1+r)(1 + r), radioactive decay uses (1r)(1 - r)
  • Compound interest variation: A=P(1+rn)ntA = P(1 + \frac{r}{n})^{nt} accounts for compounding frequency—know both forms

Logarithmic Formula

  • logb(a)=c\log_b(a) = c means bc=ab^c = a—logarithms answer "what exponent gives me this result?"
  • Common bases: log\log typically means base 10, ln\ln means base ee (natural log, approximately 2.718)
  • Inverse of exponentials—use logs to solve for exponents in equations like 2x=162^x = 16

Compare: Exponential vs. Logarithmic formulas—these are inverse operations, like multiplication and division. Exponentials ask "what do I get when I raise this base to this power?" Logarithms ask "what power gives me this result?" FRQs often require converting between forms.


Quick Reference Table

ConceptBest Examples
Finding unknown valuesQuadratic Formula, Pythagorean Theorem
Right triangle relationshipsPythagorean Theorem, Trigonometric Ratios
Circle measurementsArea (πr2\pi r^2), Circumference (2πr2\pi r)
3D measurementsVolume of Cylinder (πr2h\pi r^2 h)
Linear relationshipsSlope-Intercept Form, Distance Formula
Coordinate geometryDistance Formula, Slope-Intercept Form
Modeling change over timeExponential Growth/Decay, Logarithms
Inverse operationsExponentials ↔ Logarithms, Squaring ↔ Square roots

Self-Check Questions

  1. Both the Pythagorean Theorem and the Distance Formula involve square roots. How does the distance formula derive from the Pythagorean Theorem, and when would you use each?

  2. You need to find the area of a circular garden and the amount of fencing to surround it. Which two formulas do you need, and what's the key difference in how radius affects each answer?

  3. Compare and contrast: How would you approach solving x2+5x+6=0x^2 + 5x + 6 = 0 versus solving 3x=813^x = 81? Which formulas or techniques apply to each?

  4. A problem gives you a right triangle with one acute angle measuring 35° and a hypotenuse of 10. Which trigonometric ratio would you use to find the side opposite the angle, and why not the others?

  5. If an FRQ asks you to model a population that doubles every 5 years starting from 1,000, write the exponential equation. Then explain what logarithms would help you find if the question asked "when will the population reach 8,000?"