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Geometric distribution

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Preparatory Statistics

Definition

Geometric distribution is a probability distribution that models the number of trials needed to achieve the first success in a series of independent Bernoulli trials, where each trial has the same probability of success. It highlights scenarios where we are interested in the count of failures before the first success occurs, making it a key concept in understanding discrete probability distributions.

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5 Must Know Facts For Your Next Test

  1. The probability of getting the first success on the k-th trial is given by the formula $$P(X = k) = (1 - p)^{k-1}p$$, where p is the probability of success.
  2. Geometric distribution is memoryless, meaning that the probability of success in future trials does not depend on past trials.
  3. The expected value (mean) of a geometric distribution is given by $$E(X) = \frac{1}{p}$$, indicating how many trials are expected before the first success.
  4. The variance of a geometric distribution is calculated as $$Var(X) = \frac{1 - p}{p^2}$$, which shows how much variability there is around the expected number of trials.
  5. Geometric distribution can be used in real-world scenarios such as determining how many times one must roll a die until getting a six.

Review Questions

  • How does the geometric distribution differ from other discrete distributions in terms of its properties and applications?
    • The geometric distribution specifically focuses on counting the number of failures before the first success occurs in a series of independent trials, while other discrete distributions may model different scenarios such as total successes or outcomes over a fixed number of trials. This unique focus makes it particularly useful in applications like quality control or reliability testing, where understanding how long it takes to achieve a successful outcome is critical.
  • Using the formula for the geometric distribution, calculate the probability of needing exactly 5 trials to achieve the first success when the probability of success is 0.2.
    • To find the probability of needing exactly 5 trials for the first success with a success probability of 0.2, we use the formula $$P(X = 5) = (1 - 0.2)^{5-1}(0.2) = (0.8)^4(0.2)$$. Calculating this gives $$P(X = 5) = 0.4096 imes 0.2 = 0.08192$$. Thus, there is an approximately 8.192% chance that it will take exactly 5 trials to get the first success.
  • Evaluate how understanding geometric distribution can enhance decision-making processes in fields such as marketing or product development.
    • Understanding geometric distribution allows professionals in marketing and product development to predict outcomes and optimize strategies based on trial and error processes. For instance, if a company knows the probability of a customer making a purchase after seeing an advertisement, they can estimate how many ads need to be run before achieving their desired number of sales. This insight helps allocate resources efficiently and design targeted campaigns that maximize their chances of success while minimizing costs.
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