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๐Ÿ“˜Intermediate Algebra Unit 2 Review

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2.3 Solve a Formula for a Specific Variable

2.3 Solve a Formula for a Specific Variable

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
๐Ÿ“˜Intermediate Algebra
Unit & Topic Study Guides

Solving Formulas for Specific Variables

Solving a formula for a specific variable means rearranging the equation so that one particular variable stands alone on one side. This is the same process you use to solve regular equations, just applied to formulas that have multiple variables instead of numbers.

How to Isolate a Specific Variable

The core idea: treat every other variable like a number, then use inverse operations to get your target variable by itself.

Steps to solve a formula for a specific variable:

  1. Identify which variable you're solving for.
  2. If needed, distribute any coefficients or negative signs to clear parentheses.
  3. Use addition or subtraction to move all terms without your target variable to the other side.
  4. Use multiplication or division to remove any coefficient on your target variable.
  5. Never divide by zero (or by an expression that could equal zero).

Example: Solve P=2l+2wP = 2l + 2w for ll.

  1. Subtract 2w2w from both sides: Pโˆ’2w=2lP - 2w = 2l

  2. Divide both sides by 2: Pโˆ’2w2=l\frac{P - 2w}{2} = l

That's it. You've isolated ll. The key is that ww, PP, and 22 all get treated like numbers you can move around.

The same balancing rule from solving regular equations applies here: whatever you do to one side, you must do to the other.

Isolation of specific variables, Solve a Formula for a Specific Variable ยท Intermediate Algebra

Geometric Formulas You Should Know

You'll often be asked to take a standard geometric formula and solve it for a different variable than usual. Here are the common ones:

Area formulas:

  • Rectangle: A=lwA = lw
  • Triangle: A=12bhA = \frac{1}{2}bh
  • Circle: A=ฯ€r2A = \pi r^2

Perimeter and circumference:

  • Rectangle: P=2l+2wP = 2l + 2w
  • Circle: C=2ฯ€rC = 2\pi r

Volume formulas:

  • Rectangular prism: V=lwhV = lwh
  • Cylinder: V=ฯ€r2hV = \pi r^2 h

Example: Solve the cylinder volume formula V=ฯ€r2hV = \pi r^2 h for hh.

  1. You want hh alone, and it's being multiplied by ฯ€r2\pi r^2.
  2. Divide both sides by ฯ€r2\pi r^2: Vฯ€r2=h\frac{V}{\pi r^2} = h

Once you have the rearranged formula, you can plug in known values to find the unknown quantity.

Isolation of specific variables, Multi-Step Equations | Intermediate Algebra

Unit Conversion

Unit conversion means rewriting a measurement in a different unit without changing the actual quantity. You do this by multiplying by a conversion factor, which is a fraction equal to 1 where the numerator and denominator represent the same amount in different units.

How to Convert Units

  1. Identify your starting unit and your target unit.
  2. Find the conversion factor that relates them. Write it as a fraction with the target unit on top and the starting unit on the bottom.
  3. Multiply your original measurement by the conversion factor. The starting unit cancels out, leaving the target unit.
  4. Simplify and round as needed.

Example: Convert 5 feet to inches.

The conversion factor is 12ย inches1ย foot\frac{12 \text{ inches}}{1 \text{ foot}}. Multiply:

5ย ftร—12ย in1ย ft=60ย in5 \text{ ft} \times \frac{12 \text{ in}}{1 \text{ ft}} = 60 \text{ in}

The "ft" cancels, and you're left with inches.

Common Conversions to Know

  • Length: 1 foot = 12 inches, 1 yard = 3 feet, 1 mile = 5,280 feet
  • Volume: 1 cup = 8 fluid ounces, 1 pint = 2 cups, 1 quart = 2 pints, 1 gallon = 4 quarts
  • Mass: 1 pound = 16 ounces, 1 ton = 2,000 pounds

For multi-step conversions (like converting inches to yards), just chain conversion factors together. This approach is called dimensional analysis, and it works because each fraction equals 1, so you're never changing the actual value.