study guides for every class

that actually explain what's on your next test

NaOH

from class:

Organic Chemistry

Definition

NaOH, or sodium hydroxide, is a highly alkaline chemical compound that plays a crucial role in various organic chemistry reactions and processes. It is a strong base that is widely used in a variety of applications, including the discovery of nucleophilic substitution reactions, the SN2 reaction, the E2 reaction, carbonyl condensations, and peptide sequencing through the Edman degradation.

congrats on reading the definition of NaOH. now let's actually learn it.

ok, let's learn stuff

5 Must Know Facts For Your Next Test

  1. NaOH is a strong base that is commonly used as a reagent in organic chemistry reactions to abstract a proton and generate a nucleophile.
  2. In the SN2 reaction, NaOH can act as a nucleophile, attacking the carbon bearing the leaving group and leading to inversion of stereochemistry.
  3. The E2 reaction, which involves the elimination of a leaving group and a proton, can be facilitated by the presence of NaOH as a base.
  4. NaOH can participate in carbonyl condensation reactions, such as the aldol condensation, by deprotonating the alpha-carbon and generating a nucleophilic enolate species.
  5. In the Edman degradation, a series of reactions used for peptide sequencing, NaOH is used to cleave the phenylthiohydantoin derivative from the peptide chain.

Review Questions

  • Explain how the strong basicity of NaOH makes it a useful reagent in nucleophilic substitution reactions.
    • The high pH and strong basicity of NaOH allow it to readily abstract a proton from an organic substrate, generating a nucleophilic species that can then participate in a substitution reaction. This deprotonation step is a crucial part of the mechanism for many nucleophilic substitution reactions, such as the SN2 reaction, where NaOH can act as the nucleophile and displace a leaving group, leading to the inversion of stereochemistry at the carbon center.
  • Describe the role of NaOH in the E2 reaction and its influence on the deuterium isotope effect.
    • In the E2 reaction, NaOH serves as a strong base that can deprotonate the substrate, generating an alkoxide ion that then undergoes elimination of a leaving group and a proton. The presence of NaOH can also affect the deuterium isotope effect observed in the E2 reaction, as the basicity of the reagent influences the rate-determining step and the relative reactivity of the C-H and C-D bonds.
  • Analyze the involvement of NaOH in carbonyl condensation reactions and compare its role to that in alpha-substitution reactions.
    • NaOH plays a crucial role in carbonyl condensation reactions, such as the aldol condensation, by deprotonating the alpha-carbon of the carbonyl compound and generating a nucleophilic enolate species. This enolate can then attack another carbonyl compound, leading to the formation of a new carbon-carbon bond. In contrast, in alpha-substitution reactions, NaOH may be used to abstract a proton from the alpha-carbon, but the subsequent reactivity involves the replacement of a substituent rather than the formation of a new bond.
© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
Glossary
Guides