โˆซCalculus I

Fundamental Limit Laws

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Why This Matters

Limit laws are the computational engine of calculus. They're how you actually evaluate limits without relying on tables or graphs. Every derivative you'll compute later in the course depends on these rules working in the background.

These laws reflect a fundamental principle: limits respect algebraic operations. You can pull limits apart, work with the pieces, and reassemble them, as long as certain conditions are met. Exams love to test those conditions, especially the restrictions on the quotient rule and composite functions. Don't just memorize formulas; know when each rule applies and when it breaks down.


Building Block Laws

These are the foundation. Every other limit law builds on these two simple results.

Limit of a Constant

limโกxโ†’ck=k\lim_{x \to c} k = k

A constant function doesn't change as xx moves, so there's nothing to "approach." The output is always kk, regardless of what value xx is heading toward. This result also underpins the constant multiple rule you'll use constantly.

Limit of the Identity Function

limโกxโ†’cx=c\lim_{x \to c} x = c

The identity function f(x)=xf(x) = x is continuous everywhere, so its limit equals its function value. This is the basis for evaluating polynomial limits: combined with the power and sum rules, it's why you can plug in directly.

Compare: Both results feel "obvious," but they establish different behaviors. Constants ignore the input entirely; the identity function tracks it perfectly. Together, they justify why direct substitution works for continuous functions.


Arithmetic Operation Laws

These rules let you break a complex limit expression into simpler pieces. The core idea: limits distribute over basic arithmetic, turning one hard problem into several easy ones.

Sum/Difference Rule

limโกxโ†’c[f(x)ยฑg(x)]=limโกxโ†’cf(x)ยฑlimโกxโ†’cg(x)\lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)

Both individual limits must exist for this to apply. If either limit is undefined, you need a different approach. This rule is essential for polynomials: it lets you evaluate limโกxโ†’2(x2+3xโˆ’5)\lim_{x \to 2}(x^2 + 3x - 5) term by term as 4+6โˆ’5=54 + 6 - 5 = 5.

Product Rule

limโกxโ†’c[f(x)โ‹…g(x)]=limโกxโ†’cf(x)โ‹…limโกxโ†’cg(x)\lim_{x \to c} [f(x) \cdot g(x)] = \lim_{x \to c} f(x) \cdot \lim_{x \to c} g(x)

Both limits must exist and be finite. Watch for indeterminate forms like 0โ‹…โˆž0 \cdot \infty, where this rule cannot be applied directly. The rule extends naturally to any finite number of factors.

Quotient Rule

limโกxโ†’cf(x)g(x)=limโกxโ†’cf(x)limโกxโ†’cg(x)\lim_{x \to c} \frac{f(x)}{g(x)} = \frac{\lim_{x \to c} f(x)}{\lim_{x \to c} g(x)}

Critical restriction: the denominator's limit cannot be zero. If limโกxโ†’cg(x)=0\lim_{x \to c} g(x) = 0, this rule doesn't apply. When both numerator and denominator approach zero, you get the indeterminate form 00\frac{0}{0}, which requires algebraic manipulation (factoring, rationalizing) or L'Hรดpital's Rule.

Constant Multiple Rule

limโกxโ†’c[kโ‹…f(x)]=kโ‹…limโกxโ†’cf(x)\lim_{x \to c} [k \cdot f(x)] = k \cdot \lim_{x \to c} f(x)

This is actually a special case of the product rule where one "function" is a constant. Recognizing it separately lets you simplify faster: pull out coefficients first, then focus on the variable expression.

Compare: Product Rule vs. Constant Multiple Rule. The constant multiple rule is just the product rule with g(x)=kg(x) = k. But if you're asked to justify pulling out a coefficient, cite the constant multiple rule specifically rather than the general product rule.


Power and Root Laws

These rules handle exponents and radicals. The principle: if you can find the limit of the base, you can find the limit of any power or root of it.

Power Rule

limโกxโ†’c[f(x)]n=[limโกxโ†’cf(x)]nforย positiveย integerย n\lim_{x \to c} [f(x)]^n = \left[\lim_{x \to c} f(x)\right]^n \quad \text{for positive integer } n

The base limit must exist. If limโกxโ†’cf(x)\lim_{x \to c} f(x) is undefined, you can't apply this rule. Combined with the sum and constant rules, the power rule is why limโกxโ†’cp(x)=p(c)\lim_{x \to c} p(x) = p(c) for any polynomial pp.

