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AP Calculus AB/BC Unit 2 Review: Fundamentals of Differentiation

  • 10–12% of AP multiple choice
  • 10 topics
  • AP exam review verified for 2027

The derivative f'(x) is the limit of the difference quotient as h approaches 0. Unit 2 gives you the rules to compute that limit efficiently without returning to the definition every time: the Power Rule, constant and sum rules, Product Rule, Quotient Rule, and the standard derivatives of sin x, cos x, e^x, ln x, tan x, cot x, sec x, and csc x.

Fiveable's AP Calculus AB/BC Unit 2 review covers 10 topics, with guided practice questions for the unit.

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AP Calculus AB/BC unit 2 topics

2.5

Applying the Power Rule

Introduces d/dx(x^r) = r*x^(r-1) for all real r, including negative and fractional exponents, and emphasizes rewriting radicals and denominators as powers before differentiating.

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2.8

The Product Rule

Covers d/dx(f*g) = f'g + fg' with worked examples involving polynomial-trig and exponential-polynomial products, and addresses the common error of multiplying derivatives directly.

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2.9

The Quotient Rule

Covers d/dx(f/g) = (gf' - fg')/g^2, emphasizes the fixed subtraction order, and applies the rule to rational functions and trig ratios.

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Practice AP Calculus AB/BC unit 2 questions

Try AP-style questions on unit 2, then use the review notes below for anything you miss.

Example AP-style MCQs

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MCQ

AP-style practice question

Question

Given g(x)=∣x−3∣g(x) = |x - 3|, determine whether g′(3)g'(3) exists using the definition of the derivative.

Check that lim⁡x→3g(x)=g(3)\lim_{x \to 3} g(x) = g(3); continuity guarantees differentiability at x=3x = 3

Calculate g(b)−g(a)b−a\frac{g(b) - g(a)}{b - a} for points near x=3x = 3; constant values prove g′(3)g'(3) exists

Verify that gg is defined in a neighborhood of x=3x = 3; local definition ensures g′(3)g'(3) exists

Evaluate lim⁡h→0g(3+h)−g(3)h\lim_{h \to 0} \frac{g(3+h) - g(3)}{h} from both sides; unequal limits mean g′(3)g'(3) does not exist

MCQ

AP-style practice question

Question

Consider g(x)=4(3x3−2x)g(x) = 4(3x^3 - 2x). Which rule should be applied first to find g′(x)g'(x)?

Power Rule — because you must differentiate 3x33x^3 and −2x-2x individually before factoring out the constant 4

Constant Multiple Rule — because 4 is a constant, but you should apply it AFTER using the Sum Rule on the terms inside the parentheses

Constant Multiple Rule — because 4 multiplies the entire expression (3x3−2x)(3x^3 - 2x)

Constant Multiple Rule — because the coefficient 3 in 3x33x^3 is a constant that multiplies a power of xx

Example FRQs

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FRQ

Cyclist distance and instantaneous speed over time

1. A cyclist rides along a straight path. The function DD models the distance, in kilometers, the cyclist has traveled from the starting point tt minutes after the ride begins, for 0≤t≤300 ≤ t ≤ 30. Selected values of D(t)D(t) are given in the table in Figure 1. It can be shown that for 0≤t≤300 ≤ t ≤ 30, D(t)=0.02t2+0.3tD(t) = 0.02t^2 + 0.3t is a model that fits these values, and DD is differentiable on this interval.

Table 1. Selected values of D(t)

Table 1
A.

Use the data in Figure 1 to find the average rate of change of DD over the interval 10≤t≤2010 ≤ t ≤ 20. Show the work that leads to your answer, and include units of measure.

B.

Write a limit expression that represents D′(15)D'(15). Then use the model D(t)=0.02t2+0.3tD(t) = 0.02t^2 + 0.3t to find D′(15)D'(15), and write an equation for the line tangent to the graph of DD at t=15t = 15. Show the setup for your calculations.

