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🎒ACT

ACT Math Formulas to Memorize for ACT

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Why This Matters

The ACT Math section isn't just testing whether you can plug numbers into formulas—it's testing whether you understand when and why to use each one. You'll face 60 questions in 60 minutes, which means you need these formulas to be automatic. The test loves to combine concepts: a question might require you to find a circle's area, then use that result in a volume calculation, then interpret what that means in a real-world context.

The formulas below aren't random—they cluster around core mathematical principles: measuring flat shapes, measuring 3D objects, navigating coordinate planes, solving equations, and working with triangles. Don't just memorize each formula in isolation. Know what category it belongs to, when it applies, and how it connects to related formulas. That conceptual understanding is what separates a good score from a great one.


Two-Dimensional Area Formulas

These formulas measure the space inside flat shapes. The key principle: area always involves multiplying two dimensions together, which is why area units are always squared.

Area of a Rectangle

  • A=lwA = lw—multiply length by width to find the space inside any rectangle or square
  • Units are always squared—square feet, square meters, etc., because you're multiplying two linear measurements
  • Foundation for other formulas—rectangles are the building blocks; triangle area is half a rectangle, and prism volume extends this into 3D

Area of a Triangle

  • A=12bhA = \frac{1}{2}bh—half the base times the height, where height must be perpendicular to the base
  • Works for ALL triangles—not just right triangles; the height might fall outside the triangle in obtuse cases
  • Common ACT trap—the test often gives you side lengths instead of height, requiring you to calculate height first

Area of a Circle

  • A=πr2A = \pi r^2—square the radius first, then multiply by π\pi
  • Radius, not diameter—if given diameter, divide by 2 before using this formula
  • Sector problems—for partial circles, multiply this area by the fraction of the circle (central angle divided by 360°)

Compare: Rectangle area vs. Triangle area—both use base and height, but triangles are exactly half. If an ACT question shows a triangle inside a rectangle sharing the same base and height, the triangle is always half the rectangle's area.


Three-Dimensional Volume and Surface Area

Volume measures space inside 3D objects (cubic units), while surface area measures the outside skin (square units). The pattern: volume = base area × height.

Volume of a Rectangular Prism

  • V=lwhV = lwh—length times width times height; essentially rectangle area extended into 3D
  • Units are cubed—cubic feet, cubic meters, etc., because you're multiplying three dimensions
  • Box problems—any question about boxes, rooms, or tanks likely needs this formula

Volume of a Cylinder

  • V=πr2hV = \pi r^2 h—circle area (πr2\pi r^2) times height; same pattern as the prism
  • Stacked circles concept—visualize a cylinder as circles stacked on top of each other
  • Common applications—pipes, cans, tanks; the ACT loves practical cylinder problems

Surface Area of a Rectangular Prism

  • SA=2(lw+lh+wh)SA = 2(lw + lh + wh)—add the three different face areas, then double (since opposite faces match)
  • Six faces total—two of each type: top/bottom, front/back, left/right
  • Wrapping and painting problems—surface area tells you how much material covers the outside

Surface Area of a Cylinder

  • SA=2πrh+2πr2SA = 2\pi rh + 2\pi r^2—lateral surface (the curved part) plus two circular bases
  • Label trick—the lateral area 2πrh2\pi rh is like unrolling a rectangle wrapped around the cylinder
  • Partial cylinders—if a cylinder is open (no top), subtract one πr2\pi r^2 from the formula

Compare: Prism volume vs. Cylinder volume—both follow the pattern "base area × height." The only difference is the base shape (rectangle vs. circle). Recognizing this pattern helps you adapt to unfamiliar 3D shapes.


Circle Measurements

Circles have their own special formulas because they involve π\pi. The key relationship: everything connects back to the radius.

Circumference of a Circle

  • C=2πrC = 2\pi r or equivalently C=πdC = \pi d—the distance around the circle
  • Diameter = 2r—use whichever form matches what the problem gives you
  • Arc length—for partial circles, multiply circumference by the fraction (central angle ÷ 360°)

Compare: Circumference vs. Area—circumference uses rr to the first power (linear measurement), while area uses r2r^2 (two-dimensional). If you double the radius, circumference doubles but area quadruples.


Coordinate Geometry Formulas

These formulas let you work with points and lines on the coordinate plane. They're all derived from the relationship between horizontal and vertical distances.

