Fiveable

โž—Calculus II Unit 4 Review

QR code for Calculus II practice questions

4.3 Separable Equations

4.3 Separable Equations

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
โž—Calculus II
Unit & Topic Study Guides

Separable equations are a type of differential equation where you can isolate the variables on opposite sides of the equation. They show up constantly in modeling real-world scenarios like cooling, population growth, and radioactive decay. Mastering the technique here gives you a reliable method you'll use throughout the rest of differential equations.

Separable Equations

Solving separable differential equations

A separable equation is any differential equation that can be written in the form dydx=f(x)g(y)\frac{dy}{dx} = f(x)g(y), where the right-hand side is a product of a function of xx alone and a function of yy alone. That structure is what makes separation possible.

Here's the process for solving one:

  1. Separate the variables. Divide both sides by g(y)g(y) and multiply both sides by dxdx so that all yy-terms (including dydy) are on one side and all xx-terms (including dxdx) are on the other: 1g(y)โ€‰dy=f(x)โ€‰dx\frac{1}{g(y)}\,dy = f(x)\,dx

  2. Integrate both sides with respect to their own variable: โˆซ1g(y)โ€‰dy=โˆซf(x)โ€‰dx\int \frac{1}{g(y)}\,dy = \int f(x)\,dx These integrals may require techniques like uu-substitution, partial fractions, trig identities, or logarithmic rules (โˆซ1xโ€‰dx=lnโกโˆฃxโˆฃ+C\int \frac{1}{x}\,dx = \ln|x| + C).

  3. Solve for yy as a function of xx. This might mean exponentiating both sides if you end up with logarithms, or it might require some algebra. Don't forget the constant of integration, which appears as a single +C+C on one side (you don't need one on both sides since they combine).

  4. Apply the initial condition if one is given. Substitute the known point (x0,y0)(x_0, y_0) into your general solution and solve for CC. This pins down the one particular solution that passes through that point.

In some cases you won't be able to isolate yy explicitly, and the solution stays in implicit form. That's fine; an implicit solution is still a valid answer.

Solving separable differential equations, calculus - Understanding the relationship between differentiation and integration - Mathematics ...

Applications of separable equations

Solution concentrations. When the rate of change of a concentration is proportional to the current concentration, you get dCdt=kC\frac{dC}{dt} = kC, where kk is a constant (positive for growth, negative for decay). Separating and integrating gives C(t)=C0ektC(t) = C_0 e^{kt}, where C0C_0 is the initial concentration. You can use this to predict future concentrations or find how long it takes to reach a target value.

Newton's law of cooling. The rate of temperature change of an object is proportional to the difference between its temperature and the surrounding (ambient) temperature: dTdt=k(Tโˆ’Ta)\frac{dT}{dt} = k(T - T_a)

Here TaT_a is the ambient temperature and kk is a negative constant. Solving gives T(t)=Ta+(T0โˆ’Ta)ektT(t) = T_a + (T_0 - T_a)e^{kt}, which tells you the object's temperature at any time tt. For example, if coffee at 90ยฐC is placed in a 20ยฐC room, this model predicts how quickly it cools.

Other common models using the same separable structure:

  • Population growth: dPdt=kP\frac{dP}{dt} = kP models exponential growth (or decay if k<0k < 0)
  • Radioactive decay: dNdt=โˆ’ฮปN\frac{dN}{dt} = -\lambda N, where the decay constant ฮป\lambda determines the half-life
  • Compound interest (continuous): dAdt=rA\frac{dA}{dt} = rA, where rr is the interest rate and AA is the account value

Notice these all share the same form: the rate of change is proportional to the current amount. That's why the same separation technique solves all of them.

Solving separable differential equations, Linear Approximations and Differentials ยท Calculus

Analysis of separable equation solutions

Direction fields give you a visual picture of a differential equation's behavior without solving it. At each point (x,y)(x, y) in the plane, you evaluate dydx\frac{dy}{dx} and draw a short line segment with that slope. The collection of these segments shows you the general flow of solution curves, revealing trends, symmetry, and long-term behavior at a glance.

Initial conditions let you pick out one specific solution from the family of all solutions. The process:

  1. Solve the separable equation to get the general solution (with a constant CC).
  2. Plug in the initial condition (x0,y0)(x_0, y_0) and solve for CC.
  3. Substitute that value of CC back into the general solution to get the particular solution.

Combining both tools is powerful. Sketch the direction field first to understand the overall landscape of solutions. Then plot your initial condition and trace the solution curve through it, following the slopes the field indicates. This confirms your algebraic solution and helps you catch errors.

Autonomous Equations and Equilibrium Solutions

An autonomous equation is a separable equation where the right-hand side depends only on yy: dydx=f(y)\frac{dy}{dx} = f(y). Because xx doesn't appear explicitly, the slope at any point depends only on the yy-value. This means the direction field has identical slopes along every horizontal line.

Equilibrium solutions occur at values of yy where f(y)=0f(y) = 0. At these values, dydx=0\frac{dy}{dx} = 0, so the solution is just a constant horizontal line y=cy = c. These are the "resting states" of the system.

The phase line is a compact, one-dimensional tool for analyzing autonomous equations. You draw a vertical number line for yy, mark the equilibrium points (where f(y)=0f(y) = 0), and then add arrows between them: upward where f(y)>0f(y) > 0 (solutions increase) and downward where f(y)<0f(y) < 0 (solutions decrease). This quickly tells you whether solutions move toward or away from each equilibrium, which is the key to understanding long-term behavior.