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🌊College Physics II – Mechanics, Sound, Oscillations, and Waves Unit 6 Review

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6.3 Centripetal Force

6.3 Centripetal Force

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
🌊College Physics II – Mechanics, Sound, Oscillations, and Waves
Unit & Topic Study Guides

Circular motion is all about objects moving in curved paths. We'll explore centripetal force, the key player that keeps things spinning. This force points to the center, causing acceleration that constantly changes an object's direction without altering its speed.

We'll dive into the math behind centripetal acceleration and force. You'll learn how to solve problems involving circular motion, from Ferris wheels to orbiting satellites. Understanding these concepts is crucial for grasping the physics of rotating systems.

Centripetal Force and Circular Motion

Equation of centripetal acceleration

  • Centripetal acceleration is the acceleration directed towards the center of a circular path causes an object to follow a curved trajectory
  • Defined as the change in velocity over time a=ΔvΔta = \frac{\Delta v}{\Delta t} where the magnitude of velocity (speed) remains constant but the direction changes continuously
  • The change in velocity Δv\Delta v is perpendicular to the instantaneous velocity and points towards the center of the circle at any given point along the path
  • The magnitude of centripetal acceleration can be derived using the properties of a right triangle formed by the velocity vectors over a small time interval
    • The change in velocity Δv\Delta v is related to the angular displacement Δθ\Delta \theta and the radius of the circle rr by Δv=rΔθ\Delta v = r \Delta \theta
    • For small time intervals, the angle Δθ\Delta \theta can be approximated as ΔθvΔtr\Delta \theta \approx \frac{v \Delta t}{r} where vv is the constant speed
    • Substituting this into the acceleration equation yields a=ΔvΔt=rΔθΔtr(vΔtr)Δt=v2ra = \frac{\Delta v}{\Delta t} = \frac{r \Delta \theta}{\Delta t} \approx \frac{r (\frac{v \Delta t}{r})}{\Delta t} = \frac{v^2}{r}
  • The final equation for centripetal acceleration is ac=v2ra_c = \frac{v^2}{r} where aca_c is the centripetal acceleration, vv is the speed (magnitude of velocity), and rr is the radius of the circular path (Ferris wheel, orbiting satellite)
  • Angular velocity is related to centripetal acceleration by ac=rω2a_c = r\omega^2, where ω\omega is the angular velocity

Derivation of centripetal force

  • Newton's second law states that the net force acting on an object equals the product of its mass and acceleration Fnet=maF_{net} = ma
  • In uniform circular motion, the net force is the centripetal force FcF_c directed towards the center of the circle responsible for maintaining the curved path
  • Applying Newton's second law to circular motion gives Fc=macF_c = ma_c where aca_c is the centripetal acceleration
  • Substituting the equation for centripetal acceleration ac=v2ra_c = \frac{v^2}{r} into Newton's second law yields Fc=mv2rF_c = m \frac{v^2}{r}
  • The final equation for centripetal force is Fc=mv2rF_c = \frac{mv^2}{r} where FcF_c is the centripetal force, mm is the mass of the object, vv is the speed, and rr is the radius of the circular path (planet orbiting the sun, ball swinging on a string)

Problem-solving in circular motion

  • Identify the forces acting on the object in circular motion and determine which force provides the centripetal acceleration (tension in a string, gravity, friction, normal force)
  • Apply Newton's second law to the forces acting on the object by setting up the equation Fnet=macF_{net} = ma_c where FnetF_{net} is the net force acting towards the center of the circle
  • Substitute the equation for centripetal acceleration ac=v2ra_c = \frac{v^2}{r} into Newton's second law to get Fnet=mv2rF_{net} = m \frac{v^2}{r}
  • Use the given information (mass, speed, radius, or force) to solve for the unknown quantity by rearranging the equation as needed
  • If the speed or period of revolution is not given directly, use the relationships between speed, radius, and period to find the missing information
    1. Calculate the speed using the circumference of the circle and the period v=2πrTv = \frac{2\pi r}{T} where TT is the period of revolution
    2. Ensure consistent units throughout the problem and convert if necessary (m/s, km/h)
  • Examples of circular motion problems include calculating the tension in a rope swinging a mass horizontally, determining the speed of a car rounding a banked curve, or finding the minimum coefficient of friction needed to prevent slipping on a circular track

Forces in Circular Motion

  • Inertia: The tendency of an object to resist changes in its state of motion, which explains why objects in circular motion want to continue in a straight line
  • Centripetal force: The net force directed towards the center of the circular path that overcomes inertia and causes the object to follow a curved trajectory
  • Centrifugal force: An apparent outward force experienced by an object in a rotating reference frame, which is actually the result of inertia in the rotating system