C.

Using the data in Figure 1, estimate D′(20)D'(20) using the average rate of change over the interval 15≤t≤2515 ≤ t ≤ 25. Then find the value of D′(20)D'(20) from the model and find the absolute difference between the two values. Show the setup for your calculations.

D.

A new function GG is defined by G(t)=t⋅D(t)G(t) = t ·D(t) for 0≤t≤300 ≤ t ≤ 30. Find G′(10)G'(10). Show the setup for your calculations.

FRQ

Polynomial rates of change and tangent lines

3. The function ff is defined by f(x)=x3−4x+1f(x)=x^3-4x+1 for all real numbers xx. Selected values of ff are given in the table shown.

xx

f(x)f(x)

−1-1

44

00

11

11

−2-2

22

11

A.

Find the average rate of change of ff over the interval −1≤x≤1-1 ≤ x ≤ 1. Show the work that leads to your answer.

B.

Write an expression for f′(2)f'(2) as a limit of a difference quotient. Do not evaluate the limit.

C.

Find the equation of the line tangent to the graph of ff at x=1x=1. Show the work that leads to your answer.

D.

A new function gg is defined by g(x)=x2+1f(x)g(x)=\dfrac{x^2+1}{f(x)} for x≠1x ≠ 1. Find g′(0)g'(0). Show the work that leads to your answer. In addition, explain why gg is continuous at x=0x=0. The new function is g(x)=x2+1f(x)g(x)=\dfrac{x^2+1}{f(x)}, where f(x)=x3−4x+1f(x)=x^3-4x+1.

Unit 2 review notes

2.1

Defining the Derivative from Average to Instantaneous Rate of Change

The average rate of change of f on [a, b] is (f(b) - f(a))/(b - a), which equals the slope of the secant line through those two points. The instantaneous rate of change at x = a is the limit of that quotient as the interval collapses: f'(a) = lim(h to 0) (f(a+h) - f(a))/h. The derivative function f'(x) extends this to every point in the domain. The slope of the tangent line at x = a equals f'(a), and the tangent line equation uses point-slope form: y - f(a) = f'(a)(x - a).

  • Average rate of change: (f(b) - f(a))/(b - a); slope of the secant line between (a, f(a)) and (b, f(b)).
  • Limit definition of the derivative: f'(a) = lim(h to 0) (f(a+h) - f(a))/h, or equivalently lim(x to a) (f(x) - f(a))/(x - a).
  • Derivative function: f'(x) = lim(h to 0) (f(x+h) - f(x))/h; gives the instantaneous rate of change at every x in the domain.
  • Derivative notation: f'(x), y', and dy/dx all represent the same derivative; choose notation to match the problem context.
  • Tangent line: The line through (a, f(a)) with slope f'(a); equation is y - f(a) = f'(a)(x - a).

Given f(x) = x^2, use the limit definition to show f'(3) = 6, then write the equation of the tangent line at x = 3.

ConceptFormulaGeometric meaning
Average rate of change(f(b)-f(a))/(b-a)Slope of secant line
Instantaneous rate of changelim(h to 0)(f(a+h)-f(a))/hSlope of tangent line
Derivative functionlim(h to 0)(f(x+h)-f(x))/hSlope function for all x
2.3

Estimating Derivatives from Tables and Graphs

When you cannot compute a derivative algebraically, estimate it using nearby data. From a table, use the symmetric difference quotient (f(a+h) - f(a-h))/(2h) when interior values are available, or a one-sided quotient at endpoints. From a graph, estimate the slope of the tangent line by reading rise over run between two close points. Always include units when the context provides them.

  • Symmetric difference quotient: (f(a+h) - f(a-h))/(2h); generally the most accurate table-based estimate for f'(a) at interior points.
  • One-sided estimate: Use (f(a+h) - f(a))/h or (f(a) - f(a-h))/h when only one neighboring value is available, such as at a table endpoint.
  • Graphical estimation: Read two nearby points on the curve and compute slope; the closer the points, the better the approximation of the tangent slope.

