study guides for every class

that actually explain what's on your next test

Invertible Matrix

from class:

Honors Pre-Calculus

Definition

An invertible matrix is a square matrix that has an inverse matrix. In other words, it is a matrix that can be multiplied by another matrix to produce the identity matrix, which means that the original matrix can be 'undone' or reversed.

congrats on reading the definition of Invertible Matrix. now let's actually learn it.

ok, let's learn stuff

5 Must Know Facts For Your Next Test

  1. A matrix is invertible if and only if its determinant is non-zero.
  2. The inverse of an invertible matrix $A$ is denoted as $A^{-1}$, and satisfies the equation $A^{-1}A = AA^{-1} = I$, where $I$ is the identity matrix.
  3. If a matrix is not invertible, it is said to be singular, and its determinant is zero.
  4. Invertible matrices play a crucial role in solving systems of linear equations using the inverse method, as described in section 9.7.
  5. The inverse of a 2x2 matrix $\begin{bmatrix} a & b \\ c & d \end{bmatrix}$ is $\frac{1}{ad-bc} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix}$.

Review Questions

  • Explain the relationship between the determinant of a matrix and its invertibility.
    • The determinant of a matrix is a key property that determines whether the matrix is invertible or not. A matrix is invertible if and only if its determinant is non-zero. If the determinant is zero, the matrix is said to be singular and it does not have an inverse. The determinant can be thought of as a measure of the 'size' or 'volume' of the matrix, and a non-zero determinant indicates that the matrix can be 'undone' or reversed.
  • Describe how invertible matrices are used to solve systems of linear equations, as discussed in section 9.7.
    • In section 9.7, the concept of invertible matrices is used to solve systems of linear equations. If a system of linear equations can be represented in matrix form as $Ax = b$, where $A$ is the coefficient matrix, $x$ is the vector of unknowns, and $b$ is the vector of constants, then the system can be solved by multiplying both sides by the inverse of $A$, denoted as $A^{-1}$. This gives $x = A^{-1}b$, which provides the unique solution to the system, provided that $A$ is invertible (i.e., its determinant is non-zero).
  • Explain how to find the inverse of a 2x2 matrix, and discuss the significance of this result.
    • The inverse of a 2x2 matrix $\begin{bmatrix} a & b \\ c & d \end{bmatrix}$ can be calculated using the formula $\frac{1}{ad-bc} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix}$. This formula shows that the inverse of a 2x2 matrix depends on the determinant of the matrix, $ad-bc$. If this determinant is non-zero, then the matrix is invertible, and the inverse can be used to solve systems of linear equations involving 2 variables. The ability to easily compute the inverse of a 2x2 matrix is an important result that simplifies the process of solving systems of linear equations in this context.
© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.