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โž—Calculus II Unit 7 Review

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7.1 Parametric Equations

7.1 Parametric Equations

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
โž—Calculus II
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Parametric Equations

Parametric equations describe curves by expressing both xx and yy as separate functions of an independent parameter, usually tt. Instead of writing yy directly as a function of xx, you let both coordinates change with tt, which makes it possible to represent curves that loop, backtrack, or trace complex paths. This is especially useful for modeling motion, where tt often represents time.

Plotting Parametric Curves

A parametric curve is defined by a pair of functions x(t)x(t) and y(t)y(t). As tt varies over some interval, the point (x(t),y(t))(x(t), y(t)) traces out a curve in the xyxy-plane.

To plot a parametric curve:

  1. Choose a range of tt values (for example, 0โ‰คtโ‰ค2ฯ€0 \leq t \leq 2\pi).
  2. Evaluate x(t)x(t) and y(t)y(t) at several values of tt to get (x,y)(x, y) coordinate pairs.
  3. Plot those points on the coordinate plane and connect them in order of increasing tt.

The direction you connect the points matters. The curve has an orientation determined by the direction of increasing tt, which you can indicate with arrows.

  • Circle: x=cosโก(t)x = \cos(t), y=sinโก(t)y = \sin(t), 0โ‰คtโ‰ค2ฯ€0 \leq t \leq 2\pi traces the unit circle counterclockwise starting at (1,0)(1, 0).
  • Spiral: x=tcosโก(t)x = t\cos(t), y=tsinโก(t)y = t\sin(t), 0โ‰คtโ‰ค4ฯ€0 \leq t \leq 4\pi traces a spiral that moves outward from the origin as tt increases, since the factor of tt grows the radius over time.
Plotting parametric curves, Calculus of Parametric Curves ยท Calculus

Conversion to Rectangular Form

Converting parametric equations to rectangular form means eliminating the parameter tt to get a single equation relating xx and yy. This can help you recognize what type of curve you're dealing with (a line, ellipse, parabola, etc.).

Common elimination strategies:

  • Solve and substitute: Solve one parametric equation for tt, then plug that expression into the other equation.
  • Use trig identities: When xx and yy involve sinโก(t)\sin(t) and cosโก(t)\cos(t), the Pythagorean identity sinโก2(t)+cosโก2(t)=1\sin^2(t) + \cos^2(t) = 1 is your best friend.
  • Algebraic manipulation: Square, add, or rearrange the equations to cancel tt.

Example: Convert x=2cosโก(t)x = 2\cos(t), y=3sinโก(t)y = 3\sin(t) to rectangular form.

  1. Isolate the trig functions: cosโก(t)=x2\cos(t) = \frac{x}{2}, sinโก(t)=y3\sin(t) = \frac{y}{3}.
  2. Apply the Pythagorean identity: cosโก2(t)+sinโก2(t)=1\cos^2(t) + \sin^2(t) = 1.
  3. Substitute: x24+y29=1\frac{x^2}{4} + \frac{y^2}{9} = 1.

This is the equation of an ellipse with semi-major axis 3 (along yy) and semi-minor axis 2 (along xx).

One thing to watch: the rectangular form sometimes includes more of the curve than the parametric version traces. Always check whether the parametric equations restrict the domain (for instance, only tracing the top half of an ellipse).

Plotting parametric curves, Parametric Equations: Graphs | Precalculus

Parametric Equations for Basic Shapes

Lines:

A parametric line through the point (a,c)(a, c) with direction vector โŸจb,dโŸฉ\langle b, d \rangle is written as:

x=a+bt,y=c+dtx = a + bt, \quad y = c + dt

The slope of this line is db\frac{d}{b} (provided bโ‰ 0b \neq 0). For example, x=1+2tx = 1 + 2t, y=3+4ty = 3 + 4t passes through (1,3)(1, 3) with slope 42=2\frac{4}{2} = 2. You can verify by eliminating tt: solving the first equation gives t=xโˆ’12t = \frac{x - 1}{2}, and substituting into the second gives y=2x+1y = 2x + 1.

Circles:

A circle with center (h,k)(h, k) and radius rr has parametric equations:

x=h+rcosโก(t),y=k+rsinโก(t),0โ‰คtโ‰ค2ฯ€x = h + r\cos(t), \quad y = k + r\sin(t), \quad 0 \leq t \leq 2\pi

Here tt represents the angle measured from the positive xx-direction. For example, x=2+3cosโก(t)x = 2 + 3\cos(t), y=1+3sinโก(t)y = 1 + 3\sin(t) traces a circle centered at (2,1)(2, 1) with radius 3. Changing the interval of tt lets you trace just an arc instead of the full circle.

Interpretation of Cycloid Equations

A cycloid is the curve traced by a point on the rim of a circle as that circle rolls along a straight line without slipping. Picture a reflector on a bicycle tire as the bike moves forward.

The parametric equations for a cycloid are:

x=r(tโˆ’sinโก(t)),y=r(1โˆ’cosโก(t))x = r(t - \sin(t)), \quad y = r(1 - \cos(t))

where rr is the radius of the rolling circle and tt is the angle (in radians) through which the circle has rotated.

Key properties:

  • The curve is periodic. Each full rotation (tt increases by 2ฯ€2\pi) produces one arch.
  • The xx-coordinate advances by 2ฯ€r2\pi r per arch, which equals the circumference of the rolling circle.
  • The yy-coordinate oscillates between 00 (where the point touches the line) and 2r2r (the top of each arch).
  • At the cusps (where tt is a multiple of 2ฯ€2\pi), the point touches the ground and the curve has a sharp point.

Example: For r=2r = 2, each arch spans 4ฯ€4\pi units horizontally, and the point rises to a maximum height of 44.

Cycloids show up in physics: the brachistochrone problem asks for the curve of fastest descent between two points under gravity, and the answer is an inverted cycloid. They also appear in gear tooth design and pendulum clocks.

Motion Analysis with Parametric Equations

When tt represents time, parametric equations naturally describe the motion of an object. You can extract velocity, acceleration, and tangent line information directly from x(t)x(t) and y(t)y(t).

Velocity vector: The velocity at time tt is

vโƒ—(t)=โŸจxโ€ฒ(t),โ€‰yโ€ฒ(t)โŸฉ\vec{v}(t) = \langle x'(t),\, y'(t) \rangle

This vector points in the direction of motion. Its magnitude, โˆฅvโƒ—(t)โˆฅ=[xโ€ฒ(t)]2+[yโ€ฒ(t)]2\|\vec{v}(t)\| = \sqrt{[x'(t)]^2 + [y'(t)]^2}, gives the speed of the object at that instant.

Acceleration vector: The acceleration is the derivative of velocity:

aโƒ—(t)=โŸจxโ€ฒโ€ฒ(t),โ€‰yโ€ฒโ€ฒ(t)โŸฉ\vec{a}(t) = \langle x''(t),\, y''(t) \rangle

Tangent line slope: The slope of the tangent line to the curve at any point is found using the chain rule:

dydx=dy/dtdx/dt,providedย dxdtโ‰ 0\frac{dy}{dx} = \frac{dy/dt}{dx/dt}, \quad \text{provided } \frac{dx}{dt} \neq 0

If dxdt=0\frac{dx}{dt} = 0 but dydtโ‰ 0\frac{dy}{dt} \neq 0, the tangent line is vertical. If both derivatives are zero simultaneously, you need further analysis (such as L'Hรดpital's Rule or examining limits) to determine the behavior at that point.