---
title: "Energy Stored in an Inductor — AP Physics C: E&M Guide"
description: "Energy stored in an inductor is U = ½LI², held in the magnetic field of the current. Learn how it powers RL circuit and solenoid problems on AP Physics C: E&M."
canonical: "https://fiveable.me/ap-physics-c-e-m/key-terms/energy-stored-in-an-inductor"
type: "key-term"
subject: "AP Physics C: E&M"
unit: "Unit 13"
---

# Energy Stored in an Inductor — AP Physics C: E&M Guide

## Definition

The energy stored in an inductor is the energy held in the magnetic field created by current through it, given by U_L = ½LI². In AP Physics C: E&M, it explains where energy goes as current builds in an RL circuit and parallels the capacitor formula U_C = ½CV².

## What It Is

When [current](/ap-physics-c-e-m/unit-11/4-electric-power/study-guide/u2cRqQTlthIAJtwp "fv-autolink") flows through an [inductor](/ap-physics-c-e-m/key-terms/inductor "fv-autolink"), it creates a magnetic field, and that field stores energy. The amount is **U_L = ½LI²**, where L is the inductance and I is the current. The key physical idea is that the energy doesn't live in the wire or the charges. It lives in the magnetic field itself, mostly concentrated inside the coil (for a solenoid, almost entirely in the interior).

Where does that energy come from? Work. As current ramps up, the inductor's back-emf opposes the change, so the source has to push [charge](/ap-physics-c-e-m/unit-10/2-redistribution-of-charge-between-conductors/study-guide/3zelmsMupFfJh7VP "fv-autolink") against that emf. The power delivered to the inductor is P = LI(dI/dt), and if you integrate that from zero current up to I, you get exactly ½LI². That's the same logic used to derive ½CV² for a capacitor, just with current playing the role that charge played there. The formula also tells you something useful immediately. Energy depends on I squared, so tripling the current means nine times the stored energy.

## Why It Matters

This term lives in **Topic 13.4 (Inductance)** and **Topic 13.5 (Circuits with Resistors and Inductors)** in [Unit 13](/ap-physics-c-e-m/unit-13 "fv-autolink"), Electromagnetic Induction. It's the energy bookkeeping piece of inductance. When you analyze an [RL circuit](/ap-physics-c-e-m/key-terms/rl-circuit "fv-autolink"), Kirchhoff's loop rule tells you the math, but ½LI² tells you the story. Energy from the battery splits between resistor dissipation (I²R) and energy banked in the inductor's magnetic field. At steady state, dI/dt = 0, the inductor stops absorbing energy, and U_L locks in at ½LI². When the circuit is disconnected, that stored energy is what drives the decaying current and gets burned off in the resistor. It's also one half of the big symmetry the exam loves, magnetic field energy in inductors mirroring electric field energy in capacitors.

## Connections

### [RL Circuit (Unit 13)](/ap-physics-c-e-m/key-terms/rl-circuit)

An RL circuit is where stored inductor energy actually does something. While current grows toward its steady-state value, the battery's energy splits two ways, some dissipated in the [resistor](/ap-physics-c-e-m/key-terms/resistor "fv-autolink") and some stored as ½LI² in the inductor. During current decay, that stored energy flows back out and gets dissipated.

### Energy Stored in a Capacitor (Unit 10)

U_C = ½CV² and U_L = ½LI² are mirror images. A capacitor stores energy in an electric field and resists changes in [voltage](/ap-physics-c-e-m/key-terms/voltage "fv-autolink"); an inductor stores energy in a magnetic field and resists changes in current. If you know one derivation, you basically know both.

### dI/dt and Induced EMF (Unit 13)

Power delivered to an inductor is P = LI([dI/dt](/ap-physics-c-e-m/key-terms/di-dt "fv-autolink")), which is just the time derivative of ½LI². That means the inductor only gains or loses energy while the current is changing. Constant current means constant stored energy, even though current is still flowing.

### [Steady State (Unit 13)](/ap-physics-c-e-m/key-terms/steady-state)

At steady state an ideal inductor acts like a plain wire with no voltage across it, but it's not 'empty.' It's holding ½LI² in its magnetic field the whole time. That distinction, no voltage but plenty of stored energy, is a classic conceptual MCQ trap.

## On the AP Exam

Multiple-choice questions hit this from a few angles. Ratio reasoning is common, like a problem where 0.5 J is stored at 2 A and you're asked what current gives 4.5 J (energy scales with I², so the answer is 6 A). Conceptual stems ask where the energy is physically stored, and the answer is the magnetic field, not the wire or the charges. Calculation problems combine formulas, like finding the inductance of a solenoid from its turns and dimensions, then plugging the peak of a sinusoidal current into ½LI² for maximum stored energy. On free-response, energy storage typically shows up inside RL circuit analysis. You might derive I(t), compute the steady-state energy ½LI², or write an energy-conservation statement showing battery energy equals resistor dissipation plus stored field energy. Be ready to connect U_L to emf too, since ε = L(dI/dt) and ½LI² come as a package.

## energy stored in an inductor vs Energy stored in a capacitor

Both are ½ times something times something squared, so they blur together under exam pressure. A capacitor stores energy in an electric field and the formula uses voltage, U_C = ½CV². An inductor stores energy in a magnetic field and the formula uses current, U_L = ½LI². Quick memory check, capacitors care about voltage (they fight voltage changes), inductors care about current (they fight current changes). Each one's energy formula squares the thing it cares about.

## Key Takeaways

- The energy stored in an inductor is U_L = ½LI², and it's physically stored in the magnetic field created by the current, not in the wire itself.
- Because energy scales with the square of the current, doubling the current quadruples the stored energy, which makes ratio problems fast if you spot the pattern.
- The formula comes from integrating the power P = LI(dI/dt) delivered while current builds from zero, the same derivation style as ½CV² for a capacitor.
- In an RL circuit, battery energy splits between resistor dissipation and stored magnetic field energy, and at steady state the inductor holds a constant ½LI².
- An inductor only exchanges energy with the circuit while current is changing; with constant current it stores energy but absorbs no power.
- When current decays in an RL circuit, the inductor's stored energy is what keeps the current flowing, and it ends up dissipated in the resistor.

## FAQs

### What is the energy stored in an inductor?

It's the energy held in the magnetic field produced by current through the inductor, equal to U_L = ½LI². It builds up as current increases and is released when current decreases.

### Where is the energy in an inductor actually stored?

In the magnetic field, not in the wire or the moving charges. For a solenoid, the energy is concentrated almost entirely in the field inside the coil. This exact question shows up as a conceptual MCQ.

### Does an inductor lose its stored energy at steady state?

No. At steady state the inductor acts like a plain wire (zero voltage across an ideal inductor), but it still holds ½LI² in its magnetic field. It just stops absorbing new energy because dI/dt = 0.

### How is energy in an inductor different from energy in a capacitor?

An inductor stores energy in a magnetic field and the formula uses current, U_L = ½LI². A capacitor stores energy in an electric field and uses voltage, U_C = ½CV². Same ½(thing)(variable)² structure, different field and different variable.

### How do I find the current when the stored energy changes?

Use the fact that U is proportional to I². For example, if 0.5 J is stored at 2 A, then 4.5 J is 9 times the energy, so the current is 3 times bigger, which gives 6 A. No need to solve for L.

## Related Study Guides

- [13.4 Inductance](/ap-physics-c-e-m/unit-13/4-inductance/study-guide/v6xlvrEIaESQJi2U)

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