Root Rule

limโกxโ†’cf(x)n=limโกxโ†’cf(x)n\lim_{x \to c} \sqrt[n]{f(x)} = \sqrt[n]{\lim_{x \to c} f(x)}

For even roots (square root, fourth root, etc.), the limit of the expression under the radical must be non-negative. You can't take โˆ’4\sqrt{-4} in the reals. Odd roots are more flexible since, for example, โˆ’83=โˆ’2\sqrt[3]{-8} = -2 is perfectly valid.

Compare: Both rules move the limit operation inside, but root rules carry domain restrictions that power rules don't. Exam questions often test this by placing a function whose limit is negative under a square root.


Advanced Limit Techniques

These handle situations where basic arithmetic laws aren't enough: nested functions and functions that resist direct evaluation.

Limits of Composite Functions

limโกxโ†’cf(g(x))=f(limโกxโ†’cg(x))\lim_{x \to c} f(g(x)) = f\left(\lim_{x \to c} g(x)\right)

This requires that ff is continuous at the value limโกxโ†’cg(x)=L\lim_{x \to c} g(x) = L. If ff has a discontinuity at LL, you can't swap the limit inside.

For example, to evaluate limโกxโ†’0sinโก(x2)\lim_{x \to 0} \sin(x^2):

  1. Find the inner limit: limโกxโ†’0x2=0\lim_{x \to 0} x^2 = 0.
  2. Check that sinโก\sin is continuous at 00 (it is).
  3. Conclude: sinโก(0)=0\sin(0) = 0.

Squeeze Theorem

If h(x)โ‰คf(x)โ‰คg(x)h(x) \leq f(x) \leq g(x) near cc, and limโกxโ†’ch(x)=limโกxโ†’cg(x)=L\lim_{x \to c} h(x) = \lim_{x \to c} g(x) = L, then limโกxโ†’cf(x)=L\lim_{x \to c} f(x) = L.

This is your go-to tool for oscillating functions that have no clean algebraic form. The classic example:

limโกxโ†’0x2sinโก(1x)=0\lim_{x \to 0} x^2 \sin\left(\frac{1}{x}\right) = 0

Since โˆ’1โ‰คsinโก(1x)โ‰ค1-1 \leq \sin\left(\frac{1}{x}\right) \leq 1, multiplying through by x2x^2 gives โˆ’x2โ‰คx2sinโก(1x)โ‰คx2-x^2 \leq x^2 \sin\left(\frac{1}{x}\right) \leq x^2. Both โˆ’x2-x^2 and x2x^2 approach 00, so the middle expression is squeezed to 00.

Both bounding limits must equal the same value. If they converge to different numbers, the squeeze doesn't apply.

Compare: Composite Function Rule vs. Squeeze Theorem. Use the composite function rule when you have nested operations and a continuous outer function. Use the Squeeze Theorem when the function oscillates or lacks a nice closed form. On free-response questions, you'll often need to construct the bounding functions yourself.


Quick Reference Table

ConceptBest Examples
Basic building blocksLimit of a Constant, Limit of xx
Arithmetic operationsSum/Difference Rule, Product Rule, Quotient Rule
Factoring out constantsConstant Multiple Rule
Handling exponentsPower Rule, Root Rule
Nested functionsComposite Function Rule
Oscillating/bounded functionsSqueeze Theorem
Direct substitution justified byAll rules combined (for continuous functions)
Indeterminate forms (rule fails)Quotient Rule when denominator โ†’0\to 0

Self-Check Questions

  1. Which two limit laws together explain why you can evaluate limโกxโ†’35x2\lim_{x \to 3} 5x^2 by computing 5โ‹…9=455 \cdot 9 = 45?

  2. The Quotient Rule requires a specific condition on the denominator. What is it, and what happens when that condition fails while the numerator also approaches zero?

  3. What additional restriction applies to even roots in the Root Rule that doesn't apply to the Power Rule?

  4. You need to evaluate limโกxโ†’0xsinโก(1x)\lim_{x \to 0} x \sin\left(\frac{1}{x}\right). Which technique applies here, and what bounding functions would you use?

  5. If limโกxโ†’2f(x)=5\lim_{x \to 2} f(x) = 5, under what condition on gg can you conclude that limโกxโ†’2g(f(x))=g(5)\lim_{x \to 2} g(f(x)) = g(5)?