🥼organic chemistry review

NaOH

Written by the Fiveable Content Team • Last updated September 2025
Written by the Fiveable Content Team • Last updated September 2025

Definition

NaOH, or sodium hydroxide, is a highly alkaline chemical compound that plays a crucial role in various organic chemistry reactions and processes. It is a strong base that is widely used in a variety of applications, including the discovery of nucleophilic substitution reactions, the SN2 reaction, the E2 reaction, carbonyl condensations, and peptide sequencing through the Edman degradation.

5 Must Know Facts For Your Next Test

  1. NaOH is a strong base that is commonly used as a reagent in organic chemistry reactions to abstract a proton and generate a nucleophile.
  2. In the SN2 reaction, NaOH can act as a nucleophile, attacking the carbon bearing the leaving group and leading to inversion of stereochemistry.
  3. The E2 reaction, which involves the elimination of a leaving group and a proton, can be facilitated by the presence of NaOH as a base.
  4. NaOH can participate in carbonyl condensation reactions, such as the aldol condensation, by deprotonating the alpha-carbon and generating a nucleophilic enolate species.
  5. In the Edman degradation, a series of reactions used for peptide sequencing, NaOH is used to cleave the phenylthiohydantoin derivative from the peptide chain.

Review Questions

  • Explain how the strong basicity of NaOH makes it a useful reagent in nucleophilic substitution reactions.
    • The high pH and strong basicity of NaOH allow it to readily abstract a proton from an organic substrate, generating a nucleophilic species that can then participate in a substitution reaction. This deprotonation step is a crucial part of the mechanism for many nucleophilic substitution reactions, such as the SN2 reaction, where NaOH can act as the nucleophile and displace a leaving group, leading to the inversion of stereochemistry at the carbon center.
  • Describe the role of NaOH in the E2 reaction and its influence on the deuterium isotope effect.
    • In the E2 reaction, NaOH serves as a strong base that can deprotonate the substrate, generating an alkoxide ion that then undergoes elimination of a leaving group and a proton. The presence of NaOH can also affect the deuterium isotope effect observed in the E2 reaction, as the basicity of the reagent influences the rate-determining step and the relative reactivity of the C-H and C-D bonds.
  • Analyze the involvement of NaOH in carbonyl condensation reactions and compare its role to that in alpha-substitution reactions.
    • NaOH plays a crucial role in carbonyl condensation reactions, such as the aldol condensation, by deprotonating the alpha-carbon of the carbonyl compound and generating a nucleophilic enolate species. This enolate can then attack another carbonyl compound, leading to the formation of a new carbon-carbon bond. In contrast, in alpha-substitution reactions, NaOH may be used to abstract a proton from the alpha-carbon, but the subsequent reactivity involves the replacement of a substituent rather than the formation of a new bond.