Slope Formula

  • m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}—"rise over run," the change in y divided by change in x
  • Positive slope = upward line (left to right); negative slope = downward line; zero slope = horizontal; undefined slope = vertical
  • Parallel lines have equal slopes; perpendicular lines have slopes that are negative reciprocals

Midpoint Formula

  • (x1+x22,y1+y22)\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)—average the x-coordinates and average the y-coordinates
  • Center point applications—finding the center of a line segment or the middle of a diameter
  • Works in reverse—if given midpoint and one endpoint, you can solve for the other endpoint

Distance Formula

  • d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}—derived directly from the Pythagorean theorem
  • Creates a right triangle—the horizontal and vertical distances are legs; the direct distance is the hypotenuse
  • Always square before adding—a common error is forgetting to square the differences

Compare: Slope vs. Distance—both use (x2x1)(x_2 - x_1) and (y2y1)(y_2 - y_1), but slope divides them (ratio) while distance squares and adds them (Pythagorean theorem). Know which operation matches which formula.


Triangle Relationships

Triangles appear constantly on the ACT. These formulas and ratios help you find missing sides and angles quickly.

Pythagorean Theorem

  • a2+b2=c2a^2 + b^2 = c^2—for right triangles only; cc is always the hypotenuse (longest side, opposite the right angle)
  • Finding any side—rearrange to find a leg: a=c2b2a = \sqrt{c^2 - b^2}
  • Testing for right triangles—if the equation holds true, the triangle is a right triangle

SOHCAHTOA (Trigonometric Ratios)

  • SOH: sinθ=OppositeHypotenuse\sin\theta = \frac{\text{Opposite}}{\text{Hypotenuse}}—the side across from the angle divided by the longest side
  • CAH: cosθ=AdjacentHypotenuse\cos\theta = \frac{\text{Adjacent}}{\text{Hypotenuse}}—the side touching the angle (not the hypotenuse) divided by the longest side
  • TOA: tanθ=OppositeAdjacent\tan\theta = \frac{\text{Opposite}}{\text{Adjacent}}—useful when the hypotenuse isn't involved in the problem

Special Right Triangle Ratios

  • 45-45-90 triangle: sides in ratio 1:1:21:1:\sqrt{2}—the two legs are equal; hypotenuse is leg × 2\sqrt{2}
  • 30-60-90 triangle: sides in ratio 1:3:21:\sqrt{3}:2—shortest side opposite 30°, longest opposite 90°
  • Time-saver—memorizing these lets you skip calculations entirely when you recognize these triangles

Compare: 45-45-90 vs. 30-60-90—both are derived from the Pythagorean theorem, but 45-45-90 is isoceles (two equal sides) while 30-60-90 has three different side lengths. The ACT often hides these triangles inside other shapes—look for squares cut diagonally (45-45-90) or equilateral triangles cut in half (30-60-90).


Algebraic Problem-Solving

When geometry formulas won't help, these algebraic tools solve equations and find unknown values.

Quadratic Formula

  • x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}—solves any equation in the form ax2+bx+c=0ax^2 + bx + c = 0
  • The discriminant (b24acb^2 - 4ac) tells you the nature of solutions: positive = two real solutions, zero = one solution, negative = no real solutions
  • When to use it—when factoring isn't obvious or possible; the formula always works

Compare: Factoring vs. Quadratic formula—factoring is faster when it works, but the quadratic formula is your backup for any quadratic. If a problem seems designed to have "nice" numbers, try factoring first.


Quick Reference Table

ConceptKey Formulas
2D AreaA=lwA = lw (rectangle), A=12bhA = \frac{1}{2}bh (triangle), A=πr2A = \pi r^2 (circle)
3D VolumeV=lwhV = lwh (prism), V=πr2hV = \pi r^2 h (cylinder)
Surface AreaSA=2(lw+lh+wh)SA = 2(lw + lh + wh) (prism), SA=2πrh+2πr2SA = 2\pi rh + 2\pi r^2 (cylinder)
Circle MeasurementsC=2πrC = 2\pi r, A=πr2A = \pi r^2
Coordinate GeometrySlope: y2y1x2x1\frac{y_2-y_1}{x_2-x_1}, Distance: (x2x1)2+(y2y1)2\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, Midpoint: averages
Right Trianglesa2+b2=c2a^2 + b^2 = c^2, SOHCAHTOA
Special Triangles45-45-90: 1:1:21:1:\sqrt{2}, 30-60-90: 1:3:21:\sqrt{3}:2
Quadraticsx=b±b24ac2ax = \frac{-b \pm \sqrt{b^2-4ac}}{2a}

Self-Check Questions

  1. What do the distance formula and the Pythagorean theorem have in common, and why does this connection make sense geometrically?

  2. If you double the radius of a circle, what happens to its circumference? What happens to its area? Why are these results different?

  3. Which two formulas follow the pattern "base area × height," and how does recognizing this pattern help you with unfamiliar 3D shapes?

  4. You see a triangle with angles of 30°, 60°, and 90°. Without calculating, what is the ratio of the shortest side to the longest side?

  5. Compare and contrast: When would you use the slope formula versus the distance formula if given two coordinate points? What question is each formula answering?