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Du = t ds - p dv

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Thermodynamics I

Definition

The equation 'du = t ds - p dv' represents the differential change in internal energy (du) of a system in thermodynamics, connecting it to changes in entropy (ds) and volume (dv) under constant temperature and pressure conditions. It illustrates how internal energy is affected by heat transfer (t ds) and work done on or by the system (-p dv), providing a foundational relationship in understanding energy conservation and transformations.

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5 Must Know Facts For Your Next Test

  1. This equation is derived from the first law of thermodynamics, which states that energy cannot be created or destroyed, only transformed.
  2. In this expression, 't' represents temperature in absolute units (Kelvin), which is critical for calculating changes in entropy accurately.
  3. The term '-p dv' signifies that when a system expands (dv > 0), it does work on its surroundings, resulting in a decrease in internal energy.
  4. Conversely, if the system is compressed (dv < 0), work is done on the system, which can increase its internal energy.
  5. Understanding this relationship is crucial for solving problems related to heat engines, refrigeration cycles, and other thermodynamic processes.

Review Questions

  • How does the equation 'du = t ds - p dv' illustrate the first law of thermodynamics?
    • The equation 'du = t ds - p dv' directly embodies the first law of thermodynamics by showing how changes in internal energy (du) arise from heat transfer (t ds) and work interactions (-p dv). It indicates that any change in a system's internal energy is accounted for by the heat added to or removed from the system and the work done on or by the system. This reinforces the principle that energy is conserved in processes involving heat and work.
  • Discuss how changes in entropy (ds) and volume (dv) affect the internal energy (du) of a system based on this equation.
    • 'du = t ds - p dv' indicates that an increase in entropy at constant temperature contributes positively to the internal energy of a system. In contrast, an increase in volume leads to negative contributions due to work being done on the surroundings. Thus, if a system experiences an increase in entropy due to heat addition while keeping volume constant, its internal energy will rise. Conversely, if the system expands against external pressure without changing temperature, its internal energy will decrease. This relationship shows how different thermodynamic processes interplay with internal energy.
  • Evaluate how understanding 'du = t ds - p dv' can impact practical applications in thermal engineering.
    • 'du = t ds - p dv' provides critical insights for thermal engineering applications like heat engines and refrigerators by illustrating how energy transfer and transformations occur within these systems. Engineers can apply this relationship to optimize designs for efficiency by balancing heat input with work output or understanding how losses occur during energy conversion. For example, knowing how expanding gases do work against pressure can help improve engine designs to maximize output power while minimizing waste heat. Thus, mastering this equation allows engineers to create more effective systems across various thermal applications.

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