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Fundamental Calculus Formulas

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Why This Matters

Calculus is the mathematical language of change, and in the physical sciences, everything changes—particles move, waves oscillate, populations grow, and energy transforms. You're being tested not just on whether you can apply these formulas mechanically, but on whether you understand when and why each rule applies. The differentiation rules tell you how quantities change instantaneously, while integration connects those rates back to accumulated totals.

These formulas fall into distinct categories: basic building blocks, combination rules, special functions, and the bridge between derivatives and integrals. Don't just memorize the formulas in isolation—know which rule handles which situation. When you see a product of functions, your brain should immediately flag the product rule. When you see a function inside another function, chain rule. That pattern recognition is what separates students who struggle on exams from those who breeze through them.


Basic Building Blocks

These are the foundation of all differentiation. Master these first, because every other rule builds on them. The derivative measures instantaneous rate of change—these rules tell you the rate of change for the simplest possible functions.

Derivative of a Constant

  • ddx(c)=0\frac{d}{dx}(c) = 0—constants don't change, so their rate of change is zero
  • Graphical interpretation: a horizontal line has zero slope everywhere
  • Physical meaning: if a quantity isn't varying with your independent variable, its derivative vanishes

Power Rule

  • ddx(xn)=nxn1\frac{d}{dx}(x^n) = nx^{n-1}—works for any real exponent, including negatives and fractions
  • Mechanism: bring down the exponent as a coefficient, then reduce the exponent by one
  • Applications: polynomial functions, root functions (x1/2x^{1/2}), and inverse powers (x1x^{-1})

Compare: Constant rule vs. Power rule—both handle simple terms, but the constant rule is actually the power rule with n=0n = 0 (since 0x1=00 \cdot x^{-1} = 0). Recognizing constants as a special case helps you see calculus as a unified system.


Combination Rules

When functions are combined through addition, multiplication, or division, these rules tell you how to break down the problem. The key insight: differentiation is linear for sums but requires special handling for products and quotients.

Sum Rule

  • ddx[f(x)+g(x)]=f(x)+g(x)\frac{d}{dx}[f(x) + g(x)] = f'(x) + g'(x)—differentiate term by term
  • Linearity property: this also works for differences and scalar multiples
  • Exam strategy: always simplify expressions into sums before differentiating when possible

Product Rule

  • ddx[f(x)g(x)]=f(x)g(x)+f(x)g(x)\frac{d}{dx}[f(x)g(x)] = f'(x)g(x) + f(x)g'(x)—"first times derivative of second, plus second times derivative of first"
  • Memory trick: each function gets a turn being differentiated while the other stays unchanged
  • Common errors: forgetting to include both terms—the derivative of a product is never just the product of derivatives

Quotient Rule

  • ddx[f(x)g(x)]=f(x)g(x)f(x)g(x)[g(x)]2\frac{d}{dx}\left[\frac{f(x)}{g(x)}\right] = \frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2}—"low d-high minus high d-low, over low squared"
  • Sign matters: the numerator has subtraction, not addition (unlike the product rule)
  • Alternative approach: rewrite as f(x)[g(x)]1f(x) \cdot [g(x)]^{-1} and use product rule with chain rule instead

Compare: Product rule vs. Quotient rule—both handle two-function combinations, but the quotient rule has a subtraction (order matters!) and a squared denominator. If you forget the quotient rule on an exam, you can always convert to a product and use the chain rule.


Composite Functions

When one function is nested inside another, you need the chain rule. This is arguably the most important rule for physical science applications, where quantities often depend on intermediate variables.

Chain Rule

  • ddx[f(g(x))]=f(g(x))g(x)\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)—derivative of outer times derivative of inner
  • Identification: look for "function of a function" structures like sin(x2)\sin(x^2) or e3xe^{3x}
  • Physical interpretation: connects rates through intermediate variables (if y depends on u, and u depends on x, how does y depend on x?)

