Calculus IV

Calculus IV Unit 1 – Vectors and Vector–Valued Functions

Vectors and vector-valued functions are essential tools in calculus, physics, and engineering. They allow us to describe quantities with both magnitude and direction, enabling us to model complex systems and phenomena in multiple dimensions. This unit covers vector operations, derivatives, and integrals of vector-valued functions. We'll explore applications like projectile motion, fluid dynamics, and electromagnetic fields, while also learning to avoid common pitfalls in vector calculations and interpretations.

Key Concepts and Definitions

  • Vectors quantities with both magnitude and direction (velocity, force, displacement)
  • Scalar quantities with only magnitude, no direction (speed, mass, time)
  • Vector components xx, yy, and zz values that describe a vector in terms of the standard unit vectors i^\hat{i}, j^\hat{j}, and k^\hat{k}
  • Vector magnitude v=vx2+vy2+vz2\|\vec{v}\| = \sqrt{v_x^2 + v_y^2 + v_z^2} length of the vector
    • Calculated using the Pythagorean theorem in 2D or 3D space
  • Unit vectors vectors with a magnitude of 1 that point in a specific direction
    • Standard unit vectors: i^\hat{i} (1, 0, 0), j^\hat{j} (0, 1, 0), and k^\hat{k} (0, 0, 1)
  • Vector equality two vectors are equal if and only if their corresponding components are equal
  • Zero vector 0\vec{0} has a magnitude of 0 and no specific direction

Vector Operations and Properties

  • Vector addition u+v=(ux+vx,uy+vy,uz+vz)\vec{u} + \vec{v} = (u_x + v_x, u_y + v_y, u_z + v_z) component-wise addition
    • Geometrically, vector addition follows the parallelogram law or the triangle law
  • Vector subtraction uv=(uxvx,uyvy,uzvz)\vec{u} - \vec{v} = (u_x - v_x, u_y - v_y, u_z - v_z) component-wise subtraction
  • Scalar multiplication multiplying a vector by a scalar changes its magnitude but not its direction
    • cv=(cvx,cvy,cvz)c\vec{v} = (cv_x, cv_y, cv_z), where cc is a scalar
  • Dot product (scalar product) uv=uxvx+uyvy+uzvz\vec{u} \cdot \vec{v} = u_xv_x + u_yv_y + u_zv_z results in a scalar value
    • Geometrically, uv=uvcosθ\vec{u} \cdot \vec{v} = \|\vec{u}\| \|\vec{v}\| \cos{\theta}, where θ\theta is the angle between the vectors
  • Cross product (vector product) u×v=(uyvzuzvy,uzvxuxvz,uxvyuyvx)\vec{u} \times \vec{v} = (u_yv_z - u_zv_y, u_zv_x - u_xv_z, u_xv_y - u_yv_x) results in a vector perpendicular to both u\vec{u} and v\vec{v}
    • Magnitude of the cross product: u×v=uvsinθ\|\vec{u} \times \vec{v}\| = \|\vec{u}\| \|\vec{v}\| \sin{\theta}
  • Scalar triple product u(v×w)\vec{u} \cdot (\vec{v} \times \vec{w}) determines the volume of a parallelepiped formed by the three vectors

Vector-Valued Functions

  • Vector-valued functions functions that assign a vector to each point in their domain
    • Example: r(t)=(x(t),y(t),z(t))\vec{r}(t) = (x(t), y(t), z(t)), where tt is usually time
  • Limit of a vector-valued function limtar(t)=(limtax(t),limtay(t),limtaz(t))\lim_{t \to a} \vec{r}(t) = (\lim_{t \to a} x(t), \lim_{t \to a} y(t), \lim_{t \to a} z(t)) component-wise limit
  • Continuity of a vector-valued function r(t)\vec{r}(t) is continuous if and only if its component functions x(t)x(t), y(t)y(t), and z(t)z(t) are continuous
  • Parametric curves curves in 2D or 3D space defined by a vector-valued function
    • Example: r(t)=(t2,t3)\vec{r}(t) = (t^2, t^3) defines a parametric curve in the xyxy-plane
  • Arc length L=abr(t)dtL = \int_a^b \|\vec{r}'(t)\| dt measures the length of a parametric curve over the interval [a,b][a, b]

