Multivariable Calculus

5️⃣Multivariable Calculus Unit 7 – Surface Integrals & Stokes' Theorem

Surface integrals and Stokes' theorem are powerful tools in multivariable calculus. They allow us to analyze complex three-dimensional surfaces and vector fields, extending the concepts of line integrals to higher dimensions. These techniques have wide-ranging applications in physics and engineering. From calculating electric flux in electromagnetics to analyzing fluid flow in aerodynamics, surface integrals and Stokes' theorem provide essential mathematical frameworks for understanding real-world phenomena.

Got a Unit Test this week?

we crunched the numbers and here's the most likely topics on your next test

Key Concepts

  • Surface integrals extend the concept of line integrals to surfaces in three-dimensional space
  • Surfaces can be parametrized using two variables, typically denoted as uu and vv
  • The surface integral of a scalar function f(x,y,z)f(x, y, z) over a surface SS is denoted as Sf(x,y,z)dS\iint_S f(x, y, z) dS
  • The surface integral of a vector field F(x,y,z)\mathbf{F}(x, y, z) over a surface SS is denoted as SFdS\iint_S \mathbf{F} \cdot d\mathbf{S} or SF×dS\iint_S \mathbf{F} \times d\mathbf{S}
    • FdS\mathbf{F} \cdot d\mathbf{S} represents the flux of F\mathbf{F} through the surface SS
    • F×dS\mathbf{F} \times d\mathbf{S} represents the circulation of F\mathbf{F} along the surface SS
  • Stokes' theorem relates the surface integral of the curl of a vector field over a surface to the line integral of the vector field along the boundary of the surface
  • Stokes' theorem is a generalization of Green's theorem to three-dimensional space

Geometric Interpretation

  • Surface integrals can be visualized as the sum of the values of a function over a surface, similar to how line integrals sum values along a curve
  • The surface integral of a scalar function f(x,y,z)f(x, y, z) can be interpreted as the volume under the surface z=f(x,y)z = f(x, y) above the xyxy-plane
  • The flux of a vector field F\mathbf{F} through a surface SS represents the amount of "flow" of F\mathbf{F} through SS
    • Positive flux indicates flow in the direction of the surface normal, while negative flux indicates flow opposite to the surface normal
  • The circulation of a vector field F\mathbf{F} along a surface SS measures the tendency of F\mathbf{F} to rotate around the surface
  • Stokes' theorem relates the circulation of a vector field along the boundary of a surface to the flux of the curl of the vector field through the surface
    • This can be visualized as the net flow around the boundary being equal to the total "swirling" of the vector field within the surface

Types of Surface Integrals

  • Scalar surface integrals: Sf(x,y,z)dS\iint_S f(x, y, z) dS
    • Integrate a scalar function f(x,y,z)f(x, y, z) over a surface SS
    • Can be used to find the area of a surface by setting f(x,y,z)=1f(x, y, z) = 1
  • Vector surface integrals of the first kind (flux): SFdS\iint_S \mathbf{F} \cdot d\mathbf{S}
    • Integrate the dot product of a vector field F\mathbf{F} with the surface normal dSd\mathbf{S}
    • Measures the flux of F\mathbf{F} through the surface SS
  • Vector surface integrals of the second kind (circulation): SF×dS\iint_S \mathbf{F} \times d\mathbf{S}
    • Integrate the cross product of a vector field F\mathbf{F} with the surface normal dSd\mathbf{S}
    • Measures the circulation of F\mathbf{F} along the surface SS
  • Surface integrals can be evaluated over parametric surfaces, where the surface is defined by a vector-valued function r(u,v)\mathbf{r}(u, v)

Calculating Surface Integrals

  • To evaluate a surface integral, parametrize the surface using a vector-valued function r(u,v)=(x(u,v),y(u,v),z(u,v))\mathbf{r}(u, v) = (x(u, v), y(u, v), z(u, v))
  • Compute the partial derivatives ru\mathbf{r}_u and rv\mathbf{r}_v
  • Calculate the cross product ru×rv\mathbf{r}_u \times \mathbf{r}_v to find the surface normal vector n\mathbf{n}
    • The magnitude of ru×rv\mathbf{r}_u \times \mathbf{r}_v gives the surface area element dSdS
  • Substitute the parametrization into the integrand and evaluate the integral using the surface area element dSdS
    • For scalar surface integrals: Sf(x,y,z)dS=Df(r(u,v))ru×rvdudv\iint_S f(x, y, z) dS = \iint_D f(\mathbf{r}(u, v)) \|\mathbf{r}_u \times \mathbf{r}_v\| du dv
    • For vector surface integrals of the first kind: SFdS=DF(r(u,v))(ru×rv)dudv\iint_S \mathbf{F} \cdot d\mathbf{S} = \iint_D \mathbf{F}(\mathbf{r}(u, v)) \cdot (\mathbf{r}_u \times \mathbf{r}_v) du dv
    • For vector surface integrals of the second kind: SF×dS=DF(r(u,v))×(ru×rv)dudv\iint_S \mathbf{F} \times d\mathbf{S} = \iint_D \mathbf{F}(\mathbf{r}(u, v)) \times (\mathbf{r}_u \times \mathbf{r}_v) du dv
  • Determine the limits of integration based on the parametrization and evaluate the resulting double integral