Compare: Product rule vs. Chain rule—product rule handles f(x)g(x)f(x) \cdot g(x) (two separate functions multiplied), while chain rule handles f(g(x))f(g(x)) (one function inside another). Misidentifying which situation you're in is a top exam mistake.


Special Functions

These derivatives appear constantly in physical science applications. Exponential, logarithmic, and trigonometric functions model growth, decay, and oscillation—the three most common behaviors in nature.

Exponential Function

  • ddx(ex)=ex\frac{d}{dx}(e^x) = e^x—the only function that equals its own derivative
  • Why ee is special: this self-replicating property is why ee appears naturally in growth/decay problems
  • With chain rule: ddx(eu)=eududx\frac{d}{dx}(e^{u}) = e^{u} \cdot \frac{du}{dx}—don't forget the inner derivative

Natural Logarithm

  • ddx(lnx)=1x\frac{d}{dx}(\ln x) = \frac{1}{x}—the antiderivative of 1x\frac{1}{x} is lnx\ln|x|
  • Inverse relationship: logarithms and exponentials are inverses, reflected in their derivative relationship
  • Domain restriction: only valid for x>0x > 0 (or use lnx\ln|x| for negative values)

Trigonometric Functions

  • ddx(sinx)=cosx\frac{d}{dx}(\sin x) = \cos x and ddx(cosx)=sinx\frac{d}{dx}(\cos x) = -\sin x—note the negative sign on cosine's derivative
  • Cyclic pattern: differentiating four times returns you to the original function
  • Physical applications: simple harmonic motion, wave equations, and anything oscillatory

Compare: exe^x vs. sinx\sin x—both are "self-referential" under differentiation (exe^x returns itself; sinx\sin x cycles through four derivatives). This is why both appear in solutions to differential equations describing physical systems.


The Bridge: Connecting Derivatives and Integrals

This theorem is the conceptual heart of calculus—it tells you that differentiation and integration are inverse operations.

Fundamental Theorem of Calculus

  • abf(x)dx=F(b)F(a)\int_a^b f(x)\,dx = F(b) - F(a) where F(x)=f(x)F'(x) = f(x)—evaluate the antiderivative at the bounds and subtract
  • Two-part theorem: Part 1 says integration and differentiation undo each other; Part 2 gives the evaluation formula
  • Physical meaning: the integral accumulates the rate of change to recover the total change in a quantity

Compare: Differentiation vs. Integration—differentiation finds instantaneous rates from accumulated quantities; integration finds accumulated quantities from instantaneous rates. FRQs often require you to move fluidly between both interpretations.


Quick Reference Table

ConceptKey Formulas
Basic derivativesConstant rule, Power rule
Linear combinationsSum rule (extends to differences and scalar multiples)
Products & quotientsProduct rule, Quotient rule
Composite functionsChain rule
Exponential & logarithmicddx(ex)=ex\frac{d}{dx}(e^x) = e^x, ddx(lnx)=1x\frac{d}{dx}(\ln x) = \frac{1}{x}
Trigonometricddx(sinx)=cosx\frac{d}{dx}(\sin x) = \cos x, ddx(cosx)=sinx\frac{d}{dx}(\cos x) = -\sin x
Integration connectionFundamental Theorem of Calculus
Most common exam errorsForgetting chain rule, sign errors in quotient rule

Self-Check Questions

  1. Which two rules both involve handling combinations of functions, but one uses addition in its formula while the other uses subtraction? What's the key structural difference between when you'd use each?

  2. You need to differentiate ex2e^{x^2}. Which rules do you need, and in what order do you apply them?

  3. Compare and contrast: How are the derivatives of exe^x and sinx\sin x similar in their "self-referential" behavior? How do they differ?

  4. If you're given a velocity function v(t)v(t) and asked to find total displacement over an interval, which formula applies? What if you're given position x(t)x(t) and asked for instantaneous velocity?

  5. A classmate claims that ddx[sinxcosx]=cosx(sinx)\frac{d}{dx}[\sin x \cdot \cos x] = \cos x \cdot (-\sin x). Identify their error and provide the correct derivative.