Derivatives of Vector-Valued Functions

  • Derivative of a vector-valued function r(t)=(x(t),y(t),z(t))\vec{r}'(t) = (x'(t), y'(t), z'(t)) component-wise differentiation
    • Geometrically, the derivative represents the tangent vector to the curve at a given point
  • Second derivative r(t)=(x(t),y(t),z(t))\vec{r}''(t) = (x''(t), y''(t), z''(t)) component-wise second derivative
  • Tangent line to a curve r(t)\vec{r}(t) at t=t0t = t_0 is given by l(t)=r(t0)+(tt0)r(t0)\vec{l}(t) = \vec{r}(t_0) + (t - t_0)\vec{r}'(t_0)
  • Normal vector N(t)\vec{N}(t) vector perpendicular to the tangent vector at a given point
    • Unit normal vector: N^(t)=r(t)r(t)\hat{N}(t) = \frac{\vec{r}'(t)}{\|\vec{r}'(t)\|}
  • Binormal vector B(t)=T(t)×N(t)\vec{B}(t) = \vec{T}(t) \times \vec{N}(t) vector perpendicular to both the tangent and normal vectors
  • Curvature κ(t)=r(t)×r(t)r(t)3\kappa(t) = \frac{\|\vec{r}'(t) \times \vec{r}''(t)\|}{\|\vec{r}'(t)\|^3} measures how much a curve deviates from a straight line

Integrals of Vector-Valued Functions

  • Indefinite integral of a vector-valued function r(t)dt=(x(t)dt,y(t)dt,z(t)dt)\int \vec{r}(t) dt = (\int x(t) dt, \int y(t) dt, \int z(t) dt) component-wise integration
    • Constant of integration is a vector C=(Cx,Cy,Cz)\vec{C} = (C_x, C_y, C_z)
  • Definite integral of a vector-valued function abr(t)dt=(abx(t)dt,aby(t)dt,abz(t)dt)\int_a^b \vec{r}(t) dt = (\int_a^b x(t) dt, \int_a^b y(t) dt, \int_a^b z(t) dt) component-wise definite integration
  • Average value of a vector-valued function 1baabr(t)dt\frac{1}{b-a} \int_a^b \vec{r}(t) dt over the interval [a,b][a, b]
  • Center of mass rcm=abr(t)dmabdm\vec{r}_{cm} = \frac{\int_a^b \vec{r}(t) dm}{\int_a^b dm} for a system of particles or a continuous object
    • dmdm represents the mass element, which can be a discrete particle mass or a continuous mass distribution

Applications in Physics and Engineering

  • Position, velocity, and acceleration r(t)\vec{r}(t), v(t)=r(t)\vec{v}(t) = \vec{r}'(t), and a(t)=v(t)=r(t)\vec{a}(t) = \vec{v}'(t) = \vec{r}''(t)
    • Projectile motion: r(t)=(v0cosθt,v0sinθt12gt2)\vec{r}(t) = (v_0 \cos{\theta} t, v_0 \sin{\theta} t - \frac{1}{2}gt^2), where v0v_0 is the initial velocity, θ\theta is the launch angle, and gg is the acceleration due to gravity
  • Force F=ma\vec{F} = m\vec{a} Newton's second law of motion
    • Work done by a force: W=CFdrW = \int_C \vec{F} \cdot d\vec{r}, where CC is the path along which the force acts
  • Moment of a force (torque) τ=r×F\vec{\tau} = \vec{r} \times \vec{F} measures the tendency of a force to cause rotation
  • Fluid flow velocity fields v(x,y,z)\vec{v}(x, y, z) describe the velocity of a fluid at each point in space
    • Streamlines, pathlines, and streaklines help visualize fluid flow patterns
  • Electromagnetic fields electric field E(x,y,z)\vec{E}(x, y, z) and magnetic field B(x,y,z)\vec{B}(x, y, z) are vector fields that describe the forces acting on charged particles
    • Maxwell's equations govern the behavior of electromagnetic fields

