⏱️General Chemistry II

Gibbs Free Energy Equations

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Why This Matters

Gibbs free energy tells you whether a reaction will happen on its own or whether you need to put energy in to make it go. In General Chemistry II, you're expected to connect enthalpy, entropy, and temperature into a single predictive framework. Equilibrium problems, electrochemistry questions, and phase change discussions all come back to ΔG\Delta G.

These equations aren't isolated formulas. They represent different ways of asking the same question: is this process thermodynamically favorable? Whether you're calculating equilibrium constants, predicting cell voltages, or figuring out if a reaction becomes spontaneous at high temperatures, you need to know which equation to reach for and why it fits the situation.


Predicting Spontaneity: The Core Equation

Gibbs free energy balances two competing thermodynamic drives: the tendency to minimize energy (enthalpy) and the tendency to maximize disorder (entropy).

The Fundamental Gibbs Equation

ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S

  • Negative ΔG\Delta G indicates a spontaneous process. This is the single most important criterion for spontaneity at constant T and P.
  • ΔH\Delta H (enthalpy change) captures heat flow. Exothermic reactions (ΔH<0\Delta H < 0) favor spontaneity.
  • TΔST\Delta S (entropy term) grows with temperature. Reactions with positive ΔS\Delta S become more favorable as T rises.

There are four possible sign combinations of ΔH\Delta H and ΔS\Delta S, and two of them make spontaneity temperature-dependent:

ΔH\Delta HΔS\Delta SSpontaneous?
-++Always (ΔG<0\Delta G < 0 at all T)
++-Never (ΔG>0\Delta G > 0 at all T)
--Only at low T (enthalpy wins)
++++Only at high T (entropy wins)

For the temperature-dependent cases, the crossover temperature where ΔG=0\Delta G = 0 is:

T=ΔHΔST = \frac{\Delta H}{\Delta S}

This is the temperature at which the reaction switches between spontaneous and non-spontaneous. Just set ΔG=0\Delta G = 0 in the fundamental equation and solve for T.

Gibbs Free Energy and Maximum Work

ΔG=wmax\Delta G = w_{max} (at constant T and P)

  • ΔG\Delta G equals the maximum non-expansion work obtainable from a reversible process. Non-expansion work means any work other than pressure-volume work, such as electrical work in a battery.
  • Negative ΔG\Delta G means the system can perform work on its surroundings; positive ΔG\Delta G means work must be done on the system.
  • Real processes always yield less work than this maximum due to irreversibilities and friction.

Compare: The fundamental equation (ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S) vs. the work equation (ΔG=wmax\Delta G = w_{max}) describe the same quantity from different angles. The first tells you why a process is spontaneous; the second tells you what you can get from that spontaneity. Exam free-response questions sometimes ask you to interpret ΔG\Delta G in both contexts.


Connecting to Equilibrium: Standard and Non-Standard Conditions

These equations bridge thermodynamics and equilibrium. ΔG\Delta G determines where a reaction "wants" to go, while K tells you where it ends up.

Standard Free Energy and Equilibrium Constant

ΔG°=RTlnK\Delta G° = -RT \ln K

  • ΔG°\Delta G° is the standard free energy change, measured with all species at 1 M (solutions) or 1 atm (gases) at the specified temperature.
  • Large K (>1) corresponds to negative ΔG°\Delta G°, meaning products are favored at equilibrium.
  • Small K (<1) corresponds to positive ΔG°\Delta G°, meaning reactants are favored.
  • The relationship is logarithmic. At 298 K, a change of about 5.7 kJ/mol in ΔG°\Delta G° shifts K by a factor of 10.

Here, R=8.314 J/(mol\cdotpK)R = 8.314 \text{ J/(mol·K)} and TT is in Kelvin. Watch your units: if ΔG°\Delta G° is given in kJ/mol, convert to J/mol before plugging in. This is one of the most common calculation errors on exams.

