upgrade
upgrade

Calculus I

Fundamental Theorem of Calculus

Study smarter with Fiveable

Get study guides, practice questions, and cheatsheets for all your subjects. Join 500,000+ students with a 96% pass rate.

Get Started

Why This Matters

The Fundamental Theorem of Calculus (FTC) is arguably the most important result in all of calculus—it's the bridge that connects the two major operations you've been learning: differentiation and integration. You're being tested not just on whether you can apply the theorem mechanically, but on whether you understand why these two seemingly different processes are actually inverse operations. Exam questions will probe your ability to evaluate definite integrals using antiderivatives, interpret accumulation functions, and recognize when each part of the theorem applies.

This theorem unlocks everything from calculating areas under curves to modeling real-world accumulation problems in physics, economics, and biology. The key concepts you need to master include the evaluation of definite integrals, the derivative of integral functions, accumulation functions, and the inverse relationship between differentiation and integration. Don't just memorize the formulas—know what each part of the FTC tells you about how functions behave and why the connection between derivatives and integrals exists in the first place.


The Two Parts of the FTC

The Fundamental Theorem comes in two parts, and understanding which part to use—and when—is critical for exam success. Each part reveals a different direction of the derivative-integral relationship.

Part 1: The Evaluation Theorem

  • Converts definite integrals into antiderivative evaluation—if ff is continuous on [a,b][a, b] and FF is any antiderivative of ff, then abf(x)dx=F(b)F(a)\int_a^b f(x) \, dx = F(b) - F(a)
  • Continuity is required for the theorem to hold; discontinuities on the interval invalidate direct application
  • Transforms infinite Riemann sum calculations into simple subtraction, making area calculations practical and efficient

Part 2: The Derivative of an Integral Function

  • Defines how differentiation undoes integration—if F(x)=axf(t)dtF(x) = \int_a^x f(t) \, dt, then F(x)=f(x)F'(x) = f(x) wherever ff is continuous
  • The variable of integration (tt) is a dummy variable; the upper limit (xx) is what matters for differentiation
  • Chain rule extension applies when the upper limit is a function: if F(x)=ag(x)f(t)dtF(x) = \int_a^{g(x)} f(t) \, dt, then F(x)=f(g(x))g(x)F'(x) = f(g(x)) \cdot g'(x)

Compare: Part 1 vs. Part 2—both connect derivatives and integrals, but Part 1 evaluates a definite integral using antiderivatives, while Part 2 finds the derivative of an integral function. If an FRQ gives you an integral with a variable upper limit and asks for a derivative, that's Part 2; if it asks you to compute a definite integral's value, that's Part 1.


The Inverse Relationship

The FTC reveals that differentiation and integration are fundamentally inverse operations—understanding this conceptually is just as important as applying the formulas. This inverse relationship is the theoretical backbone of calculus.

Differentiation as Rate of Change

  • Measures instantaneous rate of change—the derivative f(x)f'(x) tells you how fast f(x)f(x) is changing at any point
  • Local behavior focus means derivatives describe what's happening at a single instant or location
  • Undone by integration when you integrate a rate of change, you recover the original quantity (plus a constant)

Integration as Accumulation

  • Accumulates quantities over intervals—the integral abf(x)dx\int_a^b f(x) \, dx adds up infinitely many infinitesimal contributions
  • Global behavior focus means integrals capture total change or total area across an entire interval
  • Undone by differentiation when you differentiate an accumulation function, you recover the rate being accumulated

Compare: Differentiation vs. Integration—differentiation breaks down accumulated quantities into rates, while integration builds up rates into accumulated quantities. Think of it like speed and distance: differentiating position gives velocity, integrating velocity gives displacement.


Antiderivatives and Indefinite Integrals

Before you can apply Part 1 of the FTC, you need to find antiderivatives. An antiderivative reverses the differentiation process.

The Antiderivative Concept

  • Definition: FF is an antiderivative of ff if F(x)=f(x)F'(x) = f(x) for all xx in the domain
  • Antiderivatives are not unique—if F(x)F(x) is an antiderivative, so is F(x)+CF(x) + C for any constant CC
  • The "+ C" matters for indefinite integrals but cancels out in definite integral evaluation since (F(b)+C)(F(a)+C)=F(b)F(a)(F(b) + C) - (F(a) + C) = F(b) - F(a)

Indefinite Integral Notation

  • Represents a family of functions—written as f(x)dx=F(x)+C\int f(x) \, dx = F(x) + C, where CC is the constant of integration
  • No bounds means no single answerindefinite integrals give you all possible antiderivatives
  • Essential for FTC Part 1 because you must first find an antiderivative before evaluating at the bounds

Compare: Definite vs. Indefinite Integrals—definite integrals have bounds and produce a number (the net signed area), while indefinite integrals have no bounds and produce a family of functions. Forgetting "+ C" on indefinite integrals is a common exam error.