A table gives f(2) = 5, f(3) = 8, f(4) = 13. Estimate f'(3) using the symmetric difference quotient.

MethodFormulaBest used when
Symmetric difference quotient(f(a+h)-f(a-h))/(2h)Interior table point with equal spacing
Forward difference quotient(f(a+h)-f(a))/hLeft endpoint or only right neighbor available
Backward difference quotient(f(a)-f(a-h))/hRight endpoint or only left neighbor available
2.4

Differentiabil­ity and Continuity

Differentiability implies continuity: if f is differentiable at x = a, it must be continuous there. The converse is false. A function can be continuous at a point but still fail to be differentiable. The four main failure cases are corners, cusps, vertical tangents, and discontinuities. To justify non-differentiability on the AP exam, name the specific reason rather than just identifying the point.

  • Differentiable implies continuous: If f'(a) exists, then f is continuous at a. Contrapositive: if f is discontinuous at a, then f is not differentiable at a.
  • Corner: Left-hand and right-hand difference quotient limits both exist but are not equal; example: f(x) = |x| at x = 0.
  • Vertical tangent: The difference quotient limit is infinite; example: f(x) = x^(1/3) at x = 0, where the slope grows without bound.
  • Cusp: One-sided difference quotient limits are infinite with opposite signs; the graph has a sharp point with infinite steepness.
  • Discontinuity: Any jump, removable, or infinite discontinuity at a point prevents differentiability there.

Explain why f(x) = |x - 2| is continuous but not differentiable at x = 2. Compute the left-hand and right-hand difference quotient limits to support your answer.

Failure typeExampleOne-sided limits of difference quotient
Corner|x| at x=0Left: -1, Right: +1 (unequal, both finite)
Vertical tangentx^(1/3) at x=0Both approach infinity
DiscontinuityPiecewise jump at x=aAt least one limit does not match function value
2.5

Power Rule and Algebraic Derivative Rules

The Power Rule states d/dx(x^r) = r*x^(r-1) for any real number r. It applies to integer, negative, and fractional exponents, so rewrite radicals and denominators as powers before differentiating. The constant rule, sum rule, difference rule, and constant multiple rule let you differentiate any polynomial term by term. The derivative of a constant is zero; a constant factor pulls out front.

  • Power Rule: d/dx(x^r) = r*x^(r-1); works for all real r, including r = 1/2 (square root) and r = -1 (reciprocal).
  • Constant rule: d/dx(c) = 0 for any constant c.
  • Constant multiple rule: d/dx(cf(x)) = cf'(x); the constant factor is preserved.
  • Sum and difference rules: d/dx(f(x) +/- g(x)) = f'(x) +/- g'(x); differentiate term by term.
  • Rewriting before differentiating: Convert sqrt(x) to x^(1/2) and 1/x^2 to x^(-2) before applying the Power Rule to avoid errors.

Find the derivative of f(x) = 3x^4 - 5x^(1/2) + 7x^(-1) + 9 using the Power Rule and algebraic rules.

RuleFormulaExample
Power Ruled/dx(x^r) = r*x^(r-1)d/dx(x^5) = 5x^4
Constant Multipled/dx(c*f) = c*f'd/dx(4x^3) = 12x^2
Sum/Differenced/dx(f +/- g) = f' +/- g'd/dx(x^2 + x) = 2x + 1
Constantd/dx(c) = 0d/dx(7) = 0
2.7

Derivatives of sin x, cos x, e^x, and ln x

Four essential derivatives must be memorized: d/dx(sin x) = cos x, d/dx(cos x) = -sin x, d/dx(e^x) = e^x, and d/dx(ln x) = 1/x. The negative sign on the cosine derivative is the most common source of errors. The self-derivative property of e^x is unique among functions. These can be combined with sum, difference, and constant multiple rules. A secondary skill from this topic is recognizing a limit expression as a derivative definition and evaluating it using a known derivative.