Non-Standard Conditions: The Reaction Quotient

ΔG=ΔG°+RTlnQ\Delta G = \Delta G° + RT \ln Q

  • Q (reaction quotient) is the current ratio of products to reactants, calculated the same way as K but using current concentrations or pressures, not equilibrium values.
  • When Q < K, ΔG<0\Delta G < 0 and the reaction proceeds forward spontaneously.
  • When Q = K, ΔG=0\Delta G = 0 and the system is at equilibrium.
  • When Q > K, ΔG>0\Delta G > 0 and the reaction proceeds in reverse.

Notice that when all species are at standard conditions, Q=1Q = 1, so lnQ=0\ln Q = 0, and the equation reduces to ΔG=ΔG°\Delta G = \Delta G°. That's why standard conditions are the "default."

Compare: ΔG°\Delta G° vs. ΔG\Delta G. Students frequently confuse these. ΔG°\Delta G° is a fixed property of the reaction at standard conditions (like a "default setting"), while ΔG\Delta G changes based on actual concentrations. If a problem gives you concentrations that aren't 1 M, you must use the Q equation.


Electrochemistry Connection

Electrochemical cells convert chemical energy directly to electrical work. The cell potential is just another way of expressing Gibbs free energy.

Gibbs Free Energy and Cell Potential

ΔG=nFE\Delta G = -nFE

  • nn = moles of electrons transferred in the balanced redox reaction
  • FF = Faraday's constant = 96,485 C/mol ee^-
  • EE = cell potential in volts (V)
  • Positive EE gives negative ΔG\Delta G, so spontaneous galvanic cells have positive voltages.

Under standard conditions, this becomes ΔG°=nFE°\Delta G° = -nFE°. You can combine this with ΔG°=RTlnK\Delta G° = -RT \ln K to get a useful relationship:

E°=RTnFlnKE° = \frac{RT}{nF} \ln K

This equation connects the standard cell potential directly to the equilibrium constant. At 298 K, it simplifies to:

E°=0.02569 VnlnKE° = \frac{0.02569 \text{ V}}{n} \ln K

Compare: ΔG°=RTlnK\Delta G° = -RT \ln K and ΔG=nFE\Delta G = -nFE both relate ΔG\Delta G to measurable quantities (K and E, respectively). Exams frequently ask you to move between all three: given E°, find ΔG°\Delta G°, then find K. Practice chaining these equations together.

Here's the typical workflow for these chain problems:

  1. Use ΔG°=nFE°\Delta G° = -nFE° to convert a given E° to ΔG°\Delta G°
  2. Use ΔG°=RTlnK\Delta G° = -RT \ln K to solve for K
  3. Or go directly with E°=RTnFlnKE° = \frac{RT}{nF} \ln K

Phase Transitions and Equilibrium Conditions

At phase boundaries and equilibrium points, the system has minimized its Gibbs free energy. Competing phases or reactions are perfectly balanced.

Equilibrium Criterion

ΔG=0\Delta G = 0 (at equilibrium)

  • Minimum Gibbs free energy defines the equilibrium state. The system has no thermodynamic driving force to change.
  • Phase transitions (melting, boiling, sublimation) occur when ΔG=0\Delta G = 0 between phases at specific T and P. For example, water boils at 100°C (at 1 atm) because that's where ΔG\Delta G for the liquid-to-gas transition equals zero.
  • Forward and reverse rates are equal, connecting thermodynamic equilibrium to kinetic equilibrium.

Temperature Dependence: Gibbs-Helmholtz Equation

((ΔG/T)T)P=ΔHT2\left(\frac{\partial(\Delta G/T)}{\partial T}\right)_P = -\frac{\Delta H}{T^2}

  • Relates the temperature dependence of ΔG\Delta G to enthalpy.
  • Exothermic reactions (ΔH<0\Delta H < 0) become less favorable as temperature increases.
  • Enables calculation of ΔG\Delta G at new temperatures when you know ΔH\Delta H and ΔG\Delta G at a reference temperature.

Note: This equation is more commonly tested in physical chemistry than in Gen Chem II. Your course may or may not require it. If your professor hasn't covered it, focus on the simpler approach of using ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S with the assumption that ΔH\Delta H and ΔS\Delta S are roughly constant over the temperature range.

