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๐ŸฌHonors Algebra II Unit 5 Review

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5.2 Complex Numbers and Operations

5.2 Complex Numbers and Operations

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
๐ŸฌHonors Algebra II
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Complex Number Representation

Complex numbers extend the real number system so that every polynomial equation has a solution. Without them, an equation like x2+1=0x^2 + 1 = 0 simply has no answer. With complex numbers, it has two: x=ix = i and x=โˆ’ix = -i.

This section covers how complex numbers are written, how to perform arithmetic with them, and how they connect back to quadratic equations with negative discriminants.

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Definition and Components

A complex number takes the form a+bia + bi, where aa and bb are real numbers and ii is the imaginary unit, defined by the property i2=โˆ’1i^2 = -1.

  • The real part is aa
  • The imaginary part is bb (just the coefficient, not bibi)
  • Examples: 3+2i3 + 2i, โˆ’4โˆ’7i-4 - 7i, 6i6i (here a=0a = 0), and 55 (here b=0b = 0, so every real number is also a complex number)

Rectangular Form and the Complex Plane

In rectangular form (a+bi)(a + bi), you can plot any complex number as a point on the complex plane (also called the Argand plane). The horizontal axis is the real axis, and the vertical axis is the imaginary axis. So 3+2i3 + 2i corresponds to the point (3,2)(3, 2).

The absolute value (or modulus) of a complex number is its distance from the origin, calculated with the Pythagorean theorem:

โˆฃa+biโˆฃ=a2+b2|a + bi| = \sqrt{a^2 + b^2}

For example, โˆฃ3+4iโˆฃ=9+16=5|3 + 4i| = \sqrt{9 + 16} = 5.

Polar Form

In polar form, a complex number is written as r(cosโกฮธ+isinโกฮธ)r(\cos\theta + i\sin\theta), where:

  • rr is the modulus (distance from the origin)
  • ฮธ\theta is the argument, the angle measured counterclockwise from the positive real axis

You can find ฮธ\theta using ฮธ=arctanโก(b/a)\theta = \arctan(b/a), but you need to adjust based on which quadrant the point falls in. For instance, if both aa and bb are negative, the point is in Quadrant III, and you'd add ฯ€\pi (or 180ยฐ) to the arctangent result.

Polar form is especially useful for multiplication and finding powers of complex numbers, since you can multiply moduli and add angles directly.

Complex Number Arithmetic

Definition and Components, Use the Complex Number System ยท Intermediate Algebra

Addition and Subtraction

Add or subtract the real and imaginary parts separately:

(a+bi)ยฑ(c+di)=(aยฑc)+(bยฑd)i(a + bi) \pm (c + di) = (a \pm c) + (b \pm d)i

Example: (3+2i)+(4โˆ’5i)=(3+4)+(2โˆ’5)i=7โˆ’3i(3 + 2i) + (4 - 5i) = (3 + 4) + (2 - 5)i = 7 - 3i

Think of it like combining like terms: real with real, imaginary with imaginary.

Multiplication

Multiply complex numbers using the distributive property (FOIL), then apply i2=โˆ’1i^2 = -1:

(a+bi)(c+di)=ac+adi+bci+bdi2=(acโˆ’bd)+(ad+bc)i(a + bi)(c + di) = ac + adi + bci + bdi^2 = (ac - bd) + (ad + bc)i

Example: (2+3i)(4โˆ’i)(2 + 3i)(4 - i)

  1. Multiply: 2โ‹…4+2โ‹…(โˆ’i)+3iโ‹…4+3iโ‹…(โˆ’i)=8โˆ’2i+12iโˆ’3i22 \cdot 4 + 2 \cdot (-i) + 3i \cdot 4 + 3i \cdot (-i) = 8 - 2i + 12i - 3i^2

  2. Replace i2i^2 with โˆ’1-1: 8โˆ’2i+12iโˆ’3(โˆ’1)=8+3+10i8 - 2i + 12i - 3(-1) = 8 + 3 + 10i

  3. Result: 11+10i11 + 10i

Conjugates

The conjugate of a+bia + bi is aโˆ’bia - bi. You flip the sign of the imaginary part. The key property: multiplying a complex number by its conjugate always gives a real number.

(a+bi)(aโˆ’bi)=a2+b2(a + bi)(a - bi) = a^2 + b^2

This fact is what makes division possible.

Division

To divide complex numbers, multiply the numerator and denominator by the conjugate of the denominator. This eliminates the imaginary part from the denominator.

