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🏃🏽‍♀️‍➡️Intro to Mathematical Analysis Unit 5 Review

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5.2 One-Sided Limits

5.2 One-Sided Limits

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
🏃🏽‍♀️‍➡️Intro to Mathematical Analysis
Unit & Topic Study Guides

One-sided limits help us understand how functions behave near tricky points. They're like looking at a function from the left or right side as we get super close to a specific value. This concept is crucial for grasping limits and continuity.

By comparing left-hand and right-hand limits, we can figure out if a function has a regular limit at a point. If both sides match up, we've got a limit. If not, no dice. This idea is super helpful for analyzing piecewise functions and spotting discontinuities.

Left-hand vs Right-hand Limits

Understanding One-sided Limits

  • Left-hand and right-hand limits describe the behavior of a function as it approaches a specific point from the left side (values less than the point) or right side (values greater than the point)
  • The left-hand limit of a function f(x)f(x) as xx approaches a point aa is denoted as limxaf(x)\lim_{x \to a^-} f(x)
    • This notation indicates that xx approaches aa from values less than aa
  • The right-hand limit of a function f(x)f(x) as xx approaches a point aa is denoted as limxa+f(x)\lim_{x \to a^+} f(x)
    • This notation indicates that xx approaches aa from values greater than aa
  • One-sided limits are useful for determining the behavior of a function near a point of discontinuity or a point where the function is not defined

Relationship between One-sided Limits and Limits

  • If the left-hand and right-hand limits of a function at a point are equal, the function is said to have a limit at that point
    • In other words, limxaf(x)=L\lim_{x \to a} f(x) = L if and only if limxaf(x)=L\lim_{x \to a^-} f(x) = L and limxa+f(x)=L\lim_{x \to a^+} f(x) = L
  • If either the left-hand or right-hand limit does not exist or if they are not equal, the function does not have a limit at that point
  • Example: Consider the function f(x)=x21x1f(x) = \frac{x^2 - 1}{x - 1} at x=1x = 1
    • limx1f(x)=2\lim_{x \to 1^-} f(x) = 2 and limx1+f(x)=2\lim_{x \to 1^+} f(x) = 2, so limx1f(x)=2\lim_{x \to 1} f(x) = 2

One-sided Limits: Graphical & Numerical

Graphical Method

  • To evaluate a one-sided limit graphically, observe the behavior of the function as it approaches the point of interest from the left or right side on the graph
  • If the function appears to approach a specific value as xx approaches the point from the left (or right), that value is the left-hand (or right-hand) limit
  • Example: For the function f(x)={x2,x<0x,x0f(x) = \begin{cases} x^2, & x < 0 \\ x, & x \geq 0 \end{cases}, the left-hand limit at x=0x = 0 is 00 and the right-hand limit at x=0x = 0 is also 00

Numerical Method

  • To evaluate a one-sided limit numerically, create a table of values for the function as xx approaches the point of interest from the left or right side
  • Observe the trend in the function values as xx gets closer to the point
    • If the function values approach a specific value, that value is the one-sided limit
  • When using the numerical method, choose xx-values that are increasingly close to the point of interest for a more accurate estimate of the one-sided limit
  • One-sided limits can be infinite (positive or negative) if the function values tend to positive or negative infinity as xx approaches the point from the left or right side
  • One-sided limits can be equal to the function value at the point if the function is continuous at that point

Limit Existence: Comparing Sides

Conditions for Limit Existence

  • A function has a limit at a point if and only if both the left-hand and right-hand limits exist and are equal
  • If the left-hand and right-hand limits are different or if either one-sided limit does not exist, then the function does not have a limit at that point
  • To determine the existence of a limit, evaluate both the left-hand and right-hand limits using graphical or numerical methods
    • If the left-hand and right-hand limits are equal and finite, the limit exists and is equal to the common value
    • If the left-hand and right-hand limits are equal and infinite (both positive or both negative), the limit exists and is equal to the corresponding infinity

Examples of Limit Existence and Non-existence

  • Example of a function with a limit: f(x)=x21x1f(x) = \frac{x^2 - 1}{x - 1} at x=1x = 1
    • limx1f(x)=2\lim_{x \to 1^-} f(x) = 2 and limx1+f(x)=2\lim_{x \to 1^+} f(x) = 2, so limx1f(x)=2\lim_{x \to 1} f(x) = 2
  • Example of a function without a limit: g(x)={1,x<00,x0g(x) = \begin{cases} 1, & x < 0 \\ 0, & x \geq 0 \end{cases} at x=0x = 0
    • limx0g(x)=1\lim_{x \to 0^-} g(x) = 1 and limx0+g(x)=0\lim_{x \to 0^+} g(x) = 0, so limx0g(x)\lim_{x \to 0} g(x) does not exist

Piecewise Functions & One-sided Limits

Analyzing Piecewise-defined Functions

  • Piecewise-defined functions are functions that are defined by different expressions or rules for different intervals of the domain
  • To analyze the behavior of a piecewise-defined function at a point where the definition changes, evaluate the one-sided limits at that point
  • When given a piecewise-defined function, identify the intervals over which each piece of the function is defined and the corresponding expressions or rules
    • Example: h(x)={x2,x<12x1,x1h(x) = \begin{cases} x^2, & x < 1 \\ 2x - 1, & x \geq 1 \end{cases}
      • For x<1x < 1, h(x)=x2h(x) = x^2
      • For x1x \geq 1, h(x)=2x1h(x) = 2x - 1

Continuity of Piecewise-defined Functions

  • To determine the continuity of a piecewise-defined function at a point where the definition changes, compare the left-hand limit, the right-hand limit, and the function value (if defined) at that point
  • If the left-hand limit, the right-hand limit, and the function value (if defined) are all equal at a point where the definition changes, the piecewise-defined function is continuous at that point
  • Example: For h(x)={x2,x<12x1,x1h(x) = \begin{cases} x^2, & x < 1 \\ 2x - 1, & x \geq 1 \end{cases}, check continuity at x=1x = 1
    • limx1h(x)=1\lim_{x \to 1^-} h(x) = 1, limx1+h(x)=1\lim_{x \to 1^+} h(x) = 1, and h(1)=2(1)1=1h(1) = 2(1) - 1 = 1
    • Since the left-hand limit, the right-hand limit, and the function value are all equal at x=1x = 1, h(x)h(x) is continuous at x=1x = 1
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