Unit 10 is about the four curves you get by slicing a double cone with a plane: circles, parabolas, ellipses and hyperbolas. By the end, you should be able to write and graph each one in standard form, find its center or focus and, for an ellipse or hyperbola, its foci, and solve systems where these curves intersect.
Read the overview first, then work through each topic's notes and try the check-yourself question before peeking at the answer.
Conic sections show up when a plane cuts through a double cone at different angles. In algebra, each one is a second-degree equation in x and y. This unit teaches you to recognize which conic an equation describes, rewrite it in a form you can graph, and find where curves meet.
Honors Algebra II Unit 10 covers conic sections. You learn the distance-based definitions and standard-form equations of circles, parabolas, ellipses and hyperbolas, and you use completing the square to convert expanded equations into standard form. You find centers, vertices, foci, directrices and asymptotes, and you graph each curve. The unit ends with solving nonlinear systems, such as a line and a circle or two conics, using substitution and elimination.
Each conic is defined by distances to a center, a focus, or two foci.
A circle keeps a fixed distance from its center. A parabola stays equally far from a focus and a directrix line. An ellipse keeps the sum of distances to two foci constant, and a hyperbola keeps the absolute difference of those distances constant.
Standard form lets you read the graph straight off the equation.
In (x−h)2+(y−k)2=r2 you can see the center (h,k) and radius r right away. The same goes for the vertex and p in a parabola, or a, b and the center in an ellipse or hyperbola. When an equation is expanded, completing the square brings it back to standard form.
Solving a system with conics means finding the points that satisfy both equations.
Substitution and elimination still work, but the result is usually a quadratic, so you can get 0, 1, 2 or more solutions. A line and a nondegenerate conic meet at most 2 times, and two distinct nondegenerate conics meet at most 4 times.
Conic sections are the graphs of second-degree equations in two variables.
A general second-degree equation has the form Ax2+Bxy+Cy2+Dx+Ey+F=0. It can describe a conic, a degenerate graph such as a point or a pair of lines, or no real points. When B=0 and the graph is a nondegenerate conic, A=C=0 gives a circle, nonzero A and C with the same sign but different values give an ellipse, opposite signs give a hyperbola, and exactly one nonzero squared coefficient gives a parabola. An xy term can indicate a rotated conic.
A circle is every point at distance r from a center (h,k), which gives (x−h)2+(y−k)2=r2. That equation is the distance formula squared. A parabola is every point that is the same distance from a fixed point, the focus, and a fixed line, the directrix.
For a parabola with vertex (h,k) that opens up or down, use (x−h)2=4p(y−k). The focus is ∣p∣ units from the vertex along the axis of symmetry, and the directrix is ∣p∣ units away on the opposite side. It opens up when p>0 and down when p<0. If y is the squared variable, (y−k)2=4p(x−h), the parabola opens right when p>0 and left when p<0. This matches vertex form y=a(x−h)2+k with a=4p1.
Circles often appear expanded, as in x2+y2+Dx+Ey+F=0. Complete the square in x and in y to get standard form back.
Worked example. Find the center and radius of x2+y2−6x+4y−12=0. Group terms and move the constant, which gives (x2−6x)+(y2+4y)=12. Half of −6 is −3 and (−3)2=9. Half of 4 is 2 and 22=4. Add 9 and 4 to both sides to get (x−3)2+(y+2)2=25. The center is (3,−2) and the radius is 5.
Focus of a parabola:The fixed point inside the curve, ∣p∣|p|∣p∣ units from the vertex, that every point on the parabola is equally distant from as it is from the directrix.
Directrix:The fixed line ∣p∣|p|∣p∣ units from the vertex on the side opposite the focus, perpendicular to the axis of symmetry.
Completing the square:Adding (b2)2(\frac{b}{2})^2(2b)2 to both sides so that x2+bxx^2+bxx2+bx becomes a perfect square (x+b2)2(x+\frac{b}{2})^2(x+2b)2.
Check yourself: Where are the focus and directrix of x2=8y? (Answer: 4p=8, so p=2. The vertex is (0,0), the focus is (0,2), and the directrix is y=−2.)
10.2
Ellipses and Hyperbolas
An ellipse is every point where the sum of the distances to two foci is constant. A hyperbola is every point where the absolute difference of those distances is a positive constant. The standard-form equation for an ellipse uses a plus sign between its squared terms, while a hyperbola uses a minus sign.
An ellipse centered at (h,k) is a2(x−h)2+b2(y−k)2=1 or the same with the denominators switched. The larger denominator is always a2, and it sits under the variable of the major axis. The foci satisfy c2=a2−b2, so they lie inside the curve.
A hyperbola has a minus sign between the fractions. The positive term tells you the direction the branches open, and a2 is always under that term, even if it is the smaller number. The foci satisfy c2=a2+b2, so they lie beyond the vertices. The asymptotes pass through the center along the diagonals of a rectangle centered there, with side lengths 2a along the transverse axis and 2b along the other axis.
Worked example. For 25x2+9y2=1, a=5 and b=3, so c2=25−9=16 and c=4. The vertices are (±5,0) and the foci are (±4,0). For 9x2−16y2=1, a=3 and b=4, so c2=9+16=25 and c=5. The vertices are (±3,0), the foci are (±5,0), and the asymptotes are y=±34x.