  • d/dx(sin x) = cos x: Derived from the limit definition using the sine addition formula and the special limits lim(sin h/h) = 1 and lim((1-cos h)/h) = 0.
  • d/dx(cos x) = -sin x: The negative sign is essential; forgetting it is one of the most common errors on trig derivative problems.
  • d/dx(e^x) = e^x: The exponential function e^x is its own derivative; this property defines e and makes it central to differential equations.
  • d/dx(ln x) = 1/x: Valid for x > 0; derived using the inverse function relationship between e^x and ln x.
  • Limit-as-derivative recognition: If a limit matches the form lim(h to 0)(f(a+h)-f(a))/h, evaluate it as f'(a) using a known derivative instead of computing the limit directly.

Evaluate lim(h to 0) (sin(pi/6 + h) - sin(pi/6))/h by recognizing it as a derivative, then confirm by differentiating sin x directly.

FunctionDerivativeKey note
sin xcos xPositive; use radian measure
cos x-sin xNegative sign required
e^xe^xSelf-derivative; unique to e
ln x1/xDomain x > 0
2.8

Product Rule and Quotient Rule

When two differentiable functions are multiplied, use the Product Rule: d/dx(fg) = f'g + fg'. When one differentiable function is divided by another, use the Quotient Rule: d/dx(f/g) = (gf' - f*g')/g^2. The subtraction order in the Quotient Rule is fixed; reversing it changes the sign of the answer. Neither rule allows you to simply multiply or divide the individual derivatives.

  • Product Rule: d/dx(f*g) = f'g + fg'; first times derivative of second, plus second times derivative of first.
  • Quotient Rule: d/dx(f/g) = (gf' - fg')/g^2; denominator times derivative of numerator minus numerator times derivative of denominator, all over denominator squared.
  • Order matters in Quotient Rule: gf' - fg' is not the same as fg' - gf'; always put the denominator function first in the numerator of the formula.
  • When to use each rule: Product Rule for expressions written as a product; Quotient Rule for explicit fractions. Rewriting a quotient as a product with a negative exponent and using the Product Rule is an alternative.

Differentiate h(x) = x^2 * sin x using the Product Rule, then differentiate k(x) = e^x / (x^2 + 1) using the Quotient Rule.

RuleFormulaCommon error
Product Rule(fg)' = f'g + fg'Multiplying f' and g' instead of using the formula
Quotient Rule(f/g)' = (gf' - fg')/g^2Reversing subtraction order or forgetting to square the denominator
2.10

Derivatives of tan x, cot x, sec x, and csc x

The four remaining trig derivatives follow from rewriting each function as a ratio of sin x and cos x and applying the Quotient Rule. The results are: d/dx(tan x) = sec^2 x, d/dx(cot x) = -csc^2 x, d/dx(sec x) = sec x * tan x, d/dx(csc x) = -csc x * cot x. The negative signs on cot x and csc x derivatives are the most frequently missed details. All four require radian measure.

  • d/dx(tan x) = sec^2 x: Derived by applying the Quotient Rule to sin x / cos x; uses the identity sin^2 x + cos^2 x = 1 to simplify.
  • d/dx(cot x) = -csc^2 x: Derived from cos x / sin x via the Quotient Rule; the negative sign is required.
  • d/dx(sec x) = sec x * tan x: Derived from 1/cos x using the reciprocal or Quotient Rule.
  • d/dx(csc x) = -csc x * cot x: Derived from 1/sin x; the negative sign is required and often forgotten.
  • Derivation strategy: Rewrite tan x = sin x/cos x, cot x = cos x/sin x, sec x = 1/cos x, csc x = 1/sin x, then apply the Quotient Rule to derive each formula rather than memorizing without understanding.

