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Molecular geometry isn't just about memorizing shapes—it's the foundation for understanding polarity, intermolecular forces, and reactivity throughout AP Chemistry. When you're asked why water has a high boiling point or why is nonpolar despite having polar bonds, you're really being tested on how electron pair repulsion, lone pair effects, and three-dimensional arrangement determine molecular behavior. These concepts connect directly to Unit 2's focus on compound structure and Unit 3's emphasis on how molecular shape influences physical properties like solubility and boiling point.
The key principle here is VSEPR theory (Valence Shell Electron Pair Repulsion): electron pairs around a central atom arrange themselves to minimize repulsion, and lone pairs repel more strongly than bonding pairs. This creates predictable distortions from ideal geometries. Don't just memorize that water is bent at 104.5°—understand why lone pairs compress bond angles and how that bent shape creates a dipole moment that explains water's remarkable properties.
When a central atom has only bonding pairs, electron groups spread out symmetrically to maximize distance from each other. These "ideal" geometries have predictable bond angles because there's no lone pair repulsion to distort them.
Compare: Linear vs. Trigonal Planar vs. Tetrahedral—all have no lone pairs, but bond angles decrease (180° → 120° → 109.5°) as more electron groups crowd around the central atom. If an FRQ asks you to explain bond angle trends, this progression is your go-to example.
Compare: Trigonal Bipyramidal vs. Octahedral—both are expanded geometries requiring d orbitals, but trigonal bipyramidal has non-equivalent positions (axial vs. equatorial) while octahedral positions are all equivalent. This distinction determines where lone pairs sit in derived geometries.
When lone pairs replace bonding pairs in a tetrahedral electron geometry, the molecular shape changes while bond angles compress. Lone pairs occupy more space than bonding pairs, pushing bonded atoms closer together.
Compare: Trigonal Pyramidal () vs. Bent ()—both derive from tetrahedral electron geometry, but adding a second lone pair compresses the bond angle further (107° → 104.5°). This is a classic FRQ comparison for demonstrating understanding of lone pair repulsion.
When lone pairs appear in a trigonal bipyramidal electron geometry, they always occupy equatorial positions first. Equatorial positions have only two 90° interactions (with axial groups), while axial positions have three 90° interactions—so lone pairs minimize repulsion by going equatorial.
Compare: Seesaw vs. T-Shaped vs. Linear (from trigonal bipyramidal)—all derive from the same electron geometry but have 1, 2, or 3 lone pairs respectively. Notice how adding lone pairs always removes equatorial bonding positions first, demonstrating the equatorial preference principle.
In octahedral electron geometry, all six positions are initially equivalent. When lone pairs are added, they position themselves to maximize distance from each other—going 180° apart when possible.
Compare: Square Planar () vs. Tetrahedral ()—both have four bonded atoms, but square planar has 90° angles (from octahedral electron geometry with 2 lone pairs) while tetrahedral has 109.5° angles (from tetrahedral electron geometry with 0 lone pairs). This is a frequently tested distinction!
| Concept | Best Examples |
|---|---|
| Ideal geometries (no lone pairs) | Linear (), Trigonal Planar (), Tetrahedral (), Octahedral () |
| Lone pair compression from tetrahedral | Trigonal Pyramidal (, 107°), Bent (, 104.5°) |
| Equatorial lone pair preference | Seesaw (), T-Shaped (), Linear () |
| Octahedral derivatives | Square Pyramidal (), Square Planar () |
| Nonpolar despite polar bonds | Linear , Trigonal Planar , Tetrahedral |
| Polar due to asymmetry | Bent , Trigonal Pyramidal , Seesaw |
| Expanded octet geometries | Trigonal Bipyramidal (), Octahedral (), Square Planar () |
Both and have three atoms, yet one is linear and one is bent. Explain how lone pairs account for this difference and predict which molecule is polar.
Compare the bond angles in , , and . What trend do you observe, and what principle explains it?
Why do lone pairs in a trigonal bipyramidal electron geometry preferentially occupy equatorial rather than axial positions? Use as your example.
Both (square planar) and (tetrahedral) have four atoms bonded to a central atom. Explain why their geometries and bond angles differ.
An FRQ asks you to explain why is nonpolar but is polar, even though both have three fluorines bonded to a central atom. How would you structure your response using molecular geometry concepts?