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📘Intermediate Algebra

Essential Operations with Complex Numbers

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Why This Matters

Complex numbers aren't just an abstract mathematical curiosity—they're the key to unlocking solutions that real numbers simply can't provide. When you encounter a quadratic equation with no real solutions, complex numbers step in to complete the picture. You're being tested on your ability to manipulate these numbers fluently across all operations: addition, subtraction, multiplication, division, and simplification. These skills connect directly to solving polynomial equations, understanding the Fundamental Theorem of Algebra, and analyzing functions that previously seemed to have "no solution."

Think of complex numbers as expanding your mathematical toolkit. The same way negative numbers let you solve x+5=3x + 5 = 3 and fractions let you solve 2x=72x = 7, complex numbers let you solve x2=1x^2 = -1. On the exam, you won't just be asked to compute—you'll need to understand why conjugates eliminate imaginary denominators, how the complex plane connects algebra to geometry, and what the cyclical powers of i reveal about structure. Don't just memorize formulas—know what concept each operation demonstrates.


Building Blocks: Understanding Complex Number Structure

Before you can operate on complex numbers, you need to understand their anatomy. Every complex number has two distinct components that behave differently under various operations.

Definition of Complex Numbers (a + bi form)

  • Standard form a+bia + bi—where aa and bb are real numbers, and every complex number can be written this way
  • Real part (aa) and imaginary part (bb)—these are both real numbers; only the imaginary unit ii makes the second term "imaginary"
  • The imaginary unit i=1i = \sqrt{-1}—this definition means i2=1i^2 = -1, which is the foundation for all complex number simplification

Powers of i (i², i³, i⁴, etc.)

  • Cyclical pattern of fouri1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, i4=1i^4 = 1, then the cycle repeats
  • Simplify any power using remainders—divide the exponent by 4; the remainder tells you which value (i53=i1=ii^{53} = i^1 = i because 53÷453 \div 4 has remainder 1)
  • Essential for simplification—whenever you see i2i^2 in a calculation, immediately replace it with 1-1

Compare: i2i^2 vs. i4i^4—both are real numbers (no imaginary part), but i2=1i^2 = -1 while i4=1i^4 = 1. If an exam question asks you to simplify i100i^{100}, find the remainder when dividing by 4.


Arithmetic Operations: Computing with Complex Numbers

These operations follow predictable rules. The key insight is that real and imaginary parts don't mix—they stay in their own lanes until multiplication forces them to interact through i2=1i^2 = -1.

Addition and Subtraction of Complex Numbers

  • Combine like terms separately—real parts with real parts, imaginary parts with imaginary parts
  • Formula: (a+bi)+(c+di)=(a+c)+(b+d)i(a + bi) + (c + di) = (a + c) + (b + d)i—works exactly like combining like terms in polynomial addition
  • Subtraction follows the same pattern(a+bi)(c+di)=(ac)+(bd)i(a + bi) - (c + di) = (a - c) + (b - d)i; distribute the negative sign carefully

Multiplication of Complex Numbers

  • Use FOIL (distributive property)—multiply each term in the first factor by each term in the second
  • Formula: (a+bi)(c+di)=ac+adi+bci+bdi2(a + bi)(c + di) = ac + adi + bci + bdi^2—the bdi2bdi^2 term becomes bd-bd since i2=1i^2 = -1
  • Final simplified form: (acbd)+(ad+bc)i(ac - bd) + (ad + bc)i—always combine and write in standard form a+bia + bi

Division of Complex Numbers

  • Multiply by the conjugate—multiply both numerator and denominator by the conjugate of the denominator
  • Why it works(a+bi)(abi)=a2+b2(a + bi)(a - bi) = a^2 + b^2, a real number, eliminating ii from the denominator
  • Process: a+bic+dicdicdi\frac{a + bi}{c + di} \cdot \frac{c - di}{c - di}—then simplify and separate into real and imaginary parts

Compare: Addition vs. Multiplication—addition keeps real and imaginary parts completely separate, while multiplication creates cross-terms that combine through i2=1i^2 = -1. FRQs often test whether you can correctly handle the i2i^2 term in multiplication.


The Conjugate: Your Division and Simplification Tool

The complex conjugate is more than just "flip the sign"—it's a powerful tool that creates real numbers from complex ones, which is essential for division and finding absolute values.