Derive d/dx(tan x) = sec^2 x by applying the Quotient Rule to sin x / cos x. Then state d/dx(sec x) and d/dx(csc x) from memory.

FunctionRewriteDerivative
tan xsin x / cos xsec^2 x
cot xcos x / sin x-csc^2 x
sec x1 / cos xsec x * tan x
csc x1 / sin x-csc x * cot x

Key terms

TermDefinition
Average Rate of ChangeThe slope of the secant line between two points on f, computed as (f(b)-f(a))/(b-a) over the interval [a, b].
Difference QuotientThe expression (f(a+h)-f(a))/h that measures average rate of change; its limit as h approaches 0 defines the derivative.
Instantaneous Rate of ChangeThe derivative f'(a), equal to lim(h to 0)(f(a+h)-f(a))/h; represents the slope of the tangent line at x = a.
Secant LineA line through two points on a curve whose slope equals the average rate of change of the function over that interval.
Tangent LineThe line through (a, f(a)) with slope f'(a); it represents the best linear approximation to the curve at that point.
Slope of the Tangent LineThe value of the derivative f'(a) at a specific point; it equals the instantaneous rate of change of f at x = a.
f(x)Prime notation for the derivative function; gives the instantaneous rate of change of f at any x in its domain.
DifferentiableA function is differentiable at x = a if the limit definition of the derivative exists there; differentiability implies continuity but not vice versa.
Vertical Tangent LineOccurs when the difference quotient limit is infinite at a point, such as for f(x) = x^(1/3) at x = 0; the derivative does not exist there.
Constant Multiple Ruled/dx(c*f(x)) = c*f'(x); a constant factor is preserved when differentiating.
Sum Ruled/dx(f(x) + g(x)) = f'(x) + g'(x); derivatives of a sum split term by term.
Difference Ruled/dx(f(x) - g(x)) = f'(x) - g'(x); derivatives of a difference split term by term.
Exponential FunctionFor the base e, d/dx(e^x) = e^x; the exponential function e^x is its own derivative, a property unique to this base.

How to review unit 2

Topics students miss most

Miss rates come from Fiveable multiple-choice practice.

Common unit 2 mistakes

Forgetting the negative sign on d/dx(cos x) and d/dx(cot x) and d/dx(csc x)

d/dx(cos x) = -sin x, d/dx(cot x) = -csc^2 x, and d/dx(csc x) = -csc x*cot x all carry a negative sign. The sine and tangent derivatives are positive; the cosine, cotangent, and cosecant derivatives are negative. Mixing these up is one of the most frequent errors on trig differentiation problems.

Multiplying derivatives instead of using the Product Rule

d/dx(f*g) is not f'*g'. The correct formula is f'g + fg'. Always write both terms before simplifying, especially when one factor is a trig or exponential function.

Reversing the subtraction order in the Quotient Rule

The numerator of the Quotient Rule is gf' - fg', not fg' - gf'. Reversing the order changes the sign of the entire derivative. A mnemonic like 'low d-high minus high d-low over low squared' can help keep the order straight.

Applying the Power Rule to expressions not yet in power form

The Power Rule requires the form x^r. Rewrite sqrt(x) as x^(1/2) and 1/x^3 as x^(-3) before differentiating. Applying the rule directly to radical or fraction notation without rewriting leads to incorrect exponents.

Concluding that a continuous function is differentiable

Continuity at a point does not guarantee differentiability. f(x) = |x| is continuous everywhere but not differentiable at x = 0. Always check for corners, cusps, or vertical tangents before claiming a derivative exists.

How this unit shows up on the AP exam

Limit-as-derivative recognition in multiple choice

A common multiple-choice task presents a limit expression such as lim(h to 0)(cos(pi/3 + h) - cos(pi/3))/h and asks for its value. The skill is recognizing the expression as f'(a) for a known function and evaluating it using the appropriate derivative formula rather than computing the limit from scratch. This tests whether you understand the definition of the derivative, not just the shortcut rules.

