Honors Algebra II

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Extraneous Solutions

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Honors Algebra II

Definition

Extraneous solutions are solutions that arise from the process of solving an equation but do not satisfy the original equation. They often occur in equations that involve rational expressions or square roots, where certain manipulations can introduce these false solutions. Identifying and eliminating extraneous solutions is crucial to ensure that the final answers are valid and applicable to the problem being solved.

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5 Must Know Facts For Your Next Test

  1. Extraneous solutions often appear when solving rational equations due to the need to multiply both sides by a variable expression that may equal zero, leading to invalid solutions.
  2. When dealing with square root equations, squaring both sides can introduce extraneous solutions that do not work in the original equation.
  3. It’s essential to check all potential solutions in the context of the original equation to determine if they are extraneous.
  4. Extraneous solutions can be easily identified if they cause any denominator in the original equation to equal zero.
  5. In some cases, a problem may have no extraneous solutions, meaning all found solutions satisfy the original equation.

Review Questions

  • How do extraneous solutions arise when solving rational equations, and why is it important to identify them?
    • Extraneous solutions arise during the process of solving rational equations, particularly when multiplying through by expressions that contain variables. This can create false solutions since these expressions may equal zero for certain variable values. Identifying these extraneous solutions is crucial because they do not satisfy the original equation and could lead to incorrect conclusions if accepted as valid answers.
  • Explain how squaring both sides of a square root equation can lead to extraneous solutions and provide an example.
    • When squaring both sides of a square root equation, you may inadvertently introduce extraneous solutions that do not hold true for the original equation. For example, consider the equation $$ ext{√}(x+3) = 5$$. Squaring both sides gives $$x + 3 = 25$$, leading to $$x = 22$$. However, substituting back into the original equation shows that it holds true. If we instead had $$ ext{√}(x) = -3$$ and squared both sides, we'd find $$x = 9$$, which doesn’t satisfy the original because square roots cannot equal negative numbers.
  • Evaluate a scenario where multiple solutions are found for a rational equation, and discuss how you would determine which ones are extraneous.
    • If you solve a rational equation like $$\frac{1}{x-2} = 3$$ and find potential solutions $x = 3$ and $x = 1$, you must check these in the original equation. For $x = 3$, substituting gives $$\frac{1}{3-2} = 1$$ which is valid; however, checking $x = 1$ results in $$\frac{1}{1-2} = -1$$ which does not match 3. This process helps identify $x = 1$ as an extraneous solution since it does not satisfy the original condition set by the equation.
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