Example: (3+4i)รท(1โˆ’2i)(3 + 4i) \div (1 - 2i)

  1. Multiply top and bottom by the conjugate of the denominator: (3+4i)(1+2i)(1โˆ’2i)(1+2i)\frac{(3 + 4i)(1 + 2i)}{(1 - 2i)(1 + 2i)}

  2. Expand the numerator: 3+6i+4i+8i2=3+10iโˆ’8=โˆ’5+10i3 + 6i + 4i + 8i^2 = 3 + 10i - 8 = -5 + 10i

  3. Expand the denominator: 1+4=51 + 4 = 5

  4. Simplify: โˆ’5+10i5=โˆ’1+2i\frac{-5 + 10i}{5} = -1 + 2i

A common mistake: forgetting to distribute to both terms in the numerator when multiplying by the conjugate. Be careful with signs.

Definition and Components, Number Sets

Complex Solutions to Quadratics

Quadratic Formula and Discriminant

The quadratic formula solves any equation of the form ax2+bx+c=0ax^2 + bx + c = 0:

x=โˆ’bยฑb2โˆ’4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The discriminant is the expression under the square root: b2โˆ’4acb^2 - 4ac. It tells you what kind of solutions to expect:

  • Positive discriminant: two distinct real solutions
  • Zero discriminant: one repeated real solution
  • Negative discriminant: two complex conjugate solutions

When the discriminant is negative, you'll factor out ii from the square root of the negative number.

Example: Solve x2+2x+5=0x^2 + 2x + 5 = 0

  1. Identify a=1a = 1, b=2b = 2, c=5c = 5

  2. Compute the discriminant: 22โˆ’4(1)(5)=4โˆ’20=โˆ’162^2 - 4(1)(5) = 4 - 20 = -16

  3. Apply the formula: x=โˆ’2ยฑโˆ’162x = \frac{-2 \pm \sqrt{-16}}{2}

  4. Simplify โˆ’16=4i\sqrt{-16} = 4i: x=โˆ’2ยฑ4i2=โˆ’1ยฑ2ix = \frac{-2 \pm 4i}{2} = -1 \pm 2i

The two solutions are โˆ’1+2i-1 + 2i and โˆ’1โˆ’2i-1 - 2i. Notice they're conjugates of each other. This always happens when the coefficients of the quadratic are real numbers.

Sum and Product of Complex Solutions

For ax2+bx+c=0ax^2 + bx + c = 0, regardless of whether the solutions are real or complex:

  • Sum of solutions =โˆ’b/a= -b/a
  • Product of solutions =c/a= c/a

These relationships come from Vieta's formulas and give you a quick way to check your work.

Example: For x2+2x+5=0x^2 + 2x + 5 = 0, the solutions are โˆ’1+2i-1 + 2i and โˆ’1โˆ’2i-1 - 2i.

  • Sum: (โˆ’1+2i)+(โˆ’1โˆ’2i)=โˆ’2(-1 + 2i) + (-1 - 2i) = -2, which matches โˆ’b/a=โˆ’2/1=โˆ’2-b/a = -2/1 = -2 โœ“
  • Product: (โˆ’1+2i)(โˆ’1โˆ’2i)=1+4=5(-1 + 2i)(-1 - 2i) = 1 + 4 = 5, which matches c/a=5/1=5c/a = 5/1 = 5 โœ“

Geometric Interpretation of Complex Numbers

The Complex Plane (Argand Plane)

Every complex number a+bia + bi maps to a unique point (a,b)(a, b) on the complex plane. This gives you a visual way to think about complex arithmetic:

  • The modulus โˆฃa+biโˆฃ|a + bi| is the point's distance from the origin
  • The argument ฮธ\theta is the angle from the positive real axis to the line connecting the origin to the point

Adding two complex numbers works just like vector addition: you're combining their horizontal and vertical components.

Geometric Transformations

Operations on complex numbers have clean geometric meanings:

  • Multiplying by ii rotates a point 90ยฐ counterclockwise. For example, iโ‹…(2+3i)=2i+3i2=โˆ’3+2ii \cdot (2 + 3i) = 2i + 3i^2 = -3 + 2i. The point (2,3)(2, 3) moves to (โˆ’3,2)(-3, 2).
  • Multiplying by โˆ’i-i rotates a point 90ยฐ clockwise.
  • Taking the conjugate reflects a point across the real axis. The conjugate of 2+3i2 + 3i is 2โˆ’3i2 - 3i, so (2,3)(2, 3) reflects to (2,โˆ’3)(2, -3).
  • Multiplying by a real number kk scales the distance from the origin by a factor of โˆฃkโˆฃ|k| (dilation). If kk is negative, it also rotates 180ยฐ.

Multiplying two complex numbers in polar form is especially elegant: you multiply their moduli and add their arguments. That's why polar form is so useful for repeated multiplication and powers.