Major axis:The longer axis of an ellipse, with length 2a2a2a, which contains the vertices and the foci.
Transverse axis:The axis of a hyperbola that connects its two vertices and contains the foci, with length 2a2a2a.
Asymptotes of a hyperbola:Two lines through the center that the branches approach, with slopes ±ba\pm\frac{b}{a}±ab for a horizontal hyperbola and ±ab\pm\frac{a}{b}±ba for a vertical one.
Eccentricity:A number that describes a conic's shape. For a circle, ellipse or hyperbola, e=cae=\frac{c}{a}e=ac. A circle has e=0e=0e=0, a noncircular ellipse has 0<e<10<e<10<e<1, a parabola has e=1e=1e=1, and a hyperbola has e>1e>1e>1.
Check yourself: Which way does 4y2−9x2=1 open, and where are its foci? (Answer: The y term is positive, so it opens up and down. a2=4 and b2=9, so c2=13 and the foci are (0,±13).)
Feature
Ellipse
Hyperbola
Distance definition
Sum of distances to foci is constant
Absolute difference of distances to foci is constant
Sign between terms
Plus
Minus
Where $a^2$ goes
Under the larger denominator
Under the positive term
Focus formula
$c^2=a^2-b^2$
$c^2=a^2+b^2$
Foci location
Inside the curve, $c<a$
Beyond the vertices, $c>a$
Eccentricity
$0<e<1$
$e>1$
Asymptotes
None
Two lines through the center
10.3
Solving Systems Involving Conic Sections
A solution to a system is a point that lies on both graphs. Sketching the curves first tells you roughly how many solutions to expect and where they are.
For a line and a conic, solve the linear equation for one variable and substitute it into the conic. The result can be quadratic or linear, and a nondegenerate conic and a line have 0, 1 or 2 intersection points. If the result is quadratic, a discriminant of 0 gives one repeated solution and a tangent line. A linear result can also give one intersection without tangency.
For two conics with only squared terms, elimination is usually faster. For example, adding x2+y2=25 and x2−y2=7 gives 2x2=32, so x=±4 and then y=±3, for four solutions. Two distinct nondegenerate conics can meet at up to 4 points.
Worked example. Solve x2+y2=25 and y=x+1. Substitute to get x2+(x+1)2=25. Expand to get 2x2+2x+1=25, then x2+x−12=0. Factor as (x+4)(x−3)=0, so x=3 or x=−4. Plug back into y=x+1 to get (3,4) and (−4,−3). Both check, since 9+16=25 and 16+9=25.
In word problems, throw out solutions that don't fit the context, like a negative distance.
Nonlinear system:A system where at least one equation is not a line, such as a circle, parabola, ellipse or hyperbola.
Tangent:A line that has the same direction as a smooth curve at a point where they meet. Two smooth curves are tangent at a shared point when they have the same tangent line there.
Extraneous solution:A value produced by the algebra that does not satisfy both original equations or the context of the problem.
Check yourself: How many times does the line y=5 meet the circle x2+y2=25? (Answer: Once. Substituting gives x2=0, so the only point is (0,5) and the line is tangent to the circle.)
Key terms
Term
Definition
Conic section
A curve formed where a plane intersects a double cone, namely a circle, parabola, ellipse or hyperbola.
Standard form
A version of a conic's equation, such as $(x-h)^2+(y-k)^2=r^2$, that shows its center or vertex and its dimensions directly.
Focus
A fixed point used to define a conic, with one for a parabola and two (called foci) for an ellipse or hyperbola.
Directrix
The fixed line that, together with the focus, defines a parabola as all points equally distant from both.
Vertex
A point where a conic crosses its main axis of symmetry, such as the turning point of a parabola or an endpoint of an ellipse's major axis.
Co-vertex
An endpoint of an ellipse's minor axis, located $b$ units from the center.
Asymptote
A line through the center of a hyperbola that the branches get closer and closer to without reaching.
Eccentricity
A number that describes a conic's shape. For a circle, ellipse or hyperbola, $e=\frac{c}{a}$; for a parabola, $e=1$.
General form of a conic
The expanded second-degree equation $Ax^2+Bxy+Cy^2+Dx+Ey+F=0$. It can describe a conic, a degenerate graph or no real points; an $xy$ term can indicate a rotated conic.
Mistakes to avoid in Conic Sections
Using $c^2=a^2-b^2$ for a hyperbola
The ellipse formula sticks in your head and gets reused. Tie the sign to the equation. A plus sign between the fractions means the ellipse formula c2=a2−b2, and a minus sign means the hyperbola formula c2=a2+b2.
Assuming $a^2$ is always under $x$
Textbooks often show a2 under x2, so it is easy to treat that as a rule. For an ellipse, a2 is the larger denominator wherever it sits. For a hyperbola, a2 is under the positive term, even when it is smaller than b2.
Getting the sign of the center wrong
In (x+2)2+(y−5)2=9, the center is (−2,5), not (2,−5). Standard form uses x−h, so rewrite x+2 as x−(−2) to read h correctly. Also remember that the right side is r2, so the radius here is 3, not 9.
Dropping solutions in a system
When you take a square root, like x2=16, both x=4 and x=−4 count. Finding x is also only half the job, because each x can pair with one or two y values. Substitute every x back in and check each point in both original equations.