Justifying differentiability in free response

Free-response problems involving piecewise functions often ask whether the function is differentiable at a join point. A complete response requires checking continuity first, then showing that the left-hand and right-hand difference quotient limits are equal. Stating only that the function looks smooth is not sufficient; you must show the one-sided derivative limits and confirm they match.

Multi-rule differentiation and tangent line equations

Both multiple-choice and free-response problems frequently ask you to differentiate a function that requires combining two or more rules (for example, the Product Rule applied to a polynomial and a trig function), then evaluate the derivative at a specific point to write a tangent line equation. Showing organized step-by-step work and using correct notation throughout is expected in free-response scoring.

More ways to review

Topic study guides

Open the individual guides for Unit 2 when you want a closer review of one topic.

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Practice questions

Use AP-style practice after you review the notes so you can check what you understand.

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FRQ practice

Practice free-response reasoning and compare your answer with scoring guidance.

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Cram archive videos

Watch past review streams filtered to Unit 2 when you want a video walkthrough.

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Official unit cheatsheet

Open the Fiveable one-page unit review, then explore visual cheatsheets for a quick refresher.

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Score calculator

Estimate your broader AP score goal after you review the course and exam format.

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Frequently Asked Questions

What's on the AP Calc Unit 2 progress check (MCQ and FRQ)?

The AP Calc Unit 2 progress check in AP Classroom includes both MCQ and FRQ parts drawn from all 10 topics in the unit. MCQ questions typically test the Power Rule, Product Rule, Quotient Rule, derivatives of sin x, cos x, e^x, and ln x, and identifying where derivatives do not exist. FRQ parts ask you to apply derivative rules and interpret instantaneous rates of change in context. For the progress check, focus especially on Topics 2.4 through 2.10, since those cover the computational rules most frequently tested. You can find matched practice problems at AP Calc Unit 2.

How do I practice AP Calc Unit 2 FRQs?

AP Calc Unit 2 FRQs most often ask you to find a derivative using the Power Rule, Product Rule, or Quotient Rule, or to interpret an instantaneous rate of change in a real-world context. To practice, work through problems that require you to write out full derivative notation, show each rule step clearly, and explain what a derivative value means in context, since partial credit depends on clear reasoning. Good practice steps:
1. Drill Topics 2.5-2.9 (the core rules) until the algebra is automatic.
2. Practice writing answers using both f'(x) and dy/dx notation (Topic 2.2).
3. Review differentiability conditions (Topic 2.4) since FRQs sometimes ask you to justify why a derivative does or does not exist. Find FRQ-style practice at AP Calc Unit 2.

Where can I find AP Calc Unit 2 practice questions?

The best place to find AP Calc Unit 2 practice questions, including multiple-choice and practice test problems, is AP Calc Unit 2. That page has resources covering all 10 topics, from the limit definition of the derivative through the Product Rule, Quotient Rule, and trig derivatives. For MCQ practice, focus on problems that mix the Power Rule with Product and Quotient Rule applications, since those combinations appear most often.

How should I study AP Calc Unit 2?

Start AP Calc Unit 2 by making sure you understand the limit definition of the derivative (Topic 2.2) before moving to the shortcut rules, since exam questions sometimes ask you to use the definition directly. Then build your rule fluency in order: Power Rule, then Constant and Sum rules, then Product and Quotient Rules, then trig and exponential derivatives. A practical study plan:
1. Memorize the derivatives of sin x, cos x, e^x, ln x, and the six trig functions (Topics 2.7 and 2.10) as a set.
2. Practice the Product and Quotient Rules (Topics 2.8-2.9) with messy expressions so the algebra doesn't slow you down on the exam.
3. Review Topic 2.4 on differentiability and continuity, since it's a common MCQ trap.
4. Do timed mixed practice sets that combine multiple rules in one problem. All study resources for this unit are at AP Calc Unit 2.

Ready to review Unit 2?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.