🔦electrical circuits and systems ii review

I_s / i_p = n_p / n_s

Written by the Fiveable Content Team • Last updated September 2025
Written by the Fiveable Content Team • Last updated September 2025

Definition

The equation $$\frac{i_s}{i_p} = \frac{n_p}{n_s}$$ describes the relationship between the primary and secondary currents in a transformer and the number of turns on each coil. This fundamental principle shows how transformers can change voltage and current levels while maintaining power balance, which is crucial for understanding energy transfer in electrical circuits. The ratio of turns affects how much current is transformed, making this relationship vital for designing and analyzing transformer circuits.

5 Must Know Facts For Your Next Test

  1. In an ideal transformer, power is conserved, which means $$P_p = P_s$$ or $$V_p \cdot i_p = V_s \cdot i_s$$.
  2. If you increase the number of turns in the primary coil (n_p), the current in the primary (i_p) will decrease if voltage is constant, and vice versa for the secondary coil.
  3. The transformation ratio affects both voltage and current; if voltage increases, current decreases, keeping power constant.
  4. This equation highlights that a higher turn ratio results in lower current on the secondary side for a given primary current.
  5. Real transformers also account for losses like copper losses and core losses, but this basic equation helps simplify initial calculations.

Review Questions

  • How does the equation $$\frac{i_s}{i_p} = \frac{n_p}{n_s}$$ help explain the operation of a transformer?
    • This equation illustrates that the current ratio between the secondary (i_s) and primary (i_p) sides of a transformer is directly related to their respective turn ratios (n_p for primary and n_s for secondary). When designing transformers, knowing this relationship allows engineers to calculate how changes in turn ratios will impact current levels, which is essential for maintaining desired power outputs. By understanding this relationship, one can determine how to efficiently step up or step down voltage levels within electrical systems.
  • In what ways does this equation relate to practical transformer applications in electrical engineering?
    • In practical applications, understanding the relationship given by $$\frac{i_s}{i_p} = \frac{n_p}{n_s}$$ is vital for designing transformers that fit specific load requirements. For example, when stepping up voltage for transmission over long distances, engineers use this equation to ensure that secondary current remains manageable. Additionally, it aids in calculating wire gauge sizes and thermal management due to varying current levels, ensuring safety and efficiency in electrical networks.
  • Evaluate how neglecting losses in a transformer impacts your calculations based on $$\frac{i_s}{i_p} = \frac{n_p}{n_s}$$.
    • Neglecting losses such as copper losses or core losses can lead to overly optimistic calculations regarding efficiency based on $$\frac{i_s}{i_p} = \frac{n_p}{n_s}$$. This oversight may result in designing transformers that do not operate as expected under load conditions. For example, if real-world losses are not accounted for, one might assume perfect power transfer while actual performance could be significantly lower, affecting system reliability. Understanding these practical considerations alongside the equation is crucial for accurate engineering outcomes.
I_s / i_p = n_p / n_s Definition - Electrical Circuits and Systems II Key Term | Fiveable