Accumulation Functions

Accumulation functions are integral functions with a variable upper limit—they're central to Part 2 of the FTC and appear frequently in AP exam questions. These functions model how a quantity builds up as you move along an interval.

Defining Accumulation Functions

  • Standard form is F(x)=axf(t)dtF(x) = \int_a^x f(t) \, dt—this represents the accumulated "area" from aa to xx
  • Output is net signed area under f(t)f(t) from aa to xx; areas below the x-axis count as negative
  • Starting value F(a)=0F(a) = 0 always, since integrating from aa to aa gives zero area

Graphical Interpretation

  • F(x)F(x) increases where f(x)>0f(x) > 0—positive values of ff add to the accumulated total
  • F(x)F(x) decreases where f(x)<0f(x) < 0—negative values of ff subtract from the accumulated total
  • FF has extrema where ff crosses zero—since F(x)=f(x)F'(x) = f(x), zeros of ff are critical points of FF

Compare: Accumulation function F(x)F(x) vs. its integrand f(x)f(x)—when ff is positive, FF is increasing; when ff crosses from positive to negative, FF has a local maximum. This relationship is a favorite topic for graph-based FRQ questions.


Applications and Problem-Solving

The FTC isn't just theoretical—it's your primary tool for solving practical problems involving areas, accumulated quantities, and rates of change. Recognizing which application fits the problem is key to exam success.

Area Under Curves

  • Computes exact areas between a function and the x-axis over [a,b][a, b] using abf(x)dx=F(b)F(a)\int_a^b f(x) \, dx = F(b) - F(a)
  • Net vs. total area distinction—the integral gives net signed area; for total area, integrate f(x)|f(x)|
  • Geometric interpretation connects algebraic calculation to visual understanding of the curve's behavior

Real-World Modeling

  • Physics applications include displacement from velocity (v(t)dt\int v(t) \, dt) and work from force
  • Economics applications include total cost from marginal cost and consumer/producer surplus calculations
  • Biology applications include population growth from growth rates and drug concentration over time

Compare: Net signed area vs. total area—if f(x)f(x) dips below the x-axis, abf(x)dx\int_a^b f(x) \, dx gives net area (positive minus negative), while abf(x)dx\int_a^b |f(x)| \, dx gives total geometric area. Watch for FRQs that specifically ask for "total distance" vs. "displacement."


Quick Reference Table

ConceptKey Formula or Idea
FTC Part 1 (Evaluation)abf(x)dx=F(b)F(a)\int_a^b f(x) \, dx = F(b) - F(a)
FTC Part 2 (Derivative of Integral)ddxaxf(t)dt=f(x)\frac{d}{dx} \int_a^x f(t) \, dt = f(x)
Chain Rule Extensionddxag(x)f(t)dt=f(g(x))g(x)\frac{d}{dx} \int_a^{g(x)} f(t) \, dt = f(g(x)) \cdot g'(x)
Indefinite Integralf(x)dx=F(x)+C\int f(x) \, dx = F(x) + C
Accumulation FunctionF(x)=axf(t)dtF(x) = \int_a^x f(t) \, dt with F(a)=0F(a) = 0
Inverse RelationshipDifferentiation and integration undo each other
Continuity Requirementff must be continuous on the interval for FTC to apply

Self-Check Questions

  1. If F(x)=2x(t34t)dtF(x) = \int_2^x (t^3 - 4t) \, dt, what is F(x)F'(x), and at what values of xx does FF have critical points?

  2. Compare and contrast: How does evaluating 03x2dx\int_0^3 x^2 \, dx using FTC Part 1 differ from finding ddx0xt2dt\frac{d}{dx} \int_0^x t^2 \, dt? What does each calculation tell you?

  3. An accumulation function G(x)=0xf(t)dtG(x) = \int_0^x f(t) \, dt is increasing on (1,4)(1, 4) and decreasing on (4,7)(4, 7). What can you conclude about f(x)f(x) on these intervals?

  4. Which part of the FTC would you use to find ddx1x2sin(t)dt\frac{d}{dx} \int_1^{x^2} \sin(t) \, dt, and what additional rule must you apply?

  5. Explain why the constant of integration CC appears in indefinite integrals but doesn't affect the value of definite integrals. How does this connect to the FTC?