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Unit 1

1.2 Kinematics: Motion in Two Dimensions ⚾

4 min readjanuary 29, 2021

gerardo-rafael34575854

Gerardo Rafael Bote

caroline49234295

Caroline Koffke


AP Physics C: Mechanics ⚙️

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1.2 Kinematics: Motion in 2-D

Great! You know how to consider motion in 1 dimension! Is your brain ready to handle TWO dimensions?
This is where projectile motion usually comes in. Take a look at the picture below:
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-RHhdEj4Y22go.png?alt=media&token=45008e50-a791-4f8c-961a-3ad7438349da

Image from DKPhysics

There are now two components to each velocity: the horizontal velocity and vertical velocity. The only component being affected by gravity (g=9.81 m/s2 ≈ 10m/s2) is vertical velocity. Therefore, an object's horizontal velocity does not change until the final impact.
An object's horizontal components and vertical components are independent of each other; however, they are related to each other via TIME.
When the object reaches its max height, be aware that v_y = 0
Look at how each of the horizontal and vertical components are comprised:
  • X-Direction Components
    https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.20-G4Cj63iubgMo.png?alt=media&token=9ed01d42-e5b9-4129-a18d-f5f8701743ec
  • Y-Direction Components
    https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.07-etQqCyZJGsCR.png?alt=media&token=e21ed7ed-a111-47c1-b56c-73321b4bb52e
    https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-lgcyPXnP4uzX.png?alt=media&token=cceded3b-9d9c-48be-aba9-b94ec7ad7891
⚠️WOAH... How did you get all of those equations above? Are they on the formula sheet?
First of all, thanks for mentioning the formula sheet! It is useful when you need to derive an equation, like what you see above! You will see this sheet when you take the AP exam in May.
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-M2DD127ehp0T.png?alt=media&token=94ab6c1f-826f-46d5-9938-03d684eec68f

Image from collegeboard.org

For this unit, the first three equations (in red box) are emphasized in finding missing values, whether it be velocity, acceleration, or time. The first three equations can also be modified to fit either the y-direction or x-direction as well! Also remember that some values may be equal to 0, canceling out some adding or subtracting.
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-cVJV6pncsewn.png?alt=media&token=adff4d4a-f8fa-4aac-ba63-5f68187ca3e3

Image from QS Study

For example, let's use the first equation above (v_x = v_x0 + a_y t )to be modified in the y-direction and solve for the time it takes a projectile to reach its max height:
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.08-qSsBAyvzdctE.png?alt=media&token=5735a05b-8a5a-4475-88ef-94bd8c247954
There are many values we can put in to solve for the time it takes a projectile to reach its max height
(t). First, let's assume the following: the ball above starts at rest on the ground. Then, the ball is launched at an angle of θ. From the following info, you know that at max height, the vertical velocity of an object is 0. You also know that a _y =−g because there is always a downward acceleration due to gravity. Lastly, you know that v_{y_0} = v_osinθ because of how trigonometry works within a projectile's launch. You then set up the equation and evaluate:
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.08-IGKvPswxKlGq.png?alt=media&token=cd31bbf5-a6f5-44e6-b4c6-74ecb6de25ed
You might be confused on how projectile motion still works, so try out the PhET Simulation below to experiment with different factors of projectile motion (i.e., time, velocity, acceleration)!
You can also see why AP says that you can assume "air resistance is negligible." 😅

Kinematics Practice Questions:

https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-hNDUYMXsxnuv.png?alt=media&token=ba62abcf-78f2-4d25-aaa0-64d31aa40d05

Image from New Jersey Center for Teaching & Learning

Answer

The correct answer is C. For this problem, all you need to know is the vertical components of the motion since we do not need to know the horizontal range of the tennis ball. We can use the
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.09-AmLCnTi7LpW7.png?alt=media&token=ea0ee1e5-5aea-47fd-a677-58a668349f5c
equation since we know everything in the equation but time.
⚠️Wait... what is the value of v_oy
​The value of v_oy is 0 because there is no initial vertical velocity. Therefore, you can just cancel out v_oy t part, leaving Δy=1/2 gt^2 This is how you set up the equation:
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.09-if9nCJkgokFP.png?alt=media&token=08441cc6-c6e5-4816-8a3e-8bce2b85645a
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-0eS4IEujg7aQ.png?alt=media&token=cd7439e0-46b0-43d7-bad7-20b630be43ef

Image from collegeboard.org

Answer

The correct answer is C. The only accceleration that takes place in projectile motion is the downward acceleration of gravity (-9.8 m/s^2). A is wrong because the vertical component of the sphere's velocity is actually at a minimum(0) at point P. B is wrong because the horizontal component of the sphere's velocity is constant throughout the whole motion, not at just point P. D is wrong because the sphere's speed is not constant throughout the whole motion, especially at point P. E is wrong because the displacement changed according to the sphere's starting point (i.e., origin). 
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-Iviwv51d5Xfo.png?alt=media&token=2cecfc58-9cf2-43a0-aaaa-1e203f958752

Image from New Jersey Center for Teaching & Learningg

Answer

The correct answer is A. To calculate the horizontal and vertical components of a projectile launched at an angle, you need to consider the trigonometry behind the ball's launch. You should know that
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.10-vglMetZ3a5gI.png?alt=media&token=74607fc2-b520-45b1-9e12-e8ec472a4ba2
Then calculate:
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.10-WNMqzdqWzM7F.png?alt=media&token=b7c0cffa-9ca3-41c9-8a6b-753e48033db9
TIP: Be careful when the problem specifies whether you should be in degrees or radians!
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2F-D6NBpWrRRmdT.png?alt=media&token=35a9fc1e-1af2-43e3-9535-28a4447cd3e3

Answer

The correct answer is E. To solve this question correctly, you need to know that the acceleration function is the derivative of the velocity function. Then, you need to know proper derivative rules to correctly get E. This is the derivative rule for functions with e, Euler's number (let u represent any real function):
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreen%20Shot%202020-09-11%20at%2010.10-d1T8xaktUMB8.png?alt=media&token=4454557b-2f1b-4a25-9629-dfd4fb4cb021
In this case, you also need to know that constants multiplied by e^u or other exponential functions stay since it is not related to x. Therefore, the constant v_o stays since it represents a number. du/dx means to derive the function represented by u, and deriving −αt would give us −α.

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