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๐Ÿƒ๐Ÿฝโ€โ™€๏ธโ€โžก๏ธIntro to Mathematical Analysis Unit 13 Review

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13.2 Radius and Interval of Convergence

13.2 Radius and Interval of Convergence

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
๐Ÿƒ๐Ÿฝโ€โ™€๏ธโ€โžก๏ธIntro to Mathematical Analysis
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Power series are the mathematical equivalent of a Swiss Army knife. They're versatile tools that let us represent functions as infinite sums of terms. But how far can we stretch these series before they break?

That's where the radius and interval of convergence come in. They tell us the range of x-values where a power series behaves nicely, giving us a playground for manipulating and analyzing functions in new ways.

Radius of convergence for power series

Definition and properties

  • A power series is a series of the form โˆ‘n=0โˆžan(xโˆ’c)n\sum_{n=0}^{\infty} a_n(x-c)^n, where cc is the center of the series and ana_n are the coefficients
  • The radius of convergence RR is the radius of the largest open interval centered at cc on which the power series converges
  • If a power series converges at a point x0x_0, it converges absolutely for all xx satisfying โˆฃxโˆ’cโˆฃ<โˆฃx0โˆ’cโˆฃ|x-c| < |x_0-c|
  • If a power series diverges at x0x_0, it diverges for all xx satisfying โˆฃxโˆ’cโˆฃ>โˆฃx0โˆ’cโˆฃ|x-c| > |x_0-c|

Types of convergence radii

  • The radius of convergence can be finite, infinite, or zero
    • If RR is finite, the series converges absolutely for โˆฃxโˆ’cโˆฃ<R|x-c| < R and diverges for โˆฃxโˆ’cโˆฃ>R|x-c| > R
    • If RR is infinite, the series converges for all xx
    • If RR is zero, the series converges only at x=cx = c
  • Examples:
    • โˆ‘n=0โˆžxn\sum_{n=0}^{\infty} x^n has an infinite radius of convergence
    • โˆ‘n=0โˆžn!xn\sum_{n=0}^{\infty} n!x^n has a radius of convergence of 0

Ratio test for convergence

Definition and properties, calculus - Interval of convergence of a power series, with a check for convergence at endpoints ...

Applying the ratio test

  • The ratio test determines the radius of convergence of a power series
    • If limโกnโ†’โˆžโˆฃan+1/anโˆฃ\lim_{n\to\infty} |a_{n+1}/a_n| exists, then the radius of convergence is R=1/limโกnโ†’โˆžโˆฃan+1/anโˆฃR = 1/\lim_{n\to\infty} |a_{n+1}/a_n|
  • To apply the ratio test, find the limit of the absolute value of the ratio of successive coefficients
    • If the limit is LL, then R=1/LR = 1/L
    • If the limit is 0, the radius of convergence is infinite
    • If the limit is โˆž\infty, the radius of convergence is 0
  • Example: For โˆ‘n=0โˆžxnn!\sum_{n=0}^{\infty} \frac{x^n}{n!}, limโกnโ†’โˆžโˆฃan+1anโˆฃ=limโกnโ†’โˆžโˆฃ1n+1โˆฃ=0\lim_{n\to\infty} |\frac{a_{n+1}}{a_n}| = \lim_{n\to\infty} |\frac{1}{n+1}| = 0, so R=โˆžR = \infty

Interpreting the limit

  • If the limit does not exist or is a finite non-zero value, the radius of convergence is the reciprocal of that value
  • Example: For โˆ‘n=0โˆž2nxn\sum_{n=0}^{\infty} 2^n x^n, limโกnโ†’โˆžโˆฃan+1anโˆฃ=limโกnโ†’โˆžโˆฃ2โˆฃ=2\lim_{n\to\infty} |\frac{a_{n+1}}{a_n}| = \lim_{n\to\infty} |2| = 2, so R=1/2R = 1/2

Interval of convergence

Definition and properties, real analysis - Proof of the "Radius of Convergence Theorem" - Mathematics Stack Exchange

Finding the interval of convergence

  • The interval of convergence is the set of all values of xx for which the power series converges, always centered at cc
  • To find the interval of convergence:
    1. Determine the radius of convergence RR using the ratio test
    2. If RR is infinite, the interval of convergence is (โˆ’โˆž,โˆž)(-\infty, \infty)
    3. If RR is zero, the interval of convergence is the single point {c}\{c\}
    4. If RR is finite, the interval of convergence is at least (cโˆ’R,c+R)(c-R, c+R)

Testing endpoints for convergence

  • To determine if the endpoints are included in the interval of convergence, test the series for convergence at x=cโˆ’Rx = c-R and x=c+Rx = c+R
  • Use other convergence tests such as the alternating series test, p-series test, or comparison test
  • Example: For โˆ‘n=0โˆžxnn2\sum_{n=0}^{\infty} \frac{x^n}{n^2}, R=1R = 1. Testing endpoints:
    • At x=โˆ’1x = -1: โˆ‘n=0โˆž(โˆ’1)nn2\sum_{n=0}^{\infty} \frac{(-1)^n}{n^2} converges by the alternating series test
    • At x=1x = 1: โˆ‘n=0โˆž1n2\sum_{n=0}^{\infty} \frac{1}{n^2} converges by the p-series test with p=2>1p=2>1
    • The interval of convergence is [โˆ’1,1][-1, 1]

Power series behavior at endpoints

Convergence and divergence at endpoints

  • The behavior of a power series at the endpoints of its interval of convergence depends on whether the series converges or diverges at those points
  • If the series converges at an endpoint, that endpoint is included in the interval of convergence
    • The series may converge conditionally or absolutely at the endpoint
  • If the series diverges at an endpoint, that endpoint is not included in the interval of convergence

Determining endpoint behavior

  • To determine the behavior at the endpoints, substitute the endpoint values into the power series
  • Use appropriate convergence tests to determine if the series converges or diverges
  • The behavior at the endpoints can differ for the left and right endpoints
    • One endpoint may be included while the other is not, or both may be included or excluded
  • Example: For โˆ‘n=0โˆž(xโˆ’1)nn\sum_{n=0}^{\infty} \frac{(x-1)^n}{n}, R=1R = 1
    • At x=0x = 0: โˆ‘n=0โˆž(โˆ’1)nn\sum_{n=0}^{\infty} \frac{(-1)^n}{n} converges conditionally by the alternating series test
    • At x=2x = 2: โˆ‘n=0โˆž1n\sum_{n=0}^{\infty} \frac{1}{n} diverges by the p-series test with p=1โ‰ค1p=1\leq 1
    • The interval of convergence is [0,2)[0, 2)