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💡AP Physics C: Electricity and Magnetism
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💡AP Physics C: Electricity and Magnetism

FRQ 4 – Qualitative/Quantitative Translation
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Unit 8: Electric Charges, Fields, and Gauss's Law
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Practice FRQ 1 of 21/2

4. A solid insulating sphere of radius 0.30 m is centered at the origin and has uniform volume charge density ρ=+6.0×10−6 C/m3\rho = +6.0\times10^{-6}\ \text{C/m}^3ρ=+6.0×10−6 C/m3. A spherical cavity of radius 0.10 m is carved out of the sphere. The cavity's center is on the +x-axis at x=0.10 mx = 0.10\ \text{m}x=0.10 m. The remaining charge in the insulating material is unchanged by the carving (charge is removed only from the cavity region). The object is surrounded by a uniform dielectric material with relative permittivity κ=2.0\kappa = 2.0κ=2.0. Consider two points on the x-axis: Point 1 is at x=+0.05 mx=+0.05\ \text{m}x=+0.05 m (inside the cavity), and Point 2 is at x=−0.05 mx=-0.05\ \text{m}x=−0.05 m (inside the charged insulating material). Figure 1 shows this setup. Ignore any polarization surface-charge details and treat the dielectric effect using ϵ=κϵ0\epsilon = \kappa\epsilon_0ϵ=κϵ0​.

Figure 1. Charged insulating sphere with an off-center spherical cavity and two labeled points on the x-axis (dielectric with κ = 2.0).

Figure 1
A.

E1E_1E1​ is the magnitude of the electric field at Point 1, and E2E_2E2​ is the magnitude of the electric field at Point 2.

Indicate whether E2E_2E2​ is greater than, less than, or equal to E1E_1E1​ by writing one of the following.

  • E2>E1E_2 > E_1E2​>E1​
  • E2<E1E_2 < E_1E2​<E1​
  • E2=E1E_2 = E_1E2​=E1​

Justify your answer.

B.

Derive an expression for the electric flux ΦE\Phi_EΦE​ through a spherical Gaussian surface of radius r=0.25 mr = 0.25\ \text{m}r=0.25 m centered at the origin. Express your answer in terms of ρ\rhoρ, ϵ0\epsilon_0ϵ0​, κ\kappaκ, and geometric constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

Figure 2. Same charged sphere and points as Figure 1, but the cavity center is moved to x = +0.05 m (Point 1 coincides with the cavity center).

Figure 2
C.

Indicate whether E2,newE_{2,\text{new}}E2,new​ is greater than, less than, or equal to E2E_2E2​ by writing one of the following. Later, the cavity is moved so that its center is at x=+0.05 mx = +0.05\ \text{m}x=+0.05 m, as shown in Figure 2. The charge density of the insulating material remains ρ=+6.0×10−6 C/m3\rho = +6.0\times10^{-6}\ \text{C/m}^3ρ=+6.0×10−6 C/m3 and the surrounding medium remains a uniform dielectric with κ=2.0\kappa = 2.0κ=2.0. The points are unchanged: Point 1 is at x=+0.05 mx=+0.05\ \text{m}x=+0.05 m and Point 2 is at x=−0.05 mx=-0.05\ \text{m}x=−0.05 m. Let E1,newE_{1,\text{new}}E1,new​ and E2,newE_{2,\text{new}}E2,new​ be the new magnitudes of the electric field at Points 1 and 2, respectively.

  • E2,new>E2E_{2,\text{new}} > E_2E2,new​>E2​
  • E2,new<E2E_{2,\text{new}} < E_2E2,new​<E2​
  • E2,new=E2E_{2,\text{new}} = E_2E2,new​=E2​

Briefly justify your answer by referencing your reasoning from part A and/or a superposition argument consistent with part B.

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Free Response Question Practice

This practice environment simulates the AP AP Physics C: Electricity and Magnetism Free Response Questions section. Here are some guidelines:

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