Compare: The equilibrium criterion (ΔG=0\Delta G = 0) tells you when equilibrium occurs, while the Gibbs-Helmholtz equation tells you how the position of equilibrium shifts with temperature.


Multicomponent Systems and Mixtures

For systems with multiple species, Gibbs free energy depends on both the amounts and the chemical potentials of each component. Most Gen Chem II courses only touch on these ideas briefly, so check whether your course covers them before spending too much time here.

Chemical Potential and Total Free Energy

G=iμiniG = \sum_i \mu_i n_i

Chemical potential (μi\mu_i) is the partial molar Gibbs free energy. Think of it as how much the total G changes when you add one mole of component i while holding everything else constant. Each component contributes to total G proportionally to its amount (nin_i) and its chemical potential (μi\mu_i).

At equilibrium, the chemical potential of each species is equal in all phases it occupies. This is what drives phase distribution.

Gibbs Free Energy of Mixing (Ideal Solutions)

ΔGmix=nRT(x1lnx1+x2lnx2)\Delta G_{mix} = nRT(x_1 \ln x_1 + x_2 \ln x_2)

  • Always negative for ideal solutions because mole fractions are between 0 and 1, making the logarithms negative. Mixing is always spontaneous for ideal solutions.
  • nn is the total number of moles, and x1x_1 and x2x_2 are mole fractions of the two components.
  • This equation assumes no enthalpy change upon mixing (ΔHmix=0\Delta H_{mix} = 0), so the spontaneity is driven entirely by entropy. The increase in disorder from mixing is the only driving force.

Gibbs-Duhem Equation

ixidμi=0\sum_i x_i \, d\mu_i = 0

This equation says that chemical potentials in a mixture are interdependent. You can't change one component's μ\mu without affecting the others. It's essential for non-ideal solution thermodynamics and activity coefficient calculations, but it's more commonly tested in physical chemistry than in Gen Chem II.

Compare: The mixing equation calculates the total ΔG\Delta G for combining pure substances, while Gibbs-Duhem describes constraints on how chemical potentials can change together. The mixing equation is more commonly tested in Gen Chem II.


Quick Reference Table

ConceptKey Equation
Spontaneity criterionΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S
Crossover temperatureT=ΔH/ΔST = \Delta H / \Delta S
Equilibrium constant relationshipΔG°=RTlnK\Delta G° = -RT \ln K
Non-standard conditionsΔG=ΔG°+RTlnQ\Delta G = \Delta G° + RT \ln Q
Electrochemistry connectionΔG=nFE\Delta G = -nFE
Maximum workΔG=wmax\Delta G = w_{max}
Equilibrium conditionΔG=0\Delta G = 0
Cell potential and KE°=RTnFlnKE° = \frac{RT}{nF} \ln K
Temperature dependence((ΔG/T)T)P=ΔHT2\left(\frac{\partial(\Delta G/T)}{\partial T}\right)_P = -\frac{\Delta H}{T^2}
Multicomponent systemsG=μiniG = \sum \mu_i n_i
Ideal mixingΔGmix=nRT(x1lnx1+x2lnx2)\Delta G_{mix} = nRT(x_1 \ln x_1 + x_2 \ln x_2)

Self-Check Questions

  1. A reaction has ΔH>0\Delta H > 0 and ΔS>0\Delta S > 0. Under what temperature conditions will it be spontaneous? Which equation would you use to find the crossover temperature?

  2. If ΔG°=30\Delta G° = -30 kJ/mol, is K greater than, less than, or equal to 1? Now suppose you're told that current concentrations give Q > K. Is the reaction spontaneous in the forward direction?

  3. Compare ΔG°\Delta G° and ΔG\Delta G. Why is it critical to distinguish between them when solving equilibrium problems with non-standard concentrations?

  4. An electrochemical cell has E°>0E° > 0. What does this tell you about ΔG°\Delta G° and K for the cell reaction? Write the equation that connects all three quantities.

  5. Why is ΔGmix\Delta G_{mix} always negative for ideal solutions, even though there's no enthalpy change? Which term in ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S is responsible?