Common Pitfalls and Misconceptions

  • Confusing scalar and vector quantities speed (scalar) vs. velocity (vector), distance (scalar) vs. displacement (vector)
  • Misunderstanding vector addition and subtraction geometrically or component-wise
    • Tip-to-tail method for vector addition and parallelogram law
  • Misinterpreting dot product and cross product results dot product yields a scalar, cross product yields a vector
    • Sign of the dot product indicates acute (>0> 0), obtuse (<0< 0), or perpendicular (=0= 0) angles between vectors
  • Forgetting to normalize vectors when finding unit tangent, normal, or binormal vectors
  • Incorrectly applying the chain rule when differentiating vector-valued functions
    • ddtr(t)=r(t)dtdt=r(t)\frac{d}{dt} \vec{r}(t) = \vec{r}'(t) \frac{dt}{dt} = \vec{r}'(t), not ddtr(t)=(ddtx(t),ddty(t),ddtz(t))\frac{d}{dt} \vec{r}(t) = (\frac{d}{dt} x(t), \frac{d}{dt} y(t), \frac{d}{dt} z(t))
  • Misinterpreting the meaning of the integral of a vector-valued function
    • Indefinite integral yields a vector-valued function, definite integral yields a vector

Practice Problems and Solutions

  1. Find the unit vector in the direction of v=(3,4,0)\vec{v} = (3, -4, 0).

    • Solution: v^=vv=(35,45,0)\hat{v} = \frac{\vec{v}}{\|\vec{v}\|} = (\frac{3}{5}, -\frac{4}{5}, 0)
  2. Determine the angle between the vectors u=(1,2,1)\vec{u} = (1, 2, -1) and v=(2,0,3)\vec{v} = (2, 0, 3).

    • Solution: cosθ=uvuv=5613\cos{\theta} = \frac{\vec{u} \cdot \vec{v}}{\|\vec{u}\| \|\vec{v}\|} = \frac{5}{\sqrt{6} \sqrt{13}}, so θ49.9°\theta \approx 49.9°
  3. Find the area of the parallelogram formed by the vectors a=(1,2)\vec{a} = (1, 2) and b=(3,1)\vec{b} = (-3, 1).

    • Solution: Area =a×b=(2,7)=53= \|\vec{a} \times \vec{b}\| = \|(-2, -7)\| = \sqrt{53}
  4. Given the vector-valued function r(t)=(t2,sint,et)\vec{r}(t) = (t^2, \sin{t}, e^t), find r(t)\vec{r}'(t) and r(t)\vec{r}''(t).

    • Solution: r(t)=(2t,cost,et)\vec{r}'(t) = (2t, \cos{t}, e^t) and r(t)=(2,sint,et)\vec{r}''(t) = (2, -\sin{t}, e^t)
  5. Evaluate the definite integral 01(3t2,2t,1)dt\int_0^1 (3t^2, 2t, 1) dt.

    • Solution: 01(3t2,2t,1)dt=(1,1,1)\int_0^1 (3t^2, 2t, 1) dt = (1, 1, 1)
  6. A particle moves along the curve r(t)=(2cost,2sint,t)\vec{r}(t) = (2\cos{t}, 2\sin{t}, t). Find its speed at t=π4t = \frac{\pi}{4}.

    • Solution: Speed =r(t)=(2sint)2+(2cost)2+12=5= \|\vec{r}'(t)\| = \sqrt{(-2\sin{t})^2 + (2\cos{t})^2 + 1^2} = \sqrt{5} at t=π4t = \frac{\pi}{4}
  7. Find the work done by the force F(x,y)=(x2,y)\vec{F}(x, y) = (x^2, y) along the path r(t)=(t,t2)\vec{r}(t) = (t, t^2) from t=0t = 0 to t=1t = 1.

    • Solution: W=CFdr=01(t2,t2)(1,2t)dt=01(t2+2t3)dt=712W = \int_C \vec{F} \cdot d\vec{r} = \int_0^1 (t^2, t^2) \cdot (1, 2t) dt = \int_0^1 (t^2 + 2t^3) dt = \frac{7}{12}
  8. Determine the curvature of the helix r(t)=(cost,sint,t)\vec{r}(t) = (\cos{t}, \sin{t}, t) at t=π2t = \frac{\pi}{2}.

    • Solution: κ(t)=r(t)×r(t)r(t)3=12\kappa(t) = \frac{\|\vec{r}'(t) \times \vec{r}''(t)\|}{\|\vec{r}'(t)\|^3} = \frac{1}{\sqrt{2}} at t=π2t = \frac{\pi}{2}


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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.