Finding the Complex Conjugate

  • Definition: conjugate of a+bia + bi is abia - bi—only the sign of the imaginary part changes
  • Geometric meaning—reflects the point across the real axis in the complex plane
  • Key property: (a+bi)(abi)=a2+b2(a + bi)(a - bi) = a^2 + b^2—a conjugate pair always multiplies to a real number

Simplifying Complex Expressions

  • Always replace i2i^2 with 1-1—this is the most common simplification step
  • Combine like terms—gather all real parts together, all imaginary parts together
  • Write in standard form a+bia + bi—exam answers should always be in this form unless otherwise specified

Compare: (3+2i)(3+2i)(3 + 2i)(3 + 2i) vs. (3+2i)(32i)(3 + 2i)(3 - 2i)—the first gives 5+12i5 + 12i (still complex), while the second gives 1313 (purely real). Conjugate pairs always yield real products.


Geometric Interpretation: The Complex Plane

The complex plane transforms abstract numbers into visual, geometric objects. This connection between algebra and geometry appears frequently on exams.

Graphing Complex Numbers on the Complex Plane

  • Horizontal axis = real part, vertical axis = imaginary part—the complex number a+bia + bi plots at point (a,b)(a, b)
  • Addition becomes vector addition—adding complex numbers is equivalent to adding position vectors geometrically
  • Conjugates are reflectionsa+bia + bi and abia - bi are mirror images across the real (horizontal) axis

Absolute Value (Modulus) of Complex Numbers

  • Formula: a+bi=a2+b2|a + bi| = \sqrt{a^2 + b^2}—this is the distance from the origin to the point (a,b)(a, b)
  • Always non-negative and real—the modulus is never complex or negative
  • Connection to conjugates: z2=zzˉ|z|^2 = z \cdot \bar{z}—the product of a complex number and its conjugate equals the square of its absolute value

Compare: 3+4i|3 + 4i| vs. 34i|3 - 4i|—both equal 55 because conjugates have the same distance from the origin. This is a common exam trap: changing the sign of the imaginary part doesn't change the modulus.


Applications: Solving Equations with Complex Solutions

This is where complex numbers prove their worth—they guarantee that every polynomial equation has solutions, completing the algebraic picture.

Solving Quadratic Equations with Complex Solutions

  • Check the discriminant b24acb^2 - 4ac—if negative, the solutions are complex (no real solutions exist)
  • Quadratic formula still works: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}—the negative discriminant produces negative\sqrt{\text{negative}}, which equals ipositivei\sqrt{\text{positive}}
  • Complex solutions come in conjugate pairs—if 2+3i2 + 3i is a solution, then 23i2 - 3i is also a solution

Compare: Discriminant >0> 0 vs. Discriminant <0< 0—positive discriminant gives two real solutions, negative discriminant gives two complex conjugate solutions. Zero discriminant gives one repeated real solution. This three-way distinction is heavily tested.


Quick Reference Table

ConceptBest Examples
Standard form structurea+bia + bi definition, real vs. imaginary parts
Powers of iii2=1i^2 = -1, cyclical pattern (period 4)
Addition/SubtractionCombine like terms separately
MultiplicationFOIL method, i2=1i^2 = -1 substitution
DivisionMultiply by conjugate of denominator
Complex conjugatea+biabia + bi \to a - bi, creates real products
Absolute value (modulus)a2+b2\sqrt{a^2 + b^2}, distance interpretation
Complex solutionsNegative discriminant, conjugate pairs

Self-Check Questions

  1. What do the complex numbers 3+4i3 + 4i and 34i3 - 4i have in common, and what makes them different? How does this relate to their positions on the complex plane?

  2. When multiplying (2+5i)(3i)(2 + 5i)(3 - i), which term produces the key simplification, and what does it simplify to?

  3. Why must you multiply by the conjugate when dividing complex numbers? What would happen if you didn't?

  4. If a quadratic equation has the solution 47i4 - 7i, what must the other solution be, and why?

  5. FRQ-style: Given z=6+8iz = 6 + 8i, calculate z|z|, find zˉ\bar{z} (the conjugate), and verify that zzˉ=z2z \cdot \bar{z} = |z|^2. Explain the geometric significance of each result.