Stokes' Theorem

  • Stokes' theorem relates the surface integral of the curl of a vector field over a surface to the line integral of the vector field along the boundary of the surface
  • Mathematically, Stokes' theorem is stated as: S(×F)dS=CFdr\iint_S (\nabla \times \mathbf{F}) \cdot d\mathbf{S} = \oint_C \mathbf{F} \cdot d\mathbf{r}
    • SS is a smooth, orientable surface bounded by a simple, closed curve CC
    • F\mathbf{F} is a vector field defined on SS and CC
    • ×F\nabla \times \mathbf{F} is the curl of F\mathbf{F}
    • dSd\mathbf{S} is the surface area element, and drd\mathbf{r} is the line element along CC
  • Stokes' theorem allows for the conversion between surface integrals and line integrals, which can simplify calculations in certain situations
  • To apply Stokes' theorem, ensure that the surface is smooth, orientable, and bounded by a simple, closed curve
    • Choose the orientation of the surface normal consistent with the right-hand rule relative to the boundary curve orientation

Applications

  • Surface integrals have numerous applications in physics, engineering, and other fields
  • Flux calculations: Surface integrals can be used to calculate the flux of a vector field through a surface
    • Examples include electric flux in electromagnetism and fluid flow through a surface in fluid dynamics
  • Circulation calculations: Surface integrals can be used to calculate the circulation of a vector field along a surface
    • Examples include the circulation of a fluid along a surface in fluid dynamics and the circulation of an electromagnetic field in electromagnetism
  • Surface area calculations: Setting the integrand to 1 in a scalar surface integral yields the surface area of the given surface
  • Stokes' theorem can be used to simplify calculations by converting between surface integrals and line integrals
    • For example, calculating the work done by a force field along a closed path using a line integral instead of a surface integral

Common Pitfalls

  • Incorrectly parametrizing the surface, leading to incorrect surface normal vectors and surface area elements
  • Inconsistent orientation of the surface normal and boundary curve when applying Stokes' theorem
    • The orientation of the surface normal should follow the right-hand rule relative to the boundary curve orientation
  • Forgetting to include the magnitude of the cross product ru×rv\|\mathbf{r}_u \times \mathbf{r}_v\| as the surface area element when evaluating surface integrals
  • Misinterpreting the meaning of the flux and circulation integrals
    • Flux measures the flow through a surface, while circulation measures the tendency to rotate along a surface
  • Attempting to apply Stokes' theorem to non-smooth, non-orientable, or unbounded surfaces
  • Incorrectly calculating the curl of a vector field when applying Stokes' theorem
  • Mixing up the order of integration or the limits of integration when evaluating surface integrals

Practice Problems

  1. Evaluate the scalar surface integral S(x2+y2)dS\iint_S (x^2 + y^2) dS, where SS is the portion of the paraboloid z=x2+y2z = x^2 + y^2 that lies above the square 0x10 \leq x \leq 1, 0y10 \leq y \leq 1 in the xyxy-plane.

  2. Calculate the flux of the vector field F(x,y,z)=(x,y,z)\mathbf{F}(x, y, z) = (x, y, z) through the surface SS, which is the portion of the sphere x2+y2+z2=1x^2 + y^2 + z^2 = 1 that lies above the xyxy-plane.

  3. Evaluate the circulation of the vector field F(x,y,z)=(y,x,0)\mathbf{F}(x, y, z) = (y, -x, 0) along the surface of the cone z=x2+y2z = \sqrt{x^2 + y^2}, bounded by the plane z=1z = 1.

  4. Use Stokes' theorem to evaluate S(×F)dS\iint_S (\nabla \times \mathbf{F}) \cdot d\mathbf{S}, where F(x,y,z)=(x2,y2,z2)\mathbf{F}(x, y, z) = (x^2, y^2, z^2) and SS is the portion of the plane 2x+y+z=12x + y + z = 1 that lies in the first octant, oriented upward.

  5. Find the area of the surface z=sin(x)+cos(y)z = \sin(x) + \cos(y) over the region D={(x,y):0xπ,0yπ}D = \{(x, y) : 0 \leq x \leq \pi, 0 \leq y \leq \pi\}.

  6. Verify Stokes' theorem for the vector field F(x,y,z)=(y,x,0)\mathbf{F}(x, y, z) = (y, -x, 0) and the surface SS, which is the portion of the paraboloid z=1x2y2z = 1 - x^2 - y^2 that lies above the xyxy-plane, oriented upward.

  7. Calculate the flux of the vector field F(x,y,z)=(x,y,z)\mathbf{F}(x, y, z) = (x, y, z) through the surface SS, which is the portion of the cylinder x2+y2=1x^2 + y^2 = 1 bounded by the planes z=0z = 0 and z=2z = 2, oriented outward.

  8. Evaluate the surface integral S(x+y+z)dS\iint_S (x + y + z) dS, where SS is the surface of the tetrahedron with vertices at (0,0,0)(0, 0, 0), (1,0,0)(1, 0, 0), (0,1,0)(0, 1, 0), and (0,0,1)(0, 0, 1).



